C++ for Engineers and Scientists
C++ for Engineers and Scientists
4th Edition
ISBN: 9781133187844
Author: Bronson, Gary J.
Publisher: Course Technology Ptr
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Chapter 5.5, Problem 2E

(cin within a loop) Write and run a C++ program that accepts 10 values of gallons, one at a time, and converts each value entered to its liter equivalent before the next value is requested. Use a for loop in your program. Use the fact that 1   g a l l o n   =   3.785   l i t e r s .

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-Program C 2. Not my Favorites by CodeChum Admin We've already done looping through a series of numbers and printing out its squares, so how about we level it up and go with cubes this time?   I have a condition though; I don't want to be associated with numbers that are divisible by 3 or 5 so if an integer is divisible by either of the two, don't make their cube values appear on the screen, please.   Care to fulfill my request?   Instructions: Print out the cube values of the numbers ranging from 1 to 1000 (inclusive). However, if the number is divisible by either 3 or 5, do not include them in printing and proceed with the next numbers. Tip: When skipping through special values, make use of the keyword continue and put them inside a conditional statement. Output Multiple lines containing an integer. 1 8 64 343 512 . . .

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C++ for Engineers and Scientists

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