BIOL 411 - 2023 Autumn - Exam 1 - Answer Key
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BIOL 411 - 2023 Autumn
Exam 1
Point total: 100 points
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Page 1
BIOL 411 - 2023 Autumn
Exam 1
1.
Based on the cell lineage shown at right, mark
each of the following statements as True or False
and provide a one sentence explanation of your
reasoning. [4pts each/12pts total]
1a.
_
False [2pts]
_ The MS cell is specified to
become pharyngeal or body wall muscle.
●
Reasoning:
To test this we would need to
isolate the MS cell and place it in a neutral
environment (e.g., culture dish) and assay
muscle formation, but the lineage was
only made based on observations of intact
embryos. [2pts]
1b.
_
False [2pts]
_ The MS cell is determined to
become pharyngeal or body wall muscle.
●
Reasoning:
To test this we would need to
isolate the MS cell and place it in a
non-neutral environment (e.g., culture
dish with other components or different
region of the embryo) and assay muscle
formation, but the lineage was only made
based on observations of intact embryos.
[2pts]
1c.
_
False [2pts]
_ The MS cell is a differentiated
pharyngeal or body wall muscle cell.
●
Reasoning:
False because the lineage
indicates MS is a precursor cell that will
undergo multiple rounds of cell division
before producing differentiated muscle
cells (at the tips of the branches). [2pts]
Figure legend:
An abbreviated embryonic cell lineage of
C. elegans
that was generated based solely on
observations of intact, wild-type embryos. Note that the
vertical axis in the diagram represents embryonic time and
the branch points represent cell divisions. Individual
blastomere names are shown above select branches.
2.
You are analyzing embryos produced by adult female flies that are either heterozygous (
nanos/+
) or
homozygous (
nanos/nanos
) for a recessive loss-of-function allele of
nanos
. For each of these cases, in what
proportion of embryos do you expect to see the
nanos
mutant phenotype (i.e., lack of abdomen)? [4pts
each/8pts total]
nanos/+
nanos/nanos
A. 100%
B. 50%
C. 25%
D. 0% [4pts]
E. Cannot determine without paternal genotype
A. 100% [4pts]
B. 50%
C. 25%
D. 0%
E. Cannot determine without paternal genotype
Page 2
BIOL 411 - 2023 Autumn
Exam 1
3.
As part of Unit 1, you had the opportunity to analyze the landmark paper “
macho-1
encodes a localized
mRNA in ascidian eggs that specifies muscle fate during embryogenesis” by Hiroki Nishida and Kaichiro
Sawada (
Nature
2001 409:724-729).
3a.
This paper makes use of ascidian embryos (
Halocynthia roretzi
) as a model system. You are discussing
the paper with a peer who has taken BIOL 355, but not BIOL 411, and is unfamiliar with
H. roretzi
as a
model. You are asked to define three advantages and one disadvantage of
H. roretzi
as a model for
analyzing muscle development compared to mammalian embryos. What do you say? (One complete
sentence per bullet point) [2pts each/8pts total]
Advantages
[6pts]
●
Multiple possible answers, e.g.:
○
Defined, invariant cell lineage
○
Externally developing embryos
○
Easy to inject mRNA/oligos
○
Simple body plan with
well-described anatomy
○
Cheap, easy to culture in lab, etc.
○
It is a chordate making it closely
related to vertebrates
Disadvantage
[2pts]
●
Multiple possible answers, e.g.:
○
Genome may not contain factors
relevant for mammalian muscle
development
○
Mammalian embryos do not have
yellow protoplasm, so mechanisms
likely different
○
Great for studying autonomous
development, but not the
conditional development
commonly used in mammalian
systems
Figure 3 legend: n–r,
Embryos at the 110-cell stage fixed and in
in situ
hybridized with the muscle actin
(
HrMA4
) probe.
n,
Uninjected control. Actin expression is observed in ten precursor blastomeres of primary muscle
cells.
o,
macho-1
-depleted embryos.
p, q,
Synthesized
macho-1
mRNA was subsequently injected. Actin is ectopically
expressed in endoderm (
p
) and epidermis (
q
) blastomeres.
r,
Subsequent injection of mutant mRNA has no effect.
Figure 1 legend: b,
Structure of macho-1 protein and constructs for
in
vitro
mRNA synthesis. Macho-1 has five zinc fingers in the central part.
The cDNA clone is 2,210 bp long and encodes a 556-amino-acid ORF.
The wild-type construct encodes the full length, but the mutant construct
lacks the zinc-finger domain.
3b.
What do you conclude based on the results presented in Figure
3o
? (Limit: 1 sentence)
[4pts]
macho-1
is necessary for muscle actin (
HrMA4
) expression at the 110-cell stage.
Page 3
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BIOL 411 - 2023 Autumn
Exam 1
[1pt] Accurate description of the results.
3c.
What do you conclude based on the combined results presented in Figure
3p,q
? (Limit: 1 sentence)
[4pts]
macho-1
is sufficient to promote muscle actin (
HrMA4
) expression in endodermal and epidermal
blastomeres at the 110-cell stage.
[1pt] Accurate description of the results.
3d.
Explain to your peer the question the authors were addressing with their mutant mRNA injection. (Limit: 1
sentence)
[4pts
]
Is injection of
macho-1
mRNA lacking the zinc finger domain sufficient to rescue muscle actin
(
HrMA4
) expression in
macho-1
-depleted embryos at the 110-cell stage?
Alternative answer: the authors were testing if the zinc finger domain is necessary for macho-1
function.
[1pt] Accurate description of the results. Argues that it is a rescue experiment or functioning as an
injection control.
[0pts] The zinc finger domain is not mentioned. Testing if macho-1 mRNA is necessary and sufficient
for muscle development was queried in figure 3o,p, and q.
3e.
Imagine that injection of the
macho-1
mutant mRNA into
macho-1
-depleted embryos resulted in embryos
that looked like the one presented in Figure
3n
. What would you infer about the potential molecular function
of Macho-1 protein based on this potential result? (Limit: 1 sentence)
[4pts]
Macho-1 can promote muscle actin (
HrMA4
) expression independently of its zinc finger domain.
Other possible interpretations: e.g., it doesn’t need to bind to DNA, function as a TF function, etc. to
promote muscle actin expression.
[2pts] The zinc finger domain is not mentioned but the answer is otherwise correct.
4.
During this Unit, you “jigsawed” the seminal paper “The
Drosophila
Homolog of
C. elegans
PAR-1 Organizes
the Oocyte Cytoskeleton and Directs
oskar
mRNA Localization to the Posterior Pole” by Joshua M. Shulman,
Richard Benton, and Daniel St Johnston (
Cell
2000 101:377–388).
4a.
Based on your understanding of the background to this paper, what led the authors to investigate PAR-1 as
a candidate regulator of A/P axis determination in
Drosophila
? Limit: 1 sentence.
[3pts]
Previous work in the early
C. elegans
embryo had identified PAR-1 as an essential regulator of A/P axis
determination and the authors wanted to test if this function of PAR-1 was conserved in
Drosophila
.
Page 4
BIOL 411 - 2023 Autumn
Exam 1
Figure 6 legend:
(
A–D
) Microtubule organization visualized in live oocytes by expression of Tau:GFP; all images were
taken at a similar, central focal plane.
(E and F)
Kin:β-gal. (
G and H
) Nod:β-gal. (
A, E, and G
)
par-1
/+ sibling controls,
in which microtubule organization and polarity are indistinguishable from wild-type.
(B)
par-1
6821
is shown, and a similar
phenotype is consistently observed in all allelic combinations. (
F and H
)
par-1
6323
/par-1
W3
. (
C
)
capu
RK
. (
D
)
grk
2E12
.
Put your developmental biology mantra to
use! For each of the panels listed at right
from Figure 6, fill in the blank with the
response that best fits the experiment.
Possible responses: (Find it / Move it /
Lose it). For full credit, explain your
reasoning. Limit: 1 sentence per response.
[5pts each/15pts total]
4b.
Figure 6A _
Find it [2.5pts]
_
●
Reasoning:
This panel serves to illustrate the
wild-type patterning of the microtubule
cytoskeleton (via Tau:GFP expression). [2.5pts]
4c.
Figure 6B _
Lose it [2.5pts]
_
●
Reasoning:
This panel serves to illustrate the
patterning of the microtubule cytoskeleton (via
Tau:GFP expression) in an oocyte homozygous for
a loss-of-function allele of
par-1
(
par-1
6821
). [2.5pts]
4d.
Figure 6E _
Find it [2.5pts]
_
●
Reasoning:
This panel serves to illustrate the
wild-type polarity of the microtubule cytoskeleton
(via Kin:β-gal, which labels the (+) ends of
microtubules). [2.5pts]
Page 5
BIOL 411 - 2023 Autumn
Exam 1
5.
While studying at the health sciences library, you come across a back issue of the journal
Development
that
contains an article analyzing the functions of the
Drosophila
gene
staufen (stau)
. Specifically, the authors
perform a structure-function analysis to assess roles for the different domains of the Stau protein.
Background: Full-length Stau (Stau
full
) contains five (ds)RNA-binding domains (dsRBDs) and a short region
within an insertion that splits dsRBD2 into two halves.
Methods: The authors assay rescue of a homozygous loss-of-function mutation in
stau
(
stau
D3
/stau
D3
) with
various transgenic constructs encoding the Stau protein forms shown below. You can assume that the Stau
full
transgene (T[Stau
full
]) completely rescues the
stau
mutant phenotype and that the anti-Stau antibody used by
the authors recognizes all of the Stau transgenes.
Figure 1 legend: D,
A diagram showing the structure of the Stau
proteins encoded by the Stau
full
, Stau
ΔN
, Stau
Δloop2
and Stau
ΔdsRBD5
transgenes. The green boxes indicate the positions of the
dsRBDs. The arrows and adjacent blue boxes indicate the
N-termini of the amino acid sequences.
Figure 2 legend: A–B,
Localization of Stau protein and
oskar
(
osk
) mRNA as indicated by the dark staining in stage 9
(i and iii) and 10 (ii and iv) oocytes from
stau
D3
T[Stau
full
]/
stau
D3
females (
A
) or
stau
D3
T[Stau
ΔN
]/
stau
D3
females (
B
).
5a.
Based on the data presented in Figure 2, what do you observe about the localization of the Stau
ΔN
protein within the oocyte? Note that you can ignore any differences in the intensity of the staining between
panels A and B. (Limit: 1 sentence)
[5pts]
Similar to Stau
full
, Stau
ΔN
localizes to the posterior of the oocyte at stages 9 and 10.
5b.
Based on the data presented in Figure 2, what do you conclude about the relationship between the
structure of the Stau protein and
osk
localization within the oocyte? Note that you can ignore any differences
in the intensity of the staining between panels A and B.(Limit: 1 sentence)
The N-terminus of Stau is not necessary for localization of
osk
mRNA to the posterior of the oocyte
at stages 9 and 10 [5pts]
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BIOL 411 - 2023 Autumn
Exam 1
Question 5 continued…
Figure 3 legend:
Localization of Stau protein (
A,B
),
oskar
(
osk
) mRNA (
C,D
), and Oskar (Osk) protein (
E,F
) in stage 9
(
A,C,E
) and 10 (
B,D,F
) oocytes from
stau
D3
T[Stau
ΔdsRBD5l
]/
stau
D3
females.
5c.
Based on the data presented in Figure 3, what do you conclude about the relationship between the
structure of the Stau protein and Osk protein localization within the oocyte? (Limit: 1 sentence)
[5pts]
The dsRBD5 domain of Stau is necessary for Osk localization to the oocyte posterior at stage 10, but
not at stage 9.
+4 for stating the dsRBD5 domain is necessary for Osk localization to the posterior.
+1 for identifying that the dsRBD5 domain is necessary for Osk localization to the oocyte posterior at
stage 10, but not at stage 9.
Page 7
BIOL 411 - 2023 Autumn
Exam 1
Question 5 continued…
Figure 4 legend:
bicoid
(
bcd
) mRNA localization in
freshly laid eggs from wildtype (top panel),
stau
D3
T[Stau
Δloop2
]/
stau
D3
(middle panel) and
stau
D3
T[Stau
ΔdsRBD5
]/
stau
D3
(bottom panel) females.
Note: please use the same coordinate system for questions 5d and 5e below. i.e., your graphs should be
comparable to each other.
5d.
Based on the data presented in Figure 4 and
using the axes below, draw the expected Bcd protein
gradient and corresponding threshold and position of
the head fold (HF) along the A/P axis in
stau
D3
T[Stau
Δloop2
]/
stau
D3
embryos. For your convenience,
the Wildtype gradient and head fold threshold and
position are shown in blue. [5pts]
5e.
Based on the data presented in Figure 4 and
using the axes below, draw the expected Bcd protein
gradient and corresponding threshold and position of
the head fold along the A/P axis in
stau
D3
T[Stau
ΔdsRBD5
]/
stau
D3
embryos.For your convenience,
the Wildtype gradient and head fold threshold and
position are shown in blue. [5pts]
5d:
+2 for drawing the Bcd concentrations for the
stau
D3
T[Stau
Δloop2
]/
stau
D3
embryos above WT across the
Page 8
BIOL 411 - 2023 Autumn
Exam 1
A-P axis
+2 for indicating HF position more posterior to WT
+1 for having threshold Bcd concentrations at same level as WT
5e:
+2 for drawing the Bcd concentrations for the T[Stau
ΔdsRBD5
]/
stau
D3
embryos above WT across the A-P
axis
+1 for indicating HF position more posterior to WT
+1 for having threshold Bcd concentrations at same level as WT
+1 for having HF position more posterior compared to
stau
D3
T[Stau
Δloop2
]/
stau
D3
embryos
6.
Developmental biologists often order processes into step-wise pathways. A great example of this is the
development of
Drosophila
oocyte polarity. Place the following items in order (1,2,3…) and put an “X” next to
any false statement. Note that by convention, a name in lower-case italics refers to an mRNA (e.g.,
nanos
) and
a non-italicized name with an upper-case first letter refers to a protein (e.g., Nanos).
[10pts - partial credit
possible]
_
X
_ Sperm entry cues initial asymmetry
_
4
_ Par-1 organizes microtubules with their plus and minus ends at the posterior and anterior ends of the
oocyte, respectively
_
2
_ Gurken binds to Torpedo expressed by follicle cells
_
X
_
nanos
is trafficked to the posterior pole along microtubules
_
X
_ Bicoid is trafficked to the anterior pole along microtubules
_
5
_
oskar
is trafficked to the posterior pole
_
3
_ Follicle cells produce protein kinase A
_
6
_ Oskar binds to
nanos
at the posterior pole
_
X
_ Par-1 localizes to the anterior pole of the oocyte
_
1
_
gurken
is synthesized by the nurse cells
+4 for correctly identifying false statements (+1 for each correct identification)
+6 for correctly identifying order (+1 is given for each correct step in the process, starting from step 1-
“gurken is synthesized by the nurse cells”. So getting steps 1-2 right will fetch +2 points, getting steps
1-3 right will fetch +3 points, and so on).
7.
Which of the following statement(s) are true about the transition from syncytial to cellular blastoderm in
Drosophila
?
[3pts]
A. Nuclei migrate to the periphery of the blastoderm where they enter cell membrane pockets
B. Transcription of zygotic genes occurs before cellularization, allowing diffusion of gene products within the
blastoderm
C. Nuclear divisions are synchronized and occur in waves across the blastoderm
D. A and B
E. A and C
F. B and C
G. All of the above
H. None of the above
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