Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 5, Problem 8P
To determine
To determine: The law describing the total force acting on this object.
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If a single constant force acts on an object that moves on a straight line, the object’s velocity is a linear function of time. The equation v = vi + at gives its velocity v as a function of time, where a is its constant acceleration. What if velocity is instead a linear function of position? Assume that as a particular object moves through a resistive medium, its speed decreases as described by the equation v = vi − kx, where k is a constant coefficient and x is the position of the object. Find the law describing the total force acting on this object.
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Chapter 5 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 5.2 - Which of the following statements is correct? (a)...Ch. 5.4 - An object experiences no acceleration. Which of...Ch. 5.4 - You push an object, initially at rest, across a...Ch. 5.5 - Suppose you are talking by interplanetary...Ch. 5.6 - (i) If a fly collides with the windshield of a...Ch. 5.8 - You press your physics textbook flat against a...Ch. 5.8 - Prob. 5.7QQCh. 5 - A certain orthodontist uses a wire brace to align...Ch. 5 - One or more external forces, large enough to be...Ch. 5 - A 3.00-kg object undergoes an acceleration given...
Ch. 5 - The average speed of a nitrogen molecule in air is...Ch. 5 - Two forces, F1=(6.00i4.00j)N and...Ch. 5 - Prob. 6PCh. 5 - Review. Three forces acting on an object are given...Ch. 5 - Prob. 8PCh. 5 - Review. The gravitational force exerted on a...Ch. 5 - Review. The gravitational force exerted on a...Ch. 5 - Review. An electron of mass 9. 11 1031 kg has an...Ch. 5 - If a man weighs 900 N on the Earth, what would he...Ch. 5 - You stand on the seat of a chair and then hop off....Ch. 5 - A brick of mass M has been placed on a rubber...Ch. 5 - Review. Figure P5.15 shows a worker poling a boata...Ch. 5 - An iron bolt of mass 65.0 g hangs from a string...Ch. 5 - A block slides down a frictionless plane having an...Ch. 5 - A bag of cement whose weight is Fg hangs in...Ch. 5 - The distance between two telephone poles is 50.0...Ch. 5 - An object of mass m = 1.00 kg is observed to have...Ch. 5 - Prob. 21PCh. 5 - An object of mass m1 = 5.00 kg placed on a...Ch. 5 - In the system shown in Figure P5.23, a horizontal...Ch. 5 - A car is stuck in the mud. A tow truck pulls on...Ch. 5 - An object of mass m1 hangs from a string that...Ch. 5 - Why is the following situation impassible? Your...Ch. 5 - Consider a large truck carrying a heavy load, such...Ch. 5 - Before 1960m people believed that the maximum...Ch. 5 - A 9.00-kg hanging object is connected by a light,...Ch. 5 - The person in Figure P5.30 weighs 170 lb. As seen...Ch. 5 - Three objects are connected on a table as shown in...Ch. 5 - You are working as a letter sorter in a U.S Post...Ch. 5 - You have been called as an expert witness for a...Ch. 5 - A block of mass 3.00 kg is pushed up against a...Ch. 5 - Prob. 35PCh. 5 - A 5.00-kg block is placed on top of a 10.0-kg...Ch. 5 - A black aluminum glider floats on a film of air...Ch. 5 - Why is the following situation impossible? A book...Ch. 5 - Two blocks of masses m1 and m2, are placed on a...Ch. 5 - A 1.00-kg glider on a horizontal air track is...Ch. 5 - An inventive child named Nick wants to reach an...Ch. 5 - Prob. 42APCh. 5 - Prob. 43APCh. 5 - Prob. 44APCh. 5 - A crate of weight Fg is pushed by a force P on a...Ch. 5 - In Figure P5.46, the pulleys and pulleys the cord...Ch. 5 - You are working as an expert witness for the...Ch. 5 - A flat cushion of mass m is released from rest at...Ch. 5 - What horizontal force must be applied to a large...Ch. 5 - Prob. 50APCh. 5 - A block of mass 2.20 kg is accelerated across a...Ch. 5 - Prob. 52CPCh. 5 - Initially, the system of objects shown in Figure...Ch. 5 - Prob. 54CPCh. 5 - In Figure P5.55, the incline has mass M and is...
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Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY