BIOL 411 - 2023 Autumn - Exam 1 - Answer Key

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BIOL 411 - 2023 Autumn Exam 1 Point total: 100 points Instructions (please read carefully): Begin by downloading this document (File > Download > Microsoft Word (.docx)) Using your own words, write precisely and concisely. Do not exceed the sentence limits. Reminder: you may refer to your one page of notes but no other sources during the exam period. Unless specified otherwise, providing multiple answers to a question will result in a loss of points. Please make sure to upload your document via Canvas at the end of the exam period. Sharing your answers with a peer is strictly prohibited. Failure to comply with these guidelines may result in our being unable to accept or grade your exam or initiating disciplinary actions. Please format your written answers (bold, colored blue) to make exam grading easier. Integrity statement: I have neither given nor received aid on this exam. _________________________ Your Signature Page 1
BIOL 411 - 2023 Autumn Exam 1 1. Based on the cell lineage shown at right, mark each of the following statements as True or False and provide a one sentence explanation of your reasoning. [4pts each/12pts total] 1a. _ False [2pts] _ The MS cell is specified to become pharyngeal or body wall muscle. Reasoning: To test this we would need to isolate the MS cell and place it in a neutral environment (e.g., culture dish) and assay muscle formation, but the lineage was only made based on observations of intact embryos. [2pts] 1b. _ False [2pts] _ The MS cell is determined to become pharyngeal or body wall muscle. Reasoning: To test this we would need to isolate the MS cell and place it in a non-neutral environment (e.g., culture dish with other components or different region of the embryo) and assay muscle formation, but the lineage was only made based on observations of intact embryos. [2pts] 1c. _ False [2pts] _ The MS cell is a differentiated pharyngeal or body wall muscle cell. Reasoning: False because the lineage indicates MS is a precursor cell that will undergo multiple rounds of cell division before producing differentiated muscle cells (at the tips of the branches). [2pts] Figure legend: An abbreviated embryonic cell lineage of C. elegans that was generated based solely on observations of intact, wild-type embryos. Note that the vertical axis in the diagram represents embryonic time and the branch points represent cell divisions. Individual blastomere names are shown above select branches. 2. You are analyzing embryos produced by adult female flies that are either heterozygous ( nanos/+ ) or homozygous ( nanos/nanos ) for a recessive loss-of-function allele of nanos . For each of these cases, in what proportion of embryos do you expect to see the nanos mutant phenotype (i.e., lack of abdomen)? [4pts each/8pts total] nanos/+ nanos/nanos A. 100% B. 50% C. 25% D. 0% [4pts] E. Cannot determine without paternal genotype A. 100% [4pts] B. 50% C. 25% D. 0% E. Cannot determine without paternal genotype Page 2
BIOL 411 - 2023 Autumn Exam 1 3. As part of Unit 1, you had the opportunity to analyze the landmark paper “ macho-1 encodes a localized mRNA in ascidian eggs that specifies muscle fate during embryogenesis” by Hiroki Nishida and Kaichiro Sawada ( Nature 2001 409:724-729). 3a. This paper makes use of ascidian embryos ( Halocynthia roretzi ) as a model system. You are discussing the paper with a peer who has taken BIOL 355, but not BIOL 411, and is unfamiliar with H. roretzi as a model. You are asked to define three advantages and one disadvantage of H. roretzi as a model for analyzing muscle development compared to mammalian embryos. What do you say? (One complete sentence per bullet point) [2pts each/8pts total] Advantages [6pts] Multiple possible answers, e.g.: Defined, invariant cell lineage Externally developing embryos Easy to inject mRNA/oligos Simple body plan with well-described anatomy Cheap, easy to culture in lab, etc. It is a chordate making it closely related to vertebrates Disadvantage [2pts] Multiple possible answers, e.g.: Genome may not contain factors relevant for mammalian muscle development Mammalian embryos do not have yellow protoplasm, so mechanisms likely different Great for studying autonomous development, but not the conditional development commonly used in mammalian systems Figure 3 legend: n–r, Embryos at the 110-cell stage fixed and in in situ hybridized with the muscle actin ( HrMA4 ) probe. n, Uninjected control. Actin expression is observed in ten precursor blastomeres of primary muscle cells. o, macho-1 -depleted embryos. p, q, Synthesized macho-1 mRNA was subsequently injected. Actin is ectopically expressed in endoderm ( p ) and epidermis ( q ) blastomeres. r, Subsequent injection of mutant mRNA has no effect. Figure 1 legend: b, Structure of macho-1 protein and constructs for in vitro mRNA synthesis. Macho-1 has five zinc fingers in the central part. The cDNA clone is 2,210 bp long and encodes a 556-amino-acid ORF. The wild-type construct encodes the full length, but the mutant construct lacks the zinc-finger domain. 3b. What do you conclude based on the results presented in Figure 3o ? (Limit: 1 sentence) [4pts] macho-1 is necessary for muscle actin ( HrMA4 ) expression at the 110-cell stage. Page 3
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BIOL 411 - 2023 Autumn Exam 1 [1pt] Accurate description of the results. 3c. What do you conclude based on the combined results presented in Figure 3p,q ? (Limit: 1 sentence) [4pts] macho-1 is sufficient to promote muscle actin ( HrMA4 ) expression in endodermal and epidermal blastomeres at the 110-cell stage. [1pt] Accurate description of the results. 3d. Explain to your peer the question the authors were addressing with their mutant mRNA injection. (Limit: 1 sentence) [4pts ] Is injection of macho-1 mRNA lacking the zinc finger domain sufficient to rescue muscle actin ( HrMA4 ) expression in macho-1 -depleted embryos at the 110-cell stage? Alternative answer: the authors were testing if the zinc finger domain is necessary for macho-1 function. [1pt] Accurate description of the results. Argues that it is a rescue experiment or functioning as an injection control. [0pts] The zinc finger domain is not mentioned. Testing if macho-1 mRNA is necessary and sufficient for muscle development was queried in figure 3o,p, and q. 3e. Imagine that injection of the macho-1 mutant mRNA into macho-1 -depleted embryos resulted in embryos that looked like the one presented in Figure 3n . What would you infer about the potential molecular function of Macho-1 protein based on this potential result? (Limit: 1 sentence) [4pts] Macho-1 can promote muscle actin ( HrMA4 ) expression independently of its zinc finger domain. Other possible interpretations: e.g., it doesn’t need to bind to DNA, function as a TF function, etc. to promote muscle actin expression. [2pts] The zinc finger domain is not mentioned but the answer is otherwise correct. 4. During this Unit, you “jigsawed” the seminal paper “The Drosophila Homolog of C. elegans PAR-1 Organizes the Oocyte Cytoskeleton and Directs oskar mRNA Localization to the Posterior Pole” by Joshua M. Shulman, Richard Benton, and Daniel St Johnston ( Cell 2000 101:377–388). 4a. Based on your understanding of the background to this paper, what led the authors to investigate PAR-1 as a candidate regulator of A/P axis determination in Drosophila ? Limit: 1 sentence. [3pts] Previous work in the early C. elegans embryo had identified PAR-1 as an essential regulator of A/P axis determination and the authors wanted to test if this function of PAR-1 was conserved in Drosophila . Page 4
BIOL 411 - 2023 Autumn Exam 1 Figure 6 legend: ( A–D ) Microtubule organization visualized in live oocytes by expression of Tau:GFP; all images were taken at a similar, central focal plane. (E and F) Kin:β-gal. ( G and H ) Nod:β-gal. ( A, E, and G ) par-1 /+ sibling controls, in which microtubule organization and polarity are indistinguishable from wild-type. (B) par-1 6821 is shown, and a similar phenotype is consistently observed in all allelic combinations. ( F and H ) par-1 6323 /par-1 W3 . ( C ) capu RK . ( D ) grk 2E12 . Put your developmental biology mantra to use! For each of the panels listed at right from Figure 6, fill in the blank with the response that best fits the experiment. Possible responses: (Find it / Move it / Lose it). For full credit, explain your reasoning. Limit: 1 sentence per response. [5pts each/15pts total] 4b. Figure 6A _ Find it [2.5pts] _ Reasoning: This panel serves to illustrate the wild-type patterning of the microtubule cytoskeleton (via Tau:GFP expression). [2.5pts] 4c. Figure 6B _ Lose it [2.5pts] _ Reasoning: This panel serves to illustrate the patterning of the microtubule cytoskeleton (via Tau:GFP expression) in an oocyte homozygous for a loss-of-function allele of par-1 ( par-1 6821 ). [2.5pts] 4d. Figure 6E _ Find it [2.5pts] _ Reasoning: This panel serves to illustrate the wild-type polarity of the microtubule cytoskeleton (via Kin:β-gal, which labels the (+) ends of microtubules). [2.5pts] Page 5
BIOL 411 - 2023 Autumn Exam 1 5. While studying at the health sciences library, you come across a back issue of the journal Development that contains an article analyzing the functions of the Drosophila gene staufen (stau) . Specifically, the authors perform a structure-function analysis to assess roles for the different domains of the Stau protein. Background: Full-length Stau (Stau full ) contains five (ds)RNA-binding domains (dsRBDs) and a short region within an insertion that splits dsRBD2 into two halves. Methods: The authors assay rescue of a homozygous loss-of-function mutation in stau ( stau D3 /stau D3 ) with various transgenic constructs encoding the Stau protein forms shown below. You can assume that the Stau full transgene (T[Stau full ]) completely rescues the stau mutant phenotype and that the anti-Stau antibody used by the authors recognizes all of the Stau transgenes. Figure 1 legend: D, A diagram showing the structure of the Stau proteins encoded by the Stau full , Stau ΔN , Stau Δloop2 and Stau ΔdsRBD5 transgenes. The green boxes indicate the positions of the dsRBDs. The arrows and adjacent blue boxes indicate the N-termini of the amino acid sequences. Figure 2 legend: A–B, Localization of Stau protein and oskar ( osk ) mRNA as indicated by the dark staining in stage 9 (i and iii) and 10 (ii and iv) oocytes from stau D3 T[Stau full ]/ stau D3 females ( A ) or stau D3 T[Stau ΔN ]/ stau D3 females ( B ). 5a. Based on the data presented in Figure 2, what do you observe about the localization of the Stau ΔN protein within the oocyte? Note that you can ignore any differences in the intensity of the staining between panels A and B. (Limit: 1 sentence) [5pts] Similar to Stau full , Stau ΔN localizes to the posterior of the oocyte at stages 9 and 10. 5b. Based on the data presented in Figure 2, what do you conclude about the relationship between the structure of the Stau protein and osk localization within the oocyte? Note that you can ignore any differences in the intensity of the staining between panels A and B.(Limit: 1 sentence) The N-terminus of Stau is not necessary for localization of osk mRNA to the posterior of the oocyte at stages 9 and 10 [5pts] Page 6
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BIOL 411 - 2023 Autumn Exam 1 Question 5 continued… Figure 3 legend: Localization of Stau protein ( A,B ), oskar ( osk ) mRNA ( C,D ), and Oskar (Osk) protein ( E,F ) in stage 9 ( A,C,E ) and 10 ( B,D,F ) oocytes from stau D3 T[Stau ΔdsRBD5l ]/ stau D3 females. 5c. Based on the data presented in Figure 3, what do you conclude about the relationship between the structure of the Stau protein and Osk protein localization within the oocyte? (Limit: 1 sentence) [5pts] The dsRBD5 domain of Stau is necessary for Osk localization to the oocyte posterior at stage 10, but not at stage 9. +4 for stating the dsRBD5 domain is necessary for Osk localization to the posterior. +1 for identifying that the dsRBD5 domain is necessary for Osk localization to the oocyte posterior at stage 10, but not at stage 9. Page 7
BIOL 411 - 2023 Autumn Exam 1 Question 5 continued… Figure 4 legend: bicoid ( bcd ) mRNA localization in freshly laid eggs from wildtype (top panel), stau D3 T[Stau Δloop2 ]/ stau D3 (middle panel) and stau D3 T[Stau ΔdsRBD5 ]/ stau D3 (bottom panel) females. Note: please use the same coordinate system for questions 5d and 5e below. i.e., your graphs should be comparable to each other. 5d. Based on the data presented in Figure 4 and using the axes below, draw the expected Bcd protein gradient and corresponding threshold and position of the head fold (HF) along the A/P axis in stau D3 T[Stau Δloop2 ]/ stau D3 embryos. For your convenience, the Wildtype gradient and head fold threshold and position are shown in blue. [5pts] 5e. Based on the data presented in Figure 4 and using the axes below, draw the expected Bcd protein gradient and corresponding threshold and position of the head fold along the A/P axis in stau D3 T[Stau ΔdsRBD5 ]/ stau D3 embryos.For your convenience, the Wildtype gradient and head fold threshold and position are shown in blue. [5pts] 5d: +2 for drawing the Bcd concentrations for the stau D3 T[Stau Δloop2 ]/ stau D3 embryos above WT across the Page 8
BIOL 411 - 2023 Autumn Exam 1 A-P axis +2 for indicating HF position more posterior to WT +1 for having threshold Bcd concentrations at same level as WT 5e: +2 for drawing the Bcd concentrations for the T[Stau ΔdsRBD5 ]/ stau D3 embryos above WT across the A-P axis +1 for indicating HF position more posterior to WT +1 for having threshold Bcd concentrations at same level as WT +1 for having HF position more posterior compared to stau D3 T[Stau Δloop2 ]/ stau D3 embryos 6. Developmental biologists often order processes into step-wise pathways. A great example of this is the development of Drosophila oocyte polarity. Place the following items in order (1,2,3…) and put an “X” next to any false statement. Note that by convention, a name in lower-case italics refers to an mRNA (e.g., nanos ) and a non-italicized name with an upper-case first letter refers to a protein (e.g., Nanos). [10pts - partial credit possible] _ X _ Sperm entry cues initial asymmetry _ 4 _ Par-1 organizes microtubules with their plus and minus ends at the posterior and anterior ends of the oocyte, respectively _ 2 _ Gurken binds to Torpedo expressed by follicle cells _ X _ nanos is trafficked to the posterior pole along microtubules _ X _ Bicoid is trafficked to the anterior pole along microtubules _ 5 _ oskar is trafficked to the posterior pole _ 3 _ Follicle cells produce protein kinase A _ 6 _ Oskar binds to nanos at the posterior pole _ X _ Par-1 localizes to the anterior pole of the oocyte _ 1 _ gurken is synthesized by the nurse cells +4 for correctly identifying false statements (+1 for each correct identification) +6 for correctly identifying order (+1 is given for each correct step in the process, starting from step 1- “gurken is synthesized by the nurse cells”. So getting steps 1-2 right will fetch +2 points, getting steps 1-3 right will fetch +3 points, and so on). 7. Which of the following statement(s) are true about the transition from syncytial to cellular blastoderm in Drosophila ? [3pts] A. Nuclei migrate to the periphery of the blastoderm where they enter cell membrane pockets B. Transcription of zygotic genes occurs before cellularization, allowing diffusion of gene products within the blastoderm C. Nuclear divisions are synchronized and occur in waves across the blastoderm D. A and B E. A and C F. B and C G. All of the above H. None of the above Page 9
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