COLLEGE ALGEBRA
1st Edition
ISBN: 9781266065989
Author: Miller
Publisher: MCG
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Textbook Question
Chapter 3.6, Problem 34PE
For Exercises 21–54, solve the inequalities. (See Examples 1–2)
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In Exercises 73–74, use the graph of the rational function to solve
each inequality.
flx) = + 1
[-4, 4, 1] by [-4, 4, 1]
1
1
73.
4(x + 2)
4(x – 2)
74.
4(x + 2)
4(x - 2)
For Exercises 5–10,
a. Simplify the expression.
b. Substitute 0 for h in the simplified expression.
2(x + h)? + 3(x + h) ·
5.
(2x + 3x)
3(x + h - 4(x + h) – (3x - 4x)
6.
h
1
1
1
1
(x + h) – 2
7.
x - 2
2(x + h) + 5
8.
2x + 5
h
(x + h) – x
9.
(x + h)
10.
- X
h
h
Exercises 38–40 will help you prepare for the material covered in
the first section of the next chapter.
In Exercises 38-39, simplify each algebraic expression.
38. (-9x³ + 7x? - 5x + 3) + (13x + 2r? – &x – 6)
39. (7x3 – 8x? + 9x – 6) – (2x – 6x? – 3x + 9)
40. The figures show the graphs of two functions.
y
y
201
10-
....
-20-
flx) = x³
glx) = -0.3x + 4x + 2
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- In Exercises 17–27, use the vertex and intercepts to sketchthe graph of each quadratic function. Give the equation of the parabola’s axis of symmetry. Use the graph to determine the function’s domain and range. 23. f(x)=2(x+2)2 -1 25. f(x)=4-(x-1)2 27. f(x)=x2 -2x-3arrow_forwardIn Exercises 39–44, an equation of a quadratic function is given. a. Determine, without graphing, whether the function has a minimum value or a maximum value. b. Find the minimum or maximum value and determine where it occurs. c. Identify the function's domain and its range. 39. f(x) = 3x – 12x – 1 41. f(x) = -4x² + &r – 3 43. f(x) = 5x? - 5x 40. f(x) = 2x? – &r – 3 42. f(x) = -2r² – 12x + 3 44. f(x) = 6x - 6x %3D %3D %3Darrow_forwardIn Exercises 20–21, solve each rational equation. 11 20. x + 4 + 2 x2 – 16 - x + 1 21. x? + 2x – 3 1 1 x + 3 x - 1 ||arrow_forward
- For Exercises 37–44, find the difference quotient and simplify. (See Examples 4-5) 37. f(х) — — 2х + 5 38. f(x) = -3x + 8 39. f(x) = -5x² – 4x + 2 40. f(x) = -4x - 2x + 6 41. f(x) = x' + 5 42. f(x) = 1 43. f(x) = 1 44. f(x) = x + 2arrow_forwardIn Exercises 31–32, each function is defined by two equations. The equation in the first row gives the output for negative numbers in the domain. The equation in the second row gives the output for nonnegative numbers in the domain. Find the indicated function values. S3x + 5 ifx 0 31. f(x) = а. f(-2) b. f(0) с. f(3) d. f(-100) + f(100)arrow_forwardThe Mauna Loa Observatory in Hawaii records the carbon dioxide concentration y (in parts per million) in Earth’s atmosphere. The January readings for various years are shown in Figure . In the July 1990 issue of Scientific American, these data were used to predict the carbon dioxide level in Earth’s atmosphere in the year 2035, using the quadratic model y = 0.018t2 + 0.70t + 316.2 (Quadratic model for 1960–1990 data) where t = 0 represents 1960, as shown in Figure a. The data shown in figure b represent the years 1980 through 2014 and can be modeled by y = 0.014t2 + 0.66t + 320.3 (Quadratic model for 1980–2014) data where t = 0 represents 1960. What was the prediction given in the Scientific American article in 1990? Given the second model for 1980 through 2014, does this prediction for the year 2035 seem accurate?arrow_forward
- For Exercises 39–42, multiply the radicals and simplify. Assume that all variable expressions represent positive real numbers. 39. (6V5 – 2V3)(2V3 + 5V3) 40. (7V2 – 2VIT)(7V2 + 2V1T) 41. (2c²Va – 5ď Vc) 42. (Vx + 2 + 4)²arrow_forwardIn Exercises 47–50, determine the x-intercepts of the graph of each quadratic function. Then match the function with its graph, labeled (a)-(d). Each graph is shown in a [-10, 10, 1] by [-10, 10, 1] viewing rectangle. 47. у 3D х2 -бх + 8 48. y = x? – 2r – 8 49. y = x² + 6x + 8 50. y = x² + 2x – 8 а. b. C. d.arrow_forwardwork out a slop y=5x + 3arrow_forward
- For Exercises 81–100, make an appropriate substitution and solve the equation. (See Examples 10–11) 81. (2x + 5)? – 7(2x + 5) - 30 = 0 82. (Зх — 7)? - 6(3х — 7)-16 3D 0 83. (x + 2x)? – 18(r + 2x) = -45 84. (x + 3x)? - 86. (у? — 3)? — 9(y? — 3) — 52 %3D 0 14(x + 3x) = -40 85. (x + 2)2 + (x + 2) – 42 = 0 10 2 10 - 61 m - - 27 = 0 x + + 35 = 0 87. 88. - 121 x + т - m m 89. 2 + 2 + = 12 90. + 3 + 6 + 3 = -8 91. 5c2/5 11c/5 + 2 = 0 92. З3 d'/3 – 4 = 0 93. y'/2 – y/4 6 = 0 94. n'/2 + 6n/4 – 16 = 0 95. 9y 10y + 1 = 0 96. 100х-4 29x-2 + 1 = 0 | 97. 4t – 25 Vi = 0 98. 9m – 16Vm = 0 100. 392 + 16q -1 99. 30k-2 – 23k- + 2 = 0 + 5 = 0arrow_forwardThe function, f(x) = –2x² + x + 5, is in standard form. The What are the zeros of the function quadratic equation is 0 = -2x + x + 5, where a = -2, b = 1, and c = 5. The discriminate b2 – 4ac is 41. Now, complete step 5 to solve for the zeros of the quadratic function. f(x) = x + 5 – 2x2? x = -1±/4T -4 5. Solve using the quadratic formula. O x= 1±/41 -4 -b±yb²- 4ac_ x = 2a x = -1±/39 - 4 X = 1±/39 - 4arrow_forwardExercises 15-20: Identify the vertex and leading coeffi- cient. Then write the expression as f(x) = ax² + bx + c. 15. f(x) = -3(x = 1)² + 2 16. f(x) = 5(x + 2)² – 5 17. f(x) = 5 – 2(x – 4)² 18. f(x) = (x + 3)² – 5 19. f(x) = (x + 5)² - } 20. f(x) = -5(x – 4)²arrow_forward
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