The velocity function for the particle if s ( t ) = t 3 − 20 t 2 + 128 t − 280 .

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Answer 1

Question

Chapter 4.3, Problem 100E

(a)

To determine

To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

(b)

To determine

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

(c)

To determine

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

(d)

To determine

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

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The function s(t) describes the motion of a particle along a line. (a) Find the velocity function of the particle at any time t ≥ 0. (b) Identify the time interval(s) on which the particle is moving in a positive direction. (c) Identify the time interval(s) on which the particle is moving in a negative direction. (d) Identify the time(s) at which the particle changes direction

Answer 2

Question

Chapter 4.3, Problem 100E

(a)

To determine

To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

(b)

To determine

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

(c)

To determine

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

(d)

To determine

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

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Answer 3

Question

Chapter 4.3, Problem 100E

(a)

To determine

To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

(b)

To determine

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

(c)

To determine

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

(d)

To determine

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 4.3, Problem 100E

(a)

To determine

To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

(b)

To determine

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

(c)

To determine

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

(d)

To determine

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

Expert Solution & Answer

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See solution

Answer 5

Chapter 4.3, Problem 100E

(a)

To determine

To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

(b)

To determine

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

(c)

To determine

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

(d)

To determine

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

Answer 6

Chapter 4.3, Problem 100E

(a)

To determine

To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

Answer 7

Chapter 4.3, Problem 100E

(a)

To determine

To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

Answer 8

(b)

To determine

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

Answer 9

(b)

To determine

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

Answer 10

(c)

To determine

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

Answer 11

(c)

To determine

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

Answer 12

(d)

To determine

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

Answer 13

(d)

To determine

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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The velocity function for the particle if s ( t ) = t 3 − 20 t 2 + 128 t − 280 .

Solution Summary: The author explains that the speed function can be computed by differentiating the function for distance with respect to time.

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To calculate: The velocity function for the particle if s(t)=t3−20t2+128t−280.

To calculate: The interval where the particle is moving in the positive direction if s(t)=t3−20t2+128t−280.

To calculate: The interval where the particle is moving in the negative direction if s(t)=t3−20t2+128t−280.

To calculate: The time when the direction of the particle changes if s(t)=t3−20t2+128t−280.

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