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Problem Set #1
Monday January 29
th
2024
1.
The following pedigree shows the inheritance of attached earlobes (black symbols) and unattached earlobes (open symbols). Both alternate phenotypes are quite common in human populations.
If the phenotypes are determined by alleles of one gene, then attached earlobes are inherited as 2.
A phenotypically normal woman is a carrier of the recessive allele that causes phenylketonuria (PKU). What proportion of her eggs will carry the allele that allows normal processing of phenylalanine?
3.
A couple in Indiana are each heterozygous for the autosomal recessive allele for albinism. They have two children. What is the probability that both children will be phenotypically identical with regard to skin color?
4.
If you had a fruit fly (
Drosophila melanogaster
) that was of phenotype A, what test would you make to determine if the fly’s genotype was A/A
or A/a
?
5.
Two black guinea pigs were mated and over several years produced 29 black and 9 white offspring. Explain these results, giving the genotypes of the parents and the progeny.
6.
In a fungus with four ascospores, a mutant allele lys-5
causes the ascospores bearing that allele to be white, whereas the wild-type allele lys-5
+
results in black ascospores. (Ascospores are the spores that constitute the four products
of meiosis.) Draw and ascus from each of the following crosses:
a.
lys-5 x lys-5
+
b.
lys-5 x lys-5
c.
lys-5
+
x lys-5
+
7.
From a large-scale screen of many plants of collinsia grandiflora, a plant with three cotyledons was discovered (normally there are two cotyledons). This plant was crossed with a normal pure-breeding wild-type plant, and 600 seeds
from this cross were planted. There were 298 plants with two cotyledons and 302 with three cotyledons. What can be deduced about the inheritance of three cotyledons? Invent gene symbols as part of your explanation.
BIL250
Problem Set #1
Dr. Alex Wilson
2
8.
In the pedigree below, the black symbols represent individuals with a very rare blood disease.
If you had no other information to go on, would you think it is more likely the disease is dominant or recessive? Give your reasons.
9.
The pedigree below was obtained for a rare kidney disease.
a.
Deduce the inheritance of this condition, stating your reasons.
b.
If persons 1 and 2 marry, what is the probability that their first child will have kidney disease?
BIL250
Problem Set #1
Dr. Alex Wilson
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Related Questions
1-Gigantism is being traced in a family through a pedigree. Its mode of inheritance is thought to be autosomal recessive.
You examine the pedigree and decide that the mode of inheritance is not correct. What is the correct mode of inheritance?
2-Provide 2 pieces of evidence for the mode of inheritance selected for Gigantism. (i.e.- Individual 45 is afflicted and passed it on to all of her offspring, indicating that it is dominant. Or there is a gendered pattern of inheritance seen when Individual 99 passed it on to only his female offspring.)
arrow_forward
tion 8:
below is the pedigree of inheritance of phenylketonuria (PKU). We will designate the letter
Caven
for the dominant allele and "p" for the recessive allele.
4
The pedigree shows that the pattern of inheritance for the allele for
phenylk
ylketonuria is:
I.
II.
1
III.
IV.
Autosomal dominant
Autosomal recessive
X-linked dominant
X-linked recessive
b. The parents in generation I have how many children:
I.
3 Boys
II.
3 Girls
III.
IV.
3 Boys and 1 Girl
3 Girls and 1 Boy
c. What is the genotype of individual 1 in generation III:
I. PP
II. pp
III. Pp
" O
1
III. 50%
E
III
1
▬
2
2
IV. 25%
1
3
IV. Can be PP or Pp
ii. Suppose that a man having type AB blood marries a woman having type O blood. What is the
probability that their child will have type A blood?
I. 100%
II. 75%
2
4
3
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What is the probability that III-j has Huntington's?
arrow_forward
PEDIGREES: Problem 7
This pedigree shows the inheritance of atype of X-linked color blindness. It is
a recessive trait. Carriers have NOT been half-shaded in this pedigree.
• QUESTIONS • • •
I ODO0
I. Work out who is definitely a carrier &
drag the correct shape onto them.
1
2
3
4
II
1
3
2. Is it possible to work out the
geno-
type of individual II-I? Explain
III
your reasoning.
1
2
3
IV
1
arrow_forward
40
Below is a pedigree of a family, some of whom have the autosomal dominant condition Huntington's disease.
Affected individuals are indicated by a dark square or circle. The male in generation I (indicated by the arrow) is
heterozygous for the Huntington's disease mutation.
The following two questions relate to this pedigree.
Generation
II
II
If H represents the disease allele, and h the wild type allele, what is the genotype of the individual indicated by the
*?
Select one alternative:
O hh
O Hh
O hH
O HH
arrow_forward
11
please answer all with complete explanation/solution
arrow_forward
age 105 of 114
3
5
€
BUD
>
D
Q
Autosomal Genes
1. Parental Cross: It is possible that your mutation is autosomal (dominant or recessive). In
this case, you only need one Punnett square to make predictions for the F1 generation that
will result from the parental cross, as it does not matter if the female or male in the parental
generation is the true breeding mutant.
a. Provide a Punnett square to predict the genotype of the F1 generation.
b.
Q Search
If the mutant allele is dominant, predict the phenotype of the F1 generation. Make
sure to also summarize the prediction as a ratio, comparing Wild-type : Mutant.
c.
If your mutant allele is recessive, predict the phenotype of the F1 generation. Make
sure to also summarize the prediction as a ratio, comparing Wild-type : Mutant.
2. F1 Self-Cross: Take the F1 results from question #1 to create a Punnett square predicting
the F2 generation genotypes.
104
a. What are the predicted F2 phenotypes if the mutant allele is dominant? Make sure
to…
arrow_forward
3
arrow_forward
13
arrow_forward
Please draw it out so I understand how it's suppose to be drawn
arrow_forward
10
arrow_forward
8-9. White eyes (w) is sex-linked and recessive in Drosophila. Cruved wings(cu) and black body (b) are
autosomal recessive alleles on the same chromosome, separated by 20 map units. If one breeds a
homozygous white, curved winged female fly to a homozygous black male fly to produce an F1, and
inbreeds the F1 males and females, at what frequency is a phenotypically wild-type male expected? (note:
male flies do not cross over)
A. 0.25
es
B.0.05
C.0.10
D. 0.20
E.0.125
arrow_forward
5
arrow_forward
70 T 꿈 ㅁ
ㅁ
이어어어어어어
In the pedigree shown, indicate whether each of the following inheritance patterns
is possible by selecting YES or NO from the appropriate drop down menu.
Y-linked
Autosomal Recessive
Autosomal Dominant
X-linked Recessive
X-linked Dominant
()
arrow_forward
Show your solution please.
4.
arrow_forward
Consider the following pedigree.
하
3
10
(5
3
2
(a) What pattern of transmission is most consistent with this pedigree?
(1) autosomal recessive, (2) autosomal dominant, (3) X-linked recessive, (4) X-linked
dominant.
(b) If individual V-2 marries a normal individual, and if the condition has a pene-trance of
85 percent, what is the probability that their second child will express the trait?
(c) On the third line, what does the diamond with a 10 in the middle mean?
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solve only a4 and a5
arrow_forward
AKS 7b/7e Mendelian Inheritance
In pea plants the allele for round seeds (R) is dominant to the allele for oval seeds
(r). In a cross between the two heterozygous plants what percentage of the
offspring will have round seeds? *
O 75%
O 50%
O 25%
O 100%
This is a required question
In pigeons, the allele for normal feathers (F) is dominant to the allele for frizzy
feathers (f). If a purebred, normal feathered bird (FF) is crossed with a frizzy
arrow_forward
BIU
A-
== 三E
12 -
Match each of the following examples to the appropriate type of non-Mendelian inheritance.
1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase
(which breaks down the amino acid phenylalanine) causes lighter skin color, a musty
odor, differences in intellectual development, and seizures.
2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W)
leading to purple flower.color, and the recessive allele (w) leading to white flower color.
Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is
homozygous recessive, WW or Ww plants always have white flowers.
3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to
green head feathers, while a recessive allele (f) leads to brown head feathers. In male
mallards, inheritance of one or more F alleles always leads to the green head feather
trait. But female mallards always have brown head feathers,…
arrow_forward
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Related Questions
- 1-Gigantism is being traced in a family through a pedigree. Its mode of inheritance is thought to be autosomal recessive. You examine the pedigree and decide that the mode of inheritance is not correct. What is the correct mode of inheritance? 2-Provide 2 pieces of evidence for the mode of inheritance selected for Gigantism. (i.e.- Individual 45 is afflicted and passed it on to all of her offspring, indicating that it is dominant. Or there is a gendered pattern of inheritance seen when Individual 99 passed it on to only his female offspring.)arrow_forwardtion 8: below is the pedigree of inheritance of phenylketonuria (PKU). We will designate the letter Caven for the dominant allele and "p" for the recessive allele. 4 The pedigree shows that the pattern of inheritance for the allele for phenylk ylketonuria is: I. II. 1 III. IV. Autosomal dominant Autosomal recessive X-linked dominant X-linked recessive b. The parents in generation I have how many children: I. 3 Boys II. 3 Girls III. IV. 3 Boys and 1 Girl 3 Girls and 1 Boy c. What is the genotype of individual 1 in generation III: I. PP II. pp III. Pp " O 1 III. 50% E III 1 ▬ 2 2 IV. 25% 1 3 IV. Can be PP or Pp ii. Suppose that a man having type AB blood marries a woman having type O blood. What is the probability that their child will have type A blood? I. 100% II. 75% 2 4 3arrow_forwardWhat is the probability that III-j has Huntington's?arrow_forward
- PEDIGREES: Problem 7 This pedigree shows the inheritance of atype of X-linked color blindness. It is a recessive trait. Carriers have NOT been half-shaded in this pedigree. • QUESTIONS • • • I ODO0 I. Work out who is definitely a carrier & drag the correct shape onto them. 1 2 3 4 II 1 3 2. Is it possible to work out the geno- type of individual II-I? Explain III your reasoning. 1 2 3 IV 1arrow_forward40 Below is a pedigree of a family, some of whom have the autosomal dominant condition Huntington's disease. Affected individuals are indicated by a dark square or circle. The male in generation I (indicated by the arrow) is heterozygous for the Huntington's disease mutation. The following two questions relate to this pedigree. Generation II II If H represents the disease allele, and h the wild type allele, what is the genotype of the individual indicated by the *? Select one alternative: O hh O Hh O hH O HHarrow_forward11 please answer all with complete explanation/solutionarrow_forward
- age 105 of 114 3 5 € BUD > D Q Autosomal Genes 1. Parental Cross: It is possible that your mutation is autosomal (dominant or recessive). In this case, you only need one Punnett square to make predictions for the F1 generation that will result from the parental cross, as it does not matter if the female or male in the parental generation is the true breeding mutant. a. Provide a Punnett square to predict the genotype of the F1 generation. b. Q Search If the mutant allele is dominant, predict the phenotype of the F1 generation. Make sure to also summarize the prediction as a ratio, comparing Wild-type : Mutant. c. If your mutant allele is recessive, predict the phenotype of the F1 generation. Make sure to also summarize the prediction as a ratio, comparing Wild-type : Mutant. 2. F1 Self-Cross: Take the F1 results from question #1 to create a Punnett square predicting the F2 generation genotypes. 104 a. What are the predicted F2 phenotypes if the mutant allele is dominant? Make sure to…arrow_forward3arrow_forward13arrow_forward
- Please draw it out so I understand how it's suppose to be drawnarrow_forward10arrow_forward8-9. White eyes (w) is sex-linked and recessive in Drosophila. Cruved wings(cu) and black body (b) are autosomal recessive alleles on the same chromosome, separated by 20 map units. If one breeds a homozygous white, curved winged female fly to a homozygous black male fly to produce an F1, and inbreeds the F1 males and females, at what frequency is a phenotypically wild-type male expected? (note: male flies do not cross over) A. 0.25 es B.0.05 C.0.10 D. 0.20 E.0.125arrow_forward
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