Concepts of Genetics (11th Edition)
Concepts of Genetics (11th Edition)
11th Edition
ISBN: 9780321948915
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 9, Problem 1NST

Chlamydomonas, a eukaryoric green alga, may be sensitive to the antibiotic erythromycin, which inhibits protein synthesis in bacteria. There are two mating types in this alga, mt+ and mt. If an mt+ cell sensitive to the antibiotic is crossed with an mt cell that is resistant, all progeny cells are sensitive. The reciprocal cross (mt+ resistant and mt sensitive) yields all resistant progeny cells. Assuming that the mutation for resistance is in the chloroplast DNA, what can you conclude from the results of these crosses?

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Summary Introduction

To determine: The conclusion that can be drawn from the results of the given crosses.

Introduction: Chlamydomonas is a eukaryotic green alga and shows two mating types mt+ and mt-. The cross between mt+ cell (sensitive to antibiotic) and mt- cell (resistant to antibiotic) produces sensitive progeny cells.

Explanation of Solution

The following conclusions can be drawn from the results of the given crosses:

  • The mt+ strain of Chlamydomonas is the donor of the chloroplast DNA. This is because the inheritance of resistance or sensitivity to the antibiotic relies on the status of mt+ gene.
  • In Chlamydomonas, the chloroplasts obtain their features from mt+, whereas mitochondria obtain their features from the mt- strain.
Conclusion

Thus, mt+ strain is the donor of chloroplast DNA and the chloroplasts gain their characteristics from mt+. The mitochondria obtain their features from mt-.

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Concepts of Genetics (11th Edition)

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