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Task 1
Heredity and Genetics – C652
Dec 4, 2023
2. Bacteria contain genomes that use energy to create proteins. An operon is a unit made of linked genes which is used to regulate the genes that are responsible for protein synthesis. So, the operon functions as a signaler to the protein-creating
genes. The operon can send activators that will signal the gene to begin protein creation, and repressors that will signal it to stop.
The E. coli bacteria are known for consuming sugars for energy, but when none are available, will consume lactose. E. coli can break down lactose, but only when glucose is not present, because of a preference for glucose. The lac
operon is responsible for encoding proteins that allow E. coli bacteria to use the lactose for energy.
The activators and repressors are the two regulators that tell the operon to start or stop. The lac repressor acts as a detector for lactose and will usually block the transcription process. When lactose is present, however, it will no longer block this function. This will activate the operon and begin the protein creation.
B. Describe two mechanisms, other than mutation, that human cells use to regulate the expression of a gene.
One mechanism used in gene expression would be transcription. Transcription describes
the process of creating a RNA copy of a gene’s DNA sequence. The copy is called the messenger RNA, and it will carry a gene’s protein information to prepare for synthesizing the encoded protein. Another mechanism used in gene expression would be
translation. During translation, proteins are produced using RNA as a guide. A sequence
of amino acids will be formed together in groups of 3 to synthesize a protein.
C. Gene regulation is how a cell controls which genes are turned on and off. Each different cell type in the human body has a unique set of genes along with the exact
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Related Questions
Urgently needed
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Please complete Task #2
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Task #2 Flow of information: A codon table is provided above. The 5' codon
nucleotide is in the left column, and second codon nucleotide is on top. The Mcr1 M and
m allele sequences are shown again in the central dogma grids below with the reading
frame designated. Fill in the grids. In the second column indicate the end polarity (5' or
3', N or C). For both alleles, determine the sequences of the DNA template strand,
mRNA, tRNA and polypeptide.
Mc1r gene M allele:
DNA sense strand
DNA template strand
mRNA codon
tRNA anticodon
polypeptide
Mc1r gene m allele:
DNA sense strand
DNA template strand
mRNA codon
tRNA anticodon
polypeptide
5' A A A A
5' A
A
A
A
A
A
Q
C
C G
C A
T G C
A C
A A C
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1
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Lesson 2
Focus Questions
1. What chemicals and molecules are needed for PCR, and what is the function of each
component?
2. Examine the 150 base promoter sequence below.
Kaylee Kauff
5'TAGAAAAGGA AGGTGGCTCC TACAAATGCC ATCATTGCGA TAAAGGAAAG
GTATCATTC AAGATGCCTC TGCCGACAGT GGTCCCAAAG ATGGACCCCC
ACCCACGAGG AGC ATCGTGG AAAAAGAAGA CGTTCCAACC ACGTCTTCAA3'
Write in the sequence of the complementary strand and mark the 3' and 5' ends of the
complementary strand.
43
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Urgently needed
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problem79
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Question:
Genetically modified animal that might be approved for human consumption is a super “muscly” pig made by the inactivation of the myostatin gene. During normal development, the myostatin protein prevents the overgrowth of muscles.
How would such a pig be achieved using CRISPR?
Why would it not considered the GMO?
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Problem 3: Proteins that bend DNA
Integration Host Factor, IHF, is an architectural protein in E. coli
that helps to package the DNA inside the cell as well as to organize
the DNA for higher-order nucleoprotein complexes. IHF can bend
some DNA segments are 35 base-pairs long into a U-turn as shown
in the figure to the right.
The Young's modulus of DNA is 300 MPa, and its cross-sectional
radius is 1 nm. Model DNA as a cylindrical rod.
A. What is the bending coefficient of DNA in units of J. m?
B. How long is a 35 base-pair long segment of DNA? (Express your answer in nm given that the
separation between base pairs in double-stranded DNA is 0.34 nm.)
C. By what angle (in radians) is the DNA bent in the IHF-bound complex?
D. Determine the radius of curvature (in nm) for the bent DNA in this IHF-bound complex.
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Task #1 Mc1r alleles: In Florida Gulf coast mice, there are two different alleles of the Melanocortin Receptor (Mcr1) gene. The sequence for both alleles is shown below. This is an internal segment of the coding (non-template) sequence of the Mcr1 gene. The reading frame is set and you do not need to find an AUG. M allele 5’...ATC ACC AAA AAC CGC AAC CTG CAC TCG... m allele 5’...ATC ACC AAA AAC TGC AAC CTG CAC TCG... A. Compare these two allele sequences and circle the nucleotides that are different.
B. Do you think this change will cause a shift in the codon reading frame? Why or why not?
C. Do you think that this change will cause an early stop in translation? Why or why not?
Task #2 Flow of information: A codon table is provided above. The 5’ codon nucleotide is in the left column, and second codon nucleotide is on top. The Mcr1 M and m allele sequences are shown again in the central dogma grids below with the reading frame designated. Fill in the grids. In the second column…
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problem18
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Practice Problem 1:
The coding sequences of Gene F and Gene G are shown by the double-stranded DNA below:
Gene F
5' ATGGGAGCACCAGG ACAAGATGGATATCATTAG 3
AGTTA C CCTCGTGGT CCTGTTCTACCTATAGTA 5'
3'
Gene G
Questions:
1. Write down the messenger RNA sequence when Gene F is transcribed.
2. Write down the polypeptide chain when Gene F is completely expressed.
3. Write down the messenger RNA sequence when Gene G is transcribed.
4. Write down the polypeptide chain when Gene G is completely expressed.
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Task #1 Mc1r alleles: In Florida Gulf coast mice, there are two different alleles of the
Melanocortin Receptor (Mcr1) gene. The sequence for both alleles is shown below. This
is an internal segment of the coding (non-template) sequence of the Mcr1 gene. The
reading frame is set and you do not need to find an AUG.
M allele
m allele
5'...ATC ACC AAA AAC CGC AAC CTG CAC TCG...
5'...ATC ACC AAA AAC TGC AAC CTG CAC TCG...
A. Compare these two allele sequences and circle the nucleotides that are different.
B. Do you think this change will cause
mRNA Codon Table
Second base
a shift in the codon reading frame?
Why or why not?
C. Do you think that this change will
cause an early stop in translation?
Why or why not?
First base
U
U Phe
Phe
Leu
Leu
C Leu
Leu
Leu
Leu
A lle
lle
lle
Met
G Val
Val
Val
Val
C
Ser
Ser
Ser
Ser
Pro
A
G
Cys
Tyr Cys
STOP Trp
STOP STOP A
His Arg
Pro
His
Pro Gin
Pro Gin
Thr
Asn
Thr
Asn
Thr
Lys
Thr
Lys
Ala
Ala
Ala
Ala
Arg
Arg
Arg
Ser
Ser
Arg
Arg
Gly
Asp
Asp
Glu Gly
Glu
Gly…
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PLEASE HELP, LONG ANSWERS WOULD BE APPRECIATED
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I need help wiht this one!
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Urgently needed
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L
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problem set 1 #25. What is Cot analysis? Do the Cot renaturation curves for a virus, bacterium, and yeast all roughly correspond to the size of their genomes?
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Task 1. Your graduate advisor asks you to amplify the following sequence of DNA by PCR:
5’-ATACGCATTCGGACCAGGTCCTAA-3’
3’-TATGCGTAAGCCTGGTCCAGGATT-5’
a. To ensure that the entire sequence above is amplified, what 6-nucleotide DNA primers
should you add to your PCR mix?
You order the primers listed above, but instead receive the following set of primers:
5’-CGCATT-3’
5’-GGACCT-3’
b. What portion of the double stranded DNA molecule will be amplified after 10 rounds of
PCR?
Your labmate attempts to rescue your PCR reaction by providing you with the following
set of primers:
5’-ATACGC-3’
5’-TCCTAA-3’
c. What is the result of running the PCR reaction with your labmate’s primers? How many
double stranded molecules of DNA will result from 10 rounds of amplification?
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ACTIVITY 3: Analyze Me!
Direction: Draw a smiling face (O) if the statement is an importance of genetic
engineering and (O if not.
1. Genetic engineering has been used to mass-produce insulin.
2. Genes and other genetic information from a wide range of organisms are
transformed into bacteria for storage and modification, creating genetically
modified bacteria in the process.
3. Some genetically engineered animals become an important source of new
drugs.
4. Many genetically engineered crops are being used by many farmers now.
5. Genetic engineering is used to produce more needed genetically engineered
medicines.
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Question (1)-Describe the three different methods of horizontal gene transfer among bacteria and mention their significance.
Be specific when discussing the donor versus recipient cell, and if the donor and recipient cells are still alive after each horizontal gene transfer event is complete.
*Please go into detail if possible on what the donor and recipient cells if they are still alive also after each gene transfer. I have a test coming up that I’m trying to learn all I can about this. Thank you so much!*
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Instructions:
Read 13-2 Manipulating DNA pages 322-323.
As you read each section, examine the figures and captions (explanations). Identify any
questions you may have.
1) Develop an analogy for the processes researchers use to make changes to DNA. In yo
analogy, explain how it is similar to the techniques used in genetic engineering.
You can draw a graphic organizer, make a table, or write a few sentences describing your
analogy.
2) Devise flowchart that shows the steps to prepare DNA for gel electrophoresis, as well
the protocol for setting up and running a gel. You can add diagrams to the flowchart an
add detailed notes if you like.
English (inited Sate)
O Focs
ere to search
4
CO
RU
G\
L
B.
2N
A\
Alt
Ciri
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Task 3: Agarose Gel Electrophoresis
Your amplicon from PCR was subjected to AGE for analysis. You are shown the image of the gel loaded with the following lanes: (A) negative control, (B) size ladder (1, 2, 3, 4, 6, and 10 kb), (C) gDNA extract, (D) PCR amplicon. However, due to mishaps while loading the gel with the samples, you are not sure which lane is which. You are shown a diagram of the obtained gel below.
a. b.
Label each lane of the gel. Write only the corresponding letters in the wells above. Above each band in the size ladder, write its size (in kb).
c.corresponding to the gene.
Approximate the size (in kb) of the polystyrenase gene. Write your answer above the band
Bonus: If you wish to identify the bacterial species in this scenario, what gene is most commonly and routinely sequenced?Answer: __________________________________
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Do help with both the parts within one and half hours I need to submit assignment urgently
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Task A: Polymerase Chain Reaction Master Mix Your first task is to isolate and amplify the NRAS gene from cDNA extracted from different samples through PCR. You will need to run a total of 7 PCRs: 3 normal samples, 3 cancerous samples, and 1 negative control. To make things easier in the lab, when running multiple reactions, the components are prepared not individually, but as a master mix—all the components for multiple reactions are prepared in bulk, except for the template DNA, which is added separately once the master mix has been distributed into individual tubes. The table below lists the different components for PCR, the available stock concentrations of these components, and the needed working concentrations for the PCR itself. Complete the table by supplying the needed volumes of each component for a single reaction and for the master mix (the first row has been filled in as an example).
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Practice Question 8
- Below are two cell signalling pathways that work together to regulate cell growth, proliferation and
ultimately the size of organs in O.Extremus. In other closely related organisms, dysfunction of these
pathways has been associated with tumor growth.
mTOR pathway:
1. Growth factors bind and stimulate the receptors.
crosstalk
Hippo
Pathway
2. Receptors can activate the phosphatidylinositol
3 kinase (PI3K) – Akt signaling pathway.
MTOR
Pathway
-
3. The activated Akt, a serine threonine kinase,
inhibits theTSC1–TSC2 complex, allowing Rheb to
activate mTORC1.
Mst
РІЗК
PTEN
Lats
АКТ
4. In parallel, amino acids activate the mTORC1
pathway through a mechanism requiring the Rag-
ator con
miR-29
YAP
TSC2-TSC1
lex.
amino acids
Rag-Ragulator
Hippo pathway:
1. The binding of the ligand activates the receptors
which activate Mst and Lats.
Rheb
cell
division
MTORC1
organ size
2. YAP activity is modulated by phosphorylation of
Mst and Lats. YAP upregulates miR-29, which in
turn…
arrow_forward
Practice Question 8
- Below are two cell signalling pathways that work together to regulate cell growth, proliferation and
ultimately the size of organs in O.Extremus. In other closely related organisms, dysfunction of these
pathways has been associated with tumor growth.
mTOR pathway:
1. Growth factors bind and stimulate the receptors.
crosstalk
Hippo
Pathway
2. Receptors can activate the phosphatidylinositol
3 kinase (PI3K) – Akt signaling pathway.
MTOR
Pathway
3. The activated Akt, a serine threonine kinase,
inhibits the TSC1-TSC2 complex, allowing Rheb to
activate mTORC1.
Mst
PI3K
PTEN
Lats
AKT
4. In parallel, amino acids activate the mTORC1
pathway through a mechanism requiring the Rag-
Ragulator complex.
(miR-29
YAP
TSC2-TSC1
amino acids
Rag-Ragulator
Hippo pathway:
1. The binding of the ligand activates the receptors
which activate Mst and Lats.
Rheb
cell
division
MTORC1
organ size
2. YAP activity is modulated by phosphorylation of
Mst and Lats. YAP upregulates miR-29, which in…
arrow_forward
Practice Question 8
- Below are two cell signalling pathways that work together to regulate cell growth, proliferation and
ultimately the size of organs in O.Extremus. In other closely related organisms, dysfunction of these
pathways has been associated with tumor growth.
MTOR pathway:
1. Growth factors bind and stimulate the receptors.
crosstalk
Hippo
Pathway
2. Receptors can activate the phosphatidylinositol
3 kinase (PI3K) – Akt signaling pathway.
MTOR
Pathway
3. The activated Akt, a serine threonine kinase,
inhibits theTSC1-TSC2 complex, allowing Rheb to
activate mTORC1.
Mst
РІЗК
PTEN
T
Lats
АКТ
4. In parallel, amino acids activate the mTORC1
pathway through a mechanism requiring the Rag-
Ragulator complex.
(miR-29
YAP
TSC2-TSC1
amino acids
Rag-Ragulator
Hippo pathway:
1. The binding of the ligand activates the receptors
which activate Mst and Lats.
Rheb
cell
division
MTORC1
organ size
2. YAP activity is modulated by phosphorylation of
Mst and Lats. YAP upregulates miR-29, which in…
arrow_forward
Practice Question 8
- Below are two cell signalling pathways that work together to regulate cell growth, proliferation and
ultimately the size of organs in O.Extremus. In other closely related organisms, dysfunction of these
pathways has been associated with tumor growth.
MTOR pathway:
1. Growth factors bind and stimulate the receptors.
crosstalk
Hippo
Pathway
2. Receptors can activate the phosphatidylinositol
3 kinase (PI3K) – Akt signaling pathway.
MTOR
Pathway
3. The activated Akt, a serine threonine kinase,
inhibits theTSC1-TSC2 complex, allowing Rheb to
activate mTORC1.
Mst
РІЗК
PTEN
Lats
АКТ
4. In parallel, amino acids activate the mTORC1
pathway through a mechanism requiring the Rag-
Ragulator complex.
miR-29
YAP
TSC2-TSC1
amino acids
Hippo pathway:
1. The binding of the ligand activates the receptors
which activate Mst and Lats.
Rheb
Rag-Ragulator
cell
division
MTORC1
organ size
2. YAP activity is modulated by phosphorylation of
Mst and Lats. YAP upregulates miR-29, which in…
arrow_forward
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Related Questions
- Urgently neededarrow_forwardPlease complete Task #2arrow_forwardTask #2 Flow of information: A codon table is provided above. The 5' codon nucleotide is in the left column, and second codon nucleotide is on top. The Mcr1 M and m allele sequences are shown again in the central dogma grids below with the reading frame designated. Fill in the grids. In the second column indicate the end polarity (5' or 3', N or C). For both alleles, determine the sequences of the DNA template strand, mRNA, tRNA and polypeptide. Mc1r gene M allele: DNA sense strand DNA template strand mRNA codon tRNA anticodon polypeptide Mc1r gene m allele: DNA sense strand DNA template strand mRNA codon tRNA anticodon polypeptide 5' A A A A 5' A A A A A A Q C C G C A T G C A C A A Carrow_forward
- 1arrow_forwardLesson 2 Focus Questions 1. What chemicals and molecules are needed for PCR, and what is the function of each component? 2. Examine the 150 base promoter sequence below. Kaylee Kauff 5'TAGAAAAGGA AGGTGGCTCC TACAAATGCC ATCATTGCGA TAAAGGAAAG GTATCATTC AAGATGCCTC TGCCGACAGT GGTCCCAAAG ATGGACCCCC ACCCACGAGG AGC ATCGTGG AAAAAGAAGA CGTTCCAACC ACGTCTTCAA3' Write in the sequence of the complementary strand and mark the 3' and 5' ends of the complementary strand. 43arrow_forwardUrgently neededarrow_forward
- problem79arrow_forwardQuestion: Genetically modified animal that might be approved for human consumption is a super “muscly” pig made by the inactivation of the myostatin gene. During normal development, the myostatin protein prevents the overgrowth of muscles. How would such a pig be achieved using CRISPR? Why would it not considered the GMO?arrow_forwardProblem 3: Proteins that bend DNA Integration Host Factor, IHF, is an architectural protein in E. coli that helps to package the DNA inside the cell as well as to organize the DNA for higher-order nucleoprotein complexes. IHF can bend some DNA segments are 35 base-pairs long into a U-turn as shown in the figure to the right. The Young's modulus of DNA is 300 MPa, and its cross-sectional radius is 1 nm. Model DNA as a cylindrical rod. A. What is the bending coefficient of DNA in units of J. m? B. How long is a 35 base-pair long segment of DNA? (Express your answer in nm given that the separation between base pairs in double-stranded DNA is 0.34 nm.) C. By what angle (in radians) is the DNA bent in the IHF-bound complex? D. Determine the radius of curvature (in nm) for the bent DNA in this IHF-bound complex.arrow_forward
- Task #1 Mc1r alleles: In Florida Gulf coast mice, there are two different alleles of the Melanocortin Receptor (Mcr1) gene. The sequence for both alleles is shown below. This is an internal segment of the coding (non-template) sequence of the Mcr1 gene. The reading frame is set and you do not need to find an AUG. M allele 5’...ATC ACC AAA AAC CGC AAC CTG CAC TCG... m allele 5’...ATC ACC AAA AAC TGC AAC CTG CAC TCG... A. Compare these two allele sequences and circle the nucleotides that are different. B. Do you think this change will cause a shift in the codon reading frame? Why or why not? C. Do you think that this change will cause an early stop in translation? Why or why not? Task #2 Flow of information: A codon table is provided above. The 5’ codon nucleotide is in the left column, and second codon nucleotide is on top. The Mcr1 M and m allele sequences are shown again in the central dogma grids below with the reading frame designated. Fill in the grids. In the second column…arrow_forwardproblem18arrow_forwardPractice Problem 1: The coding sequences of Gene F and Gene G are shown by the double-stranded DNA below: Gene F 5' ATGGGAGCACCAGG ACAAGATGGATATCATTAG 3 AGTTA C CCTCGTGGT CCTGTTCTACCTATAGTA 5' 3' Gene G Questions: 1. Write down the messenger RNA sequence when Gene F is transcribed. 2. Write down the polypeptide chain when Gene F is completely expressed. 3. Write down the messenger RNA sequence when Gene G is transcribed. 4. Write down the polypeptide chain when Gene G is completely expressed.arrow_forward
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