Chapter 2.6, Problem 11P

(A)

Interpretation Introduction

Interpretation:

The change in enthalpy.

Concept Introduction:

The expression to obtain the change in specific enthalpy $\left(\Delta \widehat{H}\right)$.

$\Delta \widehat{H}={\widehat{H}}_{out}-{\widehat{H}}_{in}$

Here, initial specific enthalpy is ${\widehat{H}}_{in}$, and final specific enthalpy is ${\widehat{H}}_{out}$.

(B)

Interpretation Introduction

Interpretation:

The change in internal energy.

Concept Introduction:

The expression of change in enthalpy $\left(d\underset{\_}{H}\right)$.

$d\underset{\_}{H}=C_P^{\ast }dT$        (2)

Here, derivative of molar enthalpy is $d\underset{\_}{H}$, constant pressure heat capacity for ideal gas is $C_P^{\ast }$, and change in temperature is $dT$.

The expression of change in specific enthalpy $\left(\Delta \widehat{H}\right)$.

$\Delta \widehat{H}=\frac{\Delta \underset{\_}{H}}{M{W}_{{\text{H}}_{\text{2}}\text{O}}}$        (5)

Here, molar enthalpy is $\Delta \underset{\_}{H}$, and molecular weight of water is $M{W}_{{\text{H}}_{\text{2}}\text{O}}$.

(C)

Interpretation Introduction

Interpretation:

The change in internal energy.

(D)

Interpretation Introduction

Interpretation:

The change in internal energy.

Concept Introduction:

The expression to obtain the change in specific enthalpy $\left(\Delta \widehat{H}\right)$.

$\Delta \widehat{H}=\frac{\Delta \underset{\_}{H}}{M{W}_{{\text{N}}_{\text{2}}}}$        (6)

Here, molecular weight of nitrogen is $M{W}_{{\text{N}}_{\text{2}}}$.

(E)

Interpretation Introduction

Interpretation:

The change in internal energy.