The uniform plate has a weight of 500 lb. Determine the tension in each of the supporting cables.
Prob. F5-7
Answer to Problem 7FP
The tension
Explanation of Solution
Given information:
- The weight (W) of the plate is 500 lb.
- The load (P) acting on the plate is 200 lb.
Explanation:
Show the free body diagram of the uniform plate as in Figure (1).
Use Figure (1).
Apply the equation of equilibrium along the z axis.
Take the moment about the x axis.
Here, the horizontal distance between cables B and A is
Take the moment about the y axis.
Here, the vertical distance between cable A and B is
Calculations:
Substitute 200 lb for P and 500 lb for W in Equation (I).
Substitute 3.0 ft for
Substitute 4.0 ft for
Simply Equation (I), multiplying by 3 and it can be written as follows.
Conclusion:
Solve Equation (VIII) and (V).
Thus, the tension in cable B is
Substitute 250 lb for
Thus, the tension in cable C is
Substitute 250 lb for
Thus, the tension in cable A is
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