Chapter 4, Problem 2P

How many subshells are in the n = 3 shell? Identify each subshell, calculate the maximum number of electrons that will fit into each, and verify that the total is 2n2 .

Calculate the turning point of an alpha particle (Z =2) directed with initial kinetic energy of 2.0 MeV, if the trajectory of the alpha particle was headed directly toward a single gold nucleus (Z =79) (the nuclei in the gold foil in Rutherford’s experiment). How close could the alpha particle in Rutherford’s experiment get to the center of a gold nucleus?

Arrange the following H atom electron transitions in order of increasing frequency of the photon absorbed or emitted:(a) n=2 to n=4(b) n=2 to n=1(c) n=2 to n=5(d) n=4 to n=3

The binding energy of sodium is 2.28ev. Calculate the number of photon electron ejected by 1.00mm^2 area of sodium metal by 500nm by an electromagnet radiation having intensity of 1.30kw/m^2. What power is carried away by the electrons

A particle with spin quantum number (s) of 1/2 is in a magnetic field with a strength of 0.02 Tesla. Calculate the energy difference between the two possible spin states of the particle in joules. The gyromagnetic ratio for the particle is 1.76 x 10^11 rad/T·s.

An experiment with protons uses a magnetic field for which the energy difference between the aligned and anti-aligned spin states is 8.4×10−26J8.4×10−26J, the same as used for a medical MRI. At what temperature will the fractional population difference be ΔN/NΔ = 0.010, a 1%% difference? Temperatures this low are routinely achieved in low-temperature physics experiments.

The energy difference between the two levels arising from the spin-orbit coupling in a d-orbital is 0.6463 eV. Consider the splitting for one electron. Calculate the spin-orbit coupling constant in cm-1. please show all calculations.    What atom could that be? (Hint: calculate the spin-orbit coupling constant in Ry and look for a matching number in the last column that provides experimental values) constant : 1 eV = 1.60217646 × 10-19 J 1Ry = 2.1798741 × 10-18 J

Why is the density of nuclear excited states larger for higher excitation energies?

Calculate the mass-defects of oxygen-16 (oxygen has an atomic number of 8 and atomic weight of 15.9949 u) =0.13700?