Krieger.Jackson.AspirinSynthesisCrystallizationandCharacterizationDLR.docx
pdf
keyboard_arrow_up
School
Case Western Reserve University *
*We aren’t endorsed by this school
Course
113
Subject
Chemistry
Date
Apr 3, 2024
Type
Pages
4
Uploaded by ConstableWildcat3533
CHEM113
Sturtz
Aspirin Synthesis, Recrystallization and Characterization
D
IGITAL
L
ABORATORY
R
EPORT PREPARED BY
:
J
ACKSON
K
RIEGER
D
ATE
:
F
EBRUARY
27
TH
, 2024
L
AB
R
OOM
:
M
ILLIS
210
S
ECTION
: T
UES
/4:15
PM
TA:
M
D
S
IRAJUL
I
SLAM
Procedure
- Must be in third person, past tense, passive voice, and paragraph format.
A 150mL beaker (reaction beaker) was taken to the balance room and after 2.8936g of salicylic
was measured on a piece of weighing paper, the salicylic acid was transferred into the reaction beaker.
This mass was recorded. A 10mL graduated cylinder was used to obtain 9.55mL of acetic anhydride and a
watch glass was used to cover the graduated cylinder to prevent the spread of acetic anhydride fumes.
This volume was recorded. Inside the hood, the acetic acid was added to the reaction beaker along with 15
drops of 85% phosphoric acid. The magnetic stir bar was put in the reaction beaker and the reaction
beaker was placed on the hot/stir plate. While the stir setting was set to around 100, the temperature
displayed on the hot plate was slowly increased from 60-250
℃
and turned off immediately when the
solution started to bubble. After taking the reaction beaker off the hot plate and letting it cool for
approximately 3 minutes, 45 drops of DI water were slowly added to the reaction beaker. Once the drops
were added, an additional 30mL of DI water was poured into the reaction beaker. The solution was then
swirled. Since the solution stayed clear it didn’t need to be reheated.
While the solution was cooling, crystallization was induced by using a glass stir rod to scratch the
bottom and walls inside of the reaction beaker. A 400mL beaker filled about a third of the way with ice
and enough DI water to cover the ice was used as an ice bath. The reaction beaker was placed in this ice
bath for a total of 15 minutes. However, every 5 minutes the reaction beaker was removed, and the glass
stir rod was used to gently scratch the inside of the reaction beaker. During the waiting period, the
vacuum filtration apparatus was prepared.
A second ice bath identical to the first one was prepared. Then a 150mL beaker was filled with
approximately 100mL of DI water and placed inside the new ice bath. With the clamp in the hood, a
filtration flask was secured before being connected from its side arm to the water aspirator with a rubber
tube. A Büchner funnel was then placed on the top of the flask, with a seal being created by a vacuum
adapter. After, the contraption was set up, a piece of filter paper was placed in the funnel and then wet
with DI water. The water aspirator was turned to full, and the suction through the funnel was tested. Once
the reaction beaker had been in the ice bath for 15 minutes, the reaction mixture was slowly poured into
the funnel. This caused the liquid to pass through and the solid to stay up top. The solid that was stuck in
the reaction beaker was scrapped out using a spatula. When all of the reaction mixture was transferred, the
aspirin crystals were washed with approximately 10mL of the chilled DI water from the second ice bath.
After 5 minutes this was repeated. During this time, the crystals were periodically moved around using
the spatula to ensure the liquid was removed. The crystals were then left to dry by leaving the water
aspirator on for 10 minutes. When the 10 minutes were up, the water aspirator was turned off.
The dried aspirin crystals were transferred to a watch glass and spread evenly. Then the watch
glass was placed in the oven for 20 minutes. During this time, a six-dram vial (without the lid on) was
weighed at 18.1846g and this mass was recorded. Once the aspirin was out of the oven, a piece of weigh
paper was used to transfer the crystals into the vial. The weight of the vial with the aspirin was 21.9260g
meaning the aspirin weighed 3.7414g. Both of these values were recorded. The theoretical yield, limiting
reagent, and percent yield were calculated using the provided equations.
A melting point tube was stuck in the crude aspirin to obtain about 1-2mm of the crude aspirin.
After ensuring that the sample was at the bottom of the tube, it was placed in the Mel-Temp apparatus.
The temperature when the first crystals just started to melt was recorded at 136
℃
and the temperature
when the last crystal disappeared was recorded at 140
℃
. These temperatures produced the melting range
of the crude aspirin produced.
CHEM113
Sturtz
Data Table(s)
- Must be in table form to receive full credit.
Mass of salicylic acid (g)
2.8936
Volume of acetic anhydride (mL)
9.55
Mass of empty vial (g)
18.1846
Mass of vial with aspirin (g)
21.9260
Mass of dry aspirin (g)
3.7414
Sample Calculations
- General equations are shown. Beneath the generic equation, you must show a
sample calculation with your numbers plugged in, then write the calculated value.
Theoretical Yield:
?ℎ?????𝑖??? 𝑦𝑖???
=
????
????????
?
(
) × 1 ???
????????
????? ????
????????
(?)
× ? ???
???????
? ???
????????
× ????? ????
???????
(?)
1 ??? ???????
?ℎ?????𝑖??? 𝑦𝑖???
=
2. 8936? ???𝑖?𝑦?𝑖? ??𝑖? × 1 ??? ???𝑖?𝑦?𝑖? ??𝑖?
138.121? ???𝑖?𝑦?𝑖? ??𝑖?
× 1 ??? ???𝑖?𝑖?
1 ??? ???𝑖?𝑦?𝑖? ??𝑖?
× 180.158? ???𝑖?𝑖?
1 ??? ???𝑖?𝑖?
= 3.7743g aspirin
Percent Yield:
??????? 𝑦𝑖???
= ???? ?? ??????? ????𝑖??? (?)
???? ?? ?ℎ?????𝑖??? 𝑦𝑖??? (?)
× 100
= 99.12%
??????? 𝑦𝑖???
= 3.7414?
3.7743?
× 100
Results
- Must be in table form to receive full credit.
Theoretical yield based on salicylic acid (g)
3.7743
Theoretical yield based on acetic anhydride (g)
18.2
Limiting reagent
salicylic acid
Percent yield (%)
99.12%
Melting Range (
℃
)
136-140
CHEM113
Sturtz
Conclusion Questions
- Must be answered in complete sentences for full credit.
Using ChemDraw draw the full balanced chemical reaction for this experiment. Be sure to include all
sideproducts.
What was your theoretical yield and what was your percent yield?
My theoretical yield using salicylic acid was 3.7743g of aspirin and my theoretical yield using acetic
anhydride was 18.2g of aspirin. Therefore salicylic acid was the limiting reagent and the theoretical yield
of 3.7743g was used in my percent yield calculations. The percent yield was calculated to be 99.12%.
An accurate percent yield must be below 100% Why?
A percent yield that is over 100% means that more product was produced than the reactants should
theoretically be able to produce. This likely, means that the product contains some impurities that it
shouldn’t. This could happen if the product is not pure and there were substances left in the aspirin that
weren’t meant to be left.
What error(s) may have caused a percent yield higher than 100%?
Cooling the reaction beaker too quickly and causing crystallization to occur too quickly could result in a
percent yield higher than 100%. This is because if crystallization happens too quickly, the crystal could
form around substances that aren’t meant to be in the crystal causing impurities. If extra substances were
trapped in the crystallization, the weight of the aspirin could be higher than what it was theoretically
calculated to be. These extra impurities could also have been left in the aspirin if the sample wasn’t
washed enough. Then there could have been extra weight if the aspirin wasn’t completely dry and still
had water in it, increasing its mass.
What did you do in the procedure to try to prevent the error(s) named above?
To prevent these errors, I first let my sample cool down by itself before slowly adding drops of water.
Then once the sample had been cooled down a little already, and water had been added, I placed the
reaction beaker in the ice bath. Immediately placing the sample in the ice bath would’ve cooled down the
sample too quickly. Then when rinsing, I used around 20mL of DI water in total to make sure no
impurities were left over. Finally, the aspirin was placed in the oven for 20 minutes to make sure it was
thoroughly dried.
Explain how differences in solubility are used to purify aspirin in the recrystallization step (
Part II
).
Aspirin is soluble at high temperatures so it is dissolved in the solute. The impurities are also dissolved at
this time. However, at lower temperatures aspirin is not soluble so as the sample was cooled down during
crystallization, the aspirin began to crystalize out of the solution. The soluble impurities still remain
dissolved in the solute. Filtration was then used to separate aspirin from the impurities. Therefore, the
differences in solubility between aspirin and the impurities allowed aspirin to fall out of the solution when
cooled.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
CHEM113
Sturtz
Does your melting point data support your successful synthesis of aspirin? Explain how the data you
collected supports your conclusion.
After looking at an SDS page, I found that the melting point/range of aspirin is 134-136
℃
. My aspirin
had a melting point range of 136-140
℃
. This means that my aspirin is very close to pure aspirin, it just
has a slightly higher melting point with a slightly higher range. This means that my aspirin is pretty close,
but it is not 100% pure and does have some impurities.
Related Documents
Related Questions
Dr. Waybell designs a study to investigate whether the dose of melatonin taken before bed impacts people's moods.
Dr. Waybell rejects Ho and computes 7²=0.05. She has made a Type Il error.
O Dr. Waybell retain reject Ho and computes n=0.005. She has made a Type Il error.
O Dr. Waybell rejects Ho and computes 7=0.005. She has made a Type Il error.
Dr. Waybell retain reject Ho and computes n=0.05. She has made a Type Il error.
arrow_forward
I.
Look at the MS/MS for paracetamol (a drug), explain the peaks seen at 134 and 110, and draw the
structure for the 110 peak.
Paracetamòl N-(4-hydroxyphenyliacetamide
ESI+, MS/MSs
Kky pan_03_c80720211368 1-38 RT: 0.00024 AV 35 N: 107ES
T TMSES F ms 12.00g24 00 0 00-10.0g
100g
110.0
CH
но
70
(M.H]*
162.0
16
1340
130
100
arrow_forward
15c
arrow_forward
LOD
TRANSMITTANCE1%
D
4000
O ketone
Oester
3000
2000
O carboxylic acid
O aldehyde
O alcohol
O nitrile (i.e., RCN)
O None of these other choices is correct.
HAVENUMBERI-I
1500
1000
500
arrow_forward
(iv) H₂0-
M
H₂C
HBr
(2 equiv)
i
CH₂-OH
+ CO₂
19
CH,MgBr
1) n-BuLi
2) D₂0
H₂C=CH₂
arrow_forward
The leaves of the Brazilian Tree Senna multijunga contain a number of pryidine alkaloids that inhibit acetylcholinterinase. Two recentyl isolated isomeric compounds have the strcture have the strcture shown below. (NOTE: M=293) Use the mass spectral data provided to determine the precise location of the hydroxyl group in each isomer.
Isomer A: EI-MS, m/z(rel. int): 222(20), 150(10), 136(25), 123(100)
Isomer B:EI-MS, m/z(re;. int): 236(20), 150(10), 136(25), 123(100)
arrow_forward
Comparison of fingerprint region between literature and experimental spectra.
arrow_forward
TTOn an aipria Gicavago OF CHITTIOccur.
I
I
I
I
I
I
I
Draw Fragment m/z of 87
+
Draw Fragment m/z of 73
1
arrow_forward
Fu_5 -q
aH
A
E1
dihedral
angle (0)
ܠܐ
ܐ
ܢܵܐ
ܠܢ ܒܛܐ ܙ ܐܡܪ .
ܚܐ
H
o
H
B
el
H
14
H
#
n
CI
C
"mw
W
4
H
+
V 120 180 340 300 360
LI
CI
It
#
H
H
H
H
F
H
arrow_forward
X 10 (select) v
molecules of penicillin
arrow_forward
designate the following stretches in the IR of asprin : Csp3-H, Csp2-H, OH of carboxylic acid, C=O of acid, C=O of ester, benzene ring, C-O
arrow_forward
Data:
Nitration of methyl benzoate:
Weight of filler paper: 0.682g
Mp product: 76-77 C
Nitration of Acetanilide:
Weight of filler paper: 0.691g
Weight of filler paper product: 1.232g
Mp product: 212-214 C
Compound
MM (g/mol)
ortho mp (oC)
meta mp (oC)
para mp (oC)
Nitroacetanilide
180.16
94
155
214-217
Methyl nitrobenzoate
181.15
-13
78-80
94-96
Draw all the resonance forms for the arenium ion formed during the nitration of acetanilide.
arrow_forward
Data:
Nitration of methyl benzoate:
Weight of filler paper: 0.682g
Mp product: 76-77 C
Nitration of Acetanilide:
Weight of filler paper: 0.691g
Weight of filler paper product: 1.232g
Mp product: 212-214 C
Compound
MM (g/mol)
ortho mp (oC)
meta mp (oC)
para mp (oC)
Nitroacetanilide
180.16
94
155
214-217
Methyl nitrobenzoate
181.15
-13
78-80
94-96
Based on the table above , determine the regiochemistry of your nitroacetanilide and draw the structure.
Draw all the resonance forms for the arenium ion (cation intermediate) formed during the nitration of methyl benzoate.
arrow_forward
Which one of the following compounds is consistent with the mass spectrum below?
100
80
Relative Intensity
ő
20-
B
SDBS:
0-fttm
MS-NU-0502
10
20
30
A) (CH3CH₂CH2)2CH
C) (CH³CH₂CH₂)2O
40
CH3CH₂CHOHCH₂CH₂CH3
D (CH3CH₂CH₂)2NH
50
60
m/z
70
80
90
100
110
arrow_forward
Identify the peaks for this compound and what functional groups are present
arrow_forward
Identify the fragments of hexanoic acid in the mass spectrum.
arrow_forward
the spectra is of a drug either cannabinoid, opiate, MDMA etc, please explain the spectra and what drug could it be
arrow_forward
All ethyl esters of long-chain aliphatic acids (for example, ethyl tetradecanoate, C13H27COOCH2CH3) show significant fragment ions at m/z 88, 73, and 45.
Draw the structure of the ion that gives the m/z 73 peak.
• In cases where there is more than one answer, just draw one.
• You do not have to include lone pairs in your answer.
• Include all valence radical electrons in your answer.
• Do not use the square brackets tool in your answer.
ChemDoodle
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you

Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Related Questions
- Dr. Waybell designs a study to investigate whether the dose of melatonin taken before bed impacts people's moods. Dr. Waybell rejects Ho and computes 7²=0.05. She has made a Type Il error. O Dr. Waybell retain reject Ho and computes n=0.005. She has made a Type Il error. O Dr. Waybell rejects Ho and computes 7=0.005. She has made a Type Il error. Dr. Waybell retain reject Ho and computes n=0.05. She has made a Type Il error.arrow_forwardI. Look at the MS/MS for paracetamol (a drug), explain the peaks seen at 134 and 110, and draw the structure for the 110 peak. Paracetamòl N-(4-hydroxyphenyliacetamide ESI+, MS/MSs Kky pan_03_c80720211368 1-38 RT: 0.00024 AV 35 N: 107ES T TMSES F ms 12.00g24 00 0 00-10.0g 100g 110.0 CH но 70 (M.H]* 162.0 16 1340 130 100arrow_forward15carrow_forward
- LOD TRANSMITTANCE1% D 4000 O ketone Oester 3000 2000 O carboxylic acid O aldehyde O alcohol O nitrile (i.e., RCN) O None of these other choices is correct. HAVENUMBERI-I 1500 1000 500arrow_forward(iv) H₂0- M H₂C HBr (2 equiv) i CH₂-OH + CO₂ 19 CH,MgBr 1) n-BuLi 2) D₂0 H₂C=CH₂arrow_forwardThe leaves of the Brazilian Tree Senna multijunga contain a number of pryidine alkaloids that inhibit acetylcholinterinase. Two recentyl isolated isomeric compounds have the strcture have the strcture shown below. (NOTE: M=293) Use the mass spectral data provided to determine the precise location of the hydroxyl group in each isomer. Isomer A: EI-MS, m/z(rel. int): 222(20), 150(10), 136(25), 123(100) Isomer B:EI-MS, m/z(re;. int): 236(20), 150(10), 136(25), 123(100)arrow_forward
- Comparison of fingerprint region between literature and experimental spectra.arrow_forwardTTOn an aipria Gicavago OF CHITTIOccur. I I I I I I I Draw Fragment m/z of 87 + Draw Fragment m/z of 73 1arrow_forwardFu_5 -q aH A E1 dihedral angle (0) ܠܐ ܐ ܢܵܐ ܠܢ ܒܛܐ ܙ ܐܡܪ . ܚܐ H o H B el H 14 H # n CI C "mw W 4 H + V 120 180 340 300 360 LI CI It # H H H H F Harrow_forward
- X 10 (select) v molecules of penicillinarrow_forwarddesignate the following stretches in the IR of asprin : Csp3-H, Csp2-H, OH of carboxylic acid, C=O of acid, C=O of ester, benzene ring, C-Oarrow_forwardData: Nitration of methyl benzoate: Weight of filler paper: 0.682g Mp product: 76-77 C Nitration of Acetanilide: Weight of filler paper: 0.691g Weight of filler paper product: 1.232g Mp product: 212-214 C Compound MM (g/mol) ortho mp (oC) meta mp (oC) para mp (oC) Nitroacetanilide 180.16 94 155 214-217 Methyl nitrobenzoate 181.15 -13 78-80 94-96 Draw all the resonance forms for the arenium ion formed during the nitration of acetanilide.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning