   Chapter 5, Problem 5.10P Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939

Solutions

Chapter
Section Principles of Geotechnical Enginee...

9th Edition
Braja M. Das + 1 other
ISBN: 9781305970939
Textbook Problem

9% of a soil is retained on No. 4 sieve, and 11 % passes the No. 200 sieve. It is also known that 10%, 30%. and 60% of the soil is smaller than 0.1 mm. 0.8 mm. and 1.9 mm, respectively. When Atterberg limit tests are conducted, it is found that the liquid limit is 32% and the plastic limit is 27%. Classify this soil according to the Unified soil classification system and give group symbol and group name.

To determine

Classify the soil according to the Unified soil classification system and provide group symbol and group name.

Explanation

Given information:

The percent of soil retained on No. 4 sieve is 9 %.

The percent of soil passing through No. 200 (F200) is 11 %.

The liquid limit (LL) is 32 %.

The plastic limit (PL) is 27 %.

Calculation:

Determine the plasticity index (PI) using the formula.

PI=LLPL

Substitute 32 % for LL and 27 % for PL.

PI=3227=5

Determine the coarse fraction using the formula.

Coarsefraction=100PercentpassingonNo.200sieve

Substitute 11 % for percent retained on No.200 sieve.

Coarsefraction=10011=89%

Determine the gravel fraction using the formula.

Gravelfraction=100PercentpassingonNo.4sieve

Substitute 9 % for percent passing No.4 sieve.

Gravelfraction=1009=91

Determine the sand fraction using the relation.

Sandfraction=GravelfractionPercentpassingonNo.200seive

Substitute 91 % for gravel fraction and 11 % for percent passing on No. 200 sieve.

Sandfraction=9111=80%

Refer Table 5.2, “Unified soil classification system” in the text book

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