Lab Report Fatty acid composition of oils_Aqilah Khairuddin

.pdf

School

University of New South Wales *

*We aren’t endorsed by this school

Course

2921

Subject

Chemistry

Date

Apr 25, 2024

Type

pdf

Pages

11

Uploaded by wanaqilah01

CHEM2921: Food Chemistry Lab Manual Student name: Aqilah Khairuddin zID:z5432922 1 FATTY ACID COMPOSITION OF OILS: REPORT Results – Method A: GC-MS a. Report your sample information: Table 1. Sample information Sample number 384 Sample mass / g 0.251g The following formula allows the calculation of the proportion of each methyl ester: Percent Fatty Acid = Peak Area (Fatty Acid methyl ester) Total peak area × 100 b. Using your GC-MS data provided, and the formula above, calculate the percentage composition of fatty acids in the unknown oil. Total peak area = 72028+ 45927905 + 6268770 + 229964567 + 20831782 + 1703110 = 304768162 % C14 (mystiric)= Peak Area (Fatty Acid methyl ester) Total peak area × 100 = 72028 304768162 × 100 = 0.02% % C16 (palmitic) = Peak Area (Fatty Acid methyl ester) Total peak area × 100 = 45927905 304768162 × 100 =15.07%
CHEM2921: Food Chemistry Lab Manual Student name: Aqilah Khairuddin zID:z5432922 2 % C18 (stearic) = Peak Area (Fatty Acid methyl ester) Total peak area × 100 = 6268770 304768162 × 100 = 2.07% % C18:1 (oleic) = Peak Area (Fatty Acid methyl ester) Total peak area × 100 = 229964567 304768162 × 100 =75.46% % C18:2 (linoleic) = Peak Area (Fatty Acid methyl ester) Total peak area × 100 = 20831782 304768162 × 100 =6.84% % C18:3 (linolenic) = Peak Area (Fatty Acid methyl ester) Total peak area × 100 = 1703110 304768162 × 100 =0.56%
CHEM2921: Food Chemistry Lab Manual Student name: Aqilah Khairuddin zID:z5432922 3 Figure 1: Gas chromatography and mass spectrum result
CHEM2921: Food Chemistry Lab Manual Student name: Aqilah Khairuddin zID:z5432922 4 Results – Method B: Iodine value and uncertainty calculation 1. Report your raw data: Table 2. Sample information Sample number 384 Mass / g Sample 0.168 0.174 Concentration of iodine monochloride in glacial acetic acid / mol L -1 16.2g/L Table 3. Titration results Volume of thiosulfate / mL Sample 29.5 30.3 Reagent blank 42.1 Concentration of sodium thiosulfate / mol L -1 0.1 2. Calculate the iodine value (g(I) / 100g) ± uncertainty from the formula below: iodine value = (b - a) × 1.269 mass of sample where b = volume (mL) of thiosulfate in titration of reagent blank a = mean volume (mL) of thiosulfate in titration of sample 1. Calculate the mean of the two sample masses: s = 0.168 + 0.174 2 s = 0.171g 2. Calculate the percentage uncertainty of this sample mean: Use the largest mass as mass 1. χ = 0.174 - 0.168 2 ÷ 0.171 ×100 χ = 1.754
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help