*O chem lab report
.docx
keyboard_arrow_up
School
Grand Canyon University *
*We aren’t endorsed by this school
Course
231L
Subject
Chemistry
Date
Feb 20, 2024
Type
docx
Pages
15
Uploaded by ConstableIronBoar27
Abstract
Natural products are materials extracting from organic compounds that can contribute to many medical, scientific, and cultural advancements. This study investigates the extraction and examination of organic compounds found naturally, particularly the chromophores in grape leaves. The main objective revolved around isolating and recognizing specific compounds using methods like column chromatography and UV-Vis Spectrophotometry. The findings pointed to the presence of Chlorophyll A, Chlorophyll B, and Pheophytin A within the grape leaves. To identify these compounds, data was compared with existing literature values within reasonable anaylsis. Recommendations of future experiments highlight the constraints of the procedures and suggests alternatives such as flash chromatography and high-performance liquid chromatography to address error within the lab. By refining extraction methods and broadening comparative studies across various plant species, future experiments could be greatly enhanced. Extracting natural products plays a significant role in scientific exploration and is vital to continue research as modern medicine and science continues to expand.
Introduction
Natural products are a diverse group consisting of organic products produced by life which can range from wood and soil, to milk and plants. Natural products can be found in prokaryotes such as bacteria and archaea and eukaryotes such as fungi, plants, and animals. Natural product extraction is the isolation of various compounds such as enzymes, proteins, pigments, terpenes, and antibiotics. The use of extraction can be traced back to beginning civilizations who harnessed the healing and regenerative properties of plants, grains, and soils. Extraction is a key role in agriculture, food, cosmetics, and fragrances. Natural product extraction also plays a key role in medicinal advancements such as cancer research, drug discovery, and preventative medicine. In pharmaceuticals, 49% of the drugs are either natural products or derived from natural products. (Cragg, 2016). Morphine, opium from poppy, quinine from cochine bark, and aspirin from willow bark all are drugs synthesized from natural products as therapeutic agents. Antibiotics such as penicillin from fungus are another example of medicinal extraction. Natural extractions can be used in cancer research such as the compound, vincristine from the Madagascar Periwinkle w;hich can be used to treat leukemia. Taxol from the
Pacific Yew Tree has also been used in cancer therapy (Cragg, 2016). A useful organic product from plants are chromophores which give pigmentation and certain chemical properties to the organic compound. Chromophores play a crucial role in the plant's photosynthetic capabilities. During photosynthesis, light energy is converted into glucose, providing energy for metabolic processes, growth, and reproduction. Moreover, photosynthesis releases oxygen and contributes to the regulation of carbon dioxide levels. Chlorophylls, carotenoids, and anthocyanins are
examples of pigments found in various plants. UV-visible spectroscopy is a technique often used
to identify and examine the absorption of light by the sample of these chromophores.
Isolation of these natural products is a mutli-stage process consisting of extraction and purification. Extraction, purification, structural identification, and synthesis are all processes involving isolation of natural products, Extraction is the first step to separate the desired natural products from the raw materials. This is based on solubility and acid base properties. Purification
is based on chromatography and recrystallization. Identification of products can be found through many procedures such as Solvent extraction, thin layer chromatography, ultraviolet visible spectroscopy, infrared spectroscopy, nuclear magnetic resonance, mass spectrometry, atomic spectroscopy, and X-ray spectroscopy (Smith, 2020). Chromophores specifically are best analyzed through the use of column chromatography and UV-Vis spectroscopy. Chromophores are grouped into subgroups such as carotenes, pheophytins, chlorophylls, and xanthophylls. Derivatives of these subgroups involve α-carotene, β-carotene, phenophytin B and chlorophyll B (Smith, 2020). Science utilizes these methods to identify and analyze natural products and compounds. The compounds must be lysed, centrifuged, and analyzed with thin layer column chromatography. The absorption of pigments extracted from the plants is analyzed with UV-
spectroscopy. The analysis of these natural compounds derived from organic compounds plays a crucial role in development of medicine, pharmaceuticals, agriculture, and technology.
Methods and Results
Week 1: Extraction of a Natural Product
Two grams of recently harvested green grape leaves were finely ground using a mortar and pestle provided by the laboratory instructor. Following the addition of 2 mL of acetone, the
resulting mixture was carefully transferred to a labeled centrifuge tube (Tube 1). The mortar underwent two additional rinses with acetone, ensuring a cumulative volume of at least 6 mL in Tube 1. After a thorough 2-minute vortexing, Tube 1 underwent centrifugation at 2000 rpm for 2 minutes, employing a counterweight. Subsequently, the tube was delicately handled to avoid disturbing the sediment, and the acetone fraction was poured into a separate labeled tube (Tube 2). Tube 2 was then supplemented with 3 mL each of
hexane and deionized water. Following a minute of vortexing
and centrifugation at 1000 rpm for 2 minutes, Tube 1 underwent
a
cleaning process to eliminate plant debris and was dried using
compressed air under the fume hood. The acetone/water layer
from Tube 2 was then carefully transferred back to Tube 1
utilizing a Pasteur pipette. Meanwhile, the hexane from Tube 2 was reserved, and 2 mL of hexane was introduced to Tube 1, followed by a minute of vortexing and centrifugation at 1000 rpm for 2 minutes. The acetone layer was discarded, and the amalgamated hexane solution from both tubes was prepared for subsequent steps. Figure 2: Sample tube after centrifugation. Sample
product assembled at the bottom of the tube.
Figure 1: Balanced centrifuge tubes ready for
centrifugation.
To establish a drying column, a Pasteur pipette was packed with cotton and sodium sulfate, affixed to a support, with a fresh centrifuge tube positioned below. The hexane layer was meticulously passed through the column. Following this, three TLC plates were readied, each delineated with a line positioned 1 cm above the bottom edge. Extract samples were applied to the plates using glass microtubes: four drops on the first
spot, eight drops on the second, and sixteen drops on the
third along the marked line. Three distinct jars containing
hexane with ratios of 90:10, 80:20, and 70:30 were
prepared. Each TLC plate was immersed in one of the jars
and retrieved when the solvent had traversed ¾ up the
plate. Subsequently, the samples were stored for evaporation, to be utilized in the upcoming week's procedures.
Week 2: Separation of Chromophores by Column Chromatography The procedure began with the combination of 4.0 grams of silica gel and 15 mL of hexane in a beaker. The contents for stirred eliminate air from the silica, and the mixture was set aside for later use. A column assembly involved gently compressing a small cotton piece at its base, securing the column to the workbench, and affixing a funnel on top. Approximately 2–4 mm of
sand was add to the sand and the column was leveled by tapping it gently with a plastic tool. 5 mL of hexane was slowly added using a Pasteur pipette. 15 mL of hexane was added with a collection beaker placed beneath.
Figure 3: TLC plates immersed in hexane filled jar to allow
the pigments to travel up the jar.
Silica gel was loaded into the column by pouring the stationary phase solution with a slow, steady flow, tapping the column to level the gel. Maintaining a
level solvent layer was crucial to prevent drying and potential
damage to the silica gel, which could compromise the separation
process. The hexane was run through the column until it nearly
reached the top of the silica gel. The column was then filled with
hexane, settled, and the process was repeated twice more. Sand
was reintroduced, and the hexane level was carefully drained to
a few millimeters above the sand.
The sample was dissolved in approximately ¾ mL of hexane and added to the column. Additional hexane was added while maintaining the sand's position to maintain the solvent flow. A solution of a 90:10 hexane to acetone mixture was introduced, collecting distinct bands
in separate test tubes. As the column progressed, solvent ratios were adjusted, and bands were collected, particularly focusing on the distinct yellow band. The ratios were altered to 80:20 and 70:30, respectively. The column was stopped after collecting the yellow bands using pure acetone.
During this process, TLC plates were prepared, marked,
and spotted with samples. They were immersed in a 70:30 hexane to acetone solution, and after solvent migration, the test tubes containing bands closest to a single pigment band were photographed, labeled, and stored for the upcoming week's experiment.
Figure 4: Separatory column filtering the sample though the
silica gel.
Figure 5: Separate bands filtered into test tubes after separatory column.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
Why chromatography is an important tool for analysis of organic compounds?
arrow_forward
Use a suitable model to explain how separation and identification of a mixture of organic compounds can be achieved with a thin layer chromatographic (TLC) technique.
arrow_forward
Can paper chromatography be used to separate and identify very volatile substances? Why? Please explain comprehensively.
arrow_forward
Gas Chromatography (GC) is one of the useful techniques in analytical chemistry. Give
two important components in GC.
arrow_forward
What does a refractometer reading of 2 mean when distilling ethanol?
arrow_forward
One method for quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is the area normalization method. In this method, complete elution of all of the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction is accomplished by dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2, and 30.2 in the order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78, and 0.88, respectively
arrow_forward
Analysis of pure molecules
either heterogenous mixture or analysis of pure molecules
neither heterogenous mixture nor analysis of pure molecules
heterogenous mixture
arrow_forward
Which one is the most common method used for the purification of liquid mixtures?
Filtration
Chromatography
Evaporation
Distillation
arrow_forward
Identify the detectors in gas chromatography that can be used for the detection of each type of analyte. More than one
detector may be appropriate for a given analyte, and a given detector may be appropriate for more than one type of analyte.
compounds ionized by
UV radiation
sulfur or nitrogen
containing compounds
halogenated compounds
flame ionization
Answer Bank
mass spectrometer
nitrogen and phosphorous
containing compounds
thermal conductivity
electrolytic conductivity
hydrocarbons
electron capture
thermionic
photoionization
arrow_forward
How else can chromatography be used?
None of these answers are correct.
To wash (or remove) unwanted solvents from a mixture.
To identify or exclude components in a mixture.
To generate IUPAC names for hydrocarbons.
arrow_forward
A young researcher set out to develop a method for quantifying the polycyclic aromatic hydrocarbon (PAH) content in a
contaminated soil sample using open tubular gas chromatography. During the initial stages of method development, the
researcher was unable to separate the early eluting compounds, anthracene and naphthalene, with baseline resolution.
Select the possible modifications the researcher could make to improve the resolution.
use a column with a smaller inner diameter
decrease the column length
increase the stationary phase thickness
increase the temperature
choose a different stationary phase
arrow_forward
One method for the quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is area normalization. Here, complete elution of all the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction involves dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2 and 30.2, in order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78 and 0.88, respectively.
arrow_forward
How does ammonia, dimethylglyoxime (DMG), and 8-hydroxyquinoline (8HQ) interact with your cations, leading to the evolution of colored species?
Context: Paper chromatography experiment (separation of inorganic cations) with a 9:1 acetone/ HCl solvent
arrow_forward
You are an aquatic scientist and tasked to sample water that contains chlorophenols for gas chromatographic analysis from your local waste water treatment plant (WWTP). Using knowledge of sample preparation and chromatograph, how would you sample, preserve and prepare these samples for GC analysis and why GC is the best detection technique?
arrow_forward
Column chromatography is also very useful for separating mixtures of organic compounds that are not coloured. Briefly explain how you could use column chromatography for the separation of a colourless mixture, and how you could identify your separated compounds.
arrow_forward
2. A chromatographic column is eluted with a solution containing a mixture of two
components, X and Y. The chemical affinity of X for the stationary phase is less than
that of Y and the chemical affinity for X for the mobile is greater than that of Y.
Which substance will be eluted first? Explain your answer.
arrow_forward
A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.144.
Assuming that the best fit linear line of the standard curve was y=0.04144x+0.01521 (μgmL), calculate the percent protein by mass in the original protein powder.
arrow_forward
what is chromatography? Explain different types of chromatography and explain how to seperate compounds. indicate stationary phase mobile phase.
arrow_forward
A 0.1 g amine-containing compound is dissolved in water then diluted to 100 mL. To get the concentration of amine in this compound, you subject it to spectroscopic analysis. So, you get 1 mL of the previously diluted sample then dilute it again to 250 mL for measurement. Then, you fill 3/4 of a 1-cm cuvette with this diluted sample then you run an analysis using an AAS. The recorded absorbance is 0.545 at 410 nm. Solve for the molecular weight of the compound. The molar absorptivity is 1.23 x 104 cm-1 mol-1 L.
arrow_forward
A student weighed out 0.150 g of protein powder and dissolved it in 100 mL of water (Solution 1). The student then diluted this solution by transferring 1 mL into a 25 mL flask and diluting with water (Solution 2). Finally, 1 mL of that solution was transferred to a test tube and combined with 4 mL Bradford reagent. The absorbance of the solution in the test tube was 0.187.
Assuming that the best fit linear line of the standard curve was y = 0.04144 x + 0.01521 (μ g mL), calculate the percent protein by mass in the original protein powder.
arrow_forward
19. What is thin layer chromatography (TLC) LEAST
useful for from the list below?
A) To determine if crystallization or distillation may be
more effective for a separation
B) To determine the number of components in a mixture
C) To determine the appropriate solvent for column-
chromatographic separation
D) To monitor the progress of an organic synthesis
reaction
14. The solubility of salicylic acid in water is 7.8g/100ml
at 100°C and 0.25g/100ml at 25°. Estimate how much
water is needed to recrystallize a 19g sample of
salicylic acid?
A) 150ml B) 250ml
C) 300ml D) 400ml
arrow_forward
Lli 5 What is the primary advantage of
temperature program in gas
?chromatography
It improves the detector response O
It facilitates the use of the electron
capture detector
It increases the number of theoretical
plates of the column
It facilitates the analysis of mixtures
of substances with widely differing
vapor pressures
arrow_forward
What are the differences between systematic and random errors and how do they effect accuracy and precision?
In what circumstances would you use standard addition (versus a normal calibration curve) to determine the amount of an analyte in a sample?
A urine sample, containing analyte Z is analysed by the standard addition method where 5 mL of the original sample was mixed with increasing amounts of a Z standard and each solution diluted to a volume of 50 mL prior to analysis. A plot of the final concentration of the standard in each of the 50 mL samples (x axis) versus
The measured signal from the analysis of each 50 mL sample (on y axis) produced a straight line with the general equation:
y = 44.72x + 4.06
what was the final concentration of Z in the 50 mL standard addition sample? what was the initial concentration of Z in the original urine sample?
arrow_forward
Here is the protocol for a UV-Vis spectrophotometer to detect water and chlorine-carbon.
1.Dissolve the water and chlorine-carbon compounds in a solvent, such as water.
2.Prepare a standard solution of known concentration that is similar to the sample being measured.
3.Calibrate the spectrophotometer using the standard solution.
4.Measure the absorbance of the sample using the spectrophotometer.
5.Calculate the concentration of the compounds in the sample using the calibration curve obtained from the standard solution.
How is the spectrophotometer calibrated with standard solutions? When is the blank solution placed in the spectrophotmeter?
arrow_forward
You have obtained a gas chromatogram of a two component mixture of compounds A and B. The height of peak A is 3.84 cm. and the width at half height is 1 cm. The height of peak B is 3.49 cm. and the width at half height is 1.36 cm. The percentage of a component in the mixture is proportional to peak area. Estimate peak areas by multiplying height by width at half height. What was the percentage of compound B in the mixture? (Enter your answer as a number without any percent symbol or the word percent.)
arrow_forward
Explain the following Chromatography (for drug analysis)
Thin-layer chromatography (TLC)
Gas chromatography (GC)
Liquid chromatography (LC) (i.e, high performance liquid chromatography or HPLC)
arrow_forward
Which statement is true?
Statement 1: In Thin Layer Chromatography (TLC), the polar compounds will have a greater Rf value compared to that of non-polar compounds.Statement 2: The stationary phase in TLC is polar.
arrow_forward
One disadvantage of thin layer chromatography is that...
it cannot be used for quantitative measurements.
O it consumes large volumes of solvents
O it cannot analyze volatile samples
it cannot be used to analyze many samples simultaneously
it requires a large amount of sample for analysis
arrow_forward
Chemistry
Briefly describe the differences between the scanning and SIM approaches with reference to your data. Discuss how and why your scanning (TIC) and SIM (mass chromatograms look different. Pay particular attention to selectivity of compounds detected and signal-to-noise. What are some advantages of SIM? What are some disadvantages?
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Related Questions
- Why chromatography is an important tool for analysis of organic compounds?arrow_forwardUse a suitable model to explain how separation and identification of a mixture of organic compounds can be achieved with a thin layer chromatographic (TLC) technique.arrow_forwardCan paper chromatography be used to separate and identify very volatile substances? Why? Please explain comprehensively.arrow_forward
- Gas Chromatography (GC) is one of the useful techniques in analytical chemistry. Give two important components in GC.arrow_forwardWhat does a refractometer reading of 2 mean when distilling ethanol?arrow_forwardOne method for quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is the area normalization method. In this method, complete elution of all of the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction is accomplished by dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2, and 30.2 in the order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78, and 0.88, respectivelyarrow_forward
- Analysis of pure molecules either heterogenous mixture or analysis of pure molecules neither heterogenous mixture nor analysis of pure molecules heterogenous mixturearrow_forwardWhich one is the most common method used for the purification of liquid mixtures? Filtration Chromatography Evaporation Distillationarrow_forwardIdentify the detectors in gas chromatography that can be used for the detection of each type of analyte. More than one detector may be appropriate for a given analyte, and a given detector may be appropriate for more than one type of analyte. compounds ionized by UV radiation sulfur or nitrogen containing compounds halogenated compounds flame ionization Answer Bank mass spectrometer nitrogen and phosphorous containing compounds thermal conductivity electrolytic conductivity hydrocarbons electron capture thermionic photoionizationarrow_forward
- How else can chromatography be used? None of these answers are correct. To wash (or remove) unwanted solvents from a mixture. To identify or exclude components in a mixture. To generate IUPAC names for hydrocarbons.arrow_forwardA young researcher set out to develop a method for quantifying the polycyclic aromatic hydrocarbon (PAH) content in a contaminated soil sample using open tubular gas chromatography. During the initial stages of method development, the researcher was unable to separate the early eluting compounds, anthracene and naphthalene, with baseline resolution. Select the possible modifications the researcher could make to improve the resolution. use a column with a smaller inner diameter decrease the column length increase the stationary phase thickness increase the temperature choose a different stationary phasearrow_forwardOne method for the quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is area normalization. Here, complete elution of all the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction involves dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2 and 30.2, in order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78 and 0.88, respectively.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you