Lab 1_ Charge to Mass Ratio of the Electron
.pdf
keyboard_arrow_up
School
Toronto Metropolitan University *
*We aren’t endorsed by this school
Course
130
Subject
Electrical Engineering
Date
Feb 20, 2024
Type
Pages
7
Uploaded by ChefCrow20511
Charge to Mass Ratio of the Electron
Bassel Marouni & Joannie Naluz
PCS 130 - Physics II
Section 10
Vladislav Toronov
Fatemeh Lalegani Dezaki
Introduction
A magnetic field is when the surrounding space of a magnet is affected and magnetism is
observed. Uncharged particles do not create a magnetic field, but charged particles do when they
are in motion. Depending on the particle's charge, the magnetic field could have different
properties. The charge-to-mass ratio is the charge divided by the mass of a particle, and so
different particles each have their unique charge-to-mass ratio. That means that scientists could
use the charge-to-mass ratio to identify whether a particle is an electron or a proton. The main
objective of this experiment is to calculate the charge-to-mass ratio of the particle with the
equipment listed below. This will be determined by collecting the motion of the particle in the
magnetic field at different radii and currents.
Procedure
This experiment was conducted using an e/m apparatus; composed of an e/m tube,
Helmholtz coils, a high voltage power supply, a low voltage variable power supply, banana
cables, a wooden cover, and a meter stick. The power supply was turned on, and the voltage was
set to 230V and left running until a circular, green beam formed. While maintaining the voltage,
the current was changed which simultaneously changes the diameter of the circle, both these
values were collected. This process was repeated until ten trials of different diameters were
conducted, and these values are shown in
Table 1.
A scatter plot was created to compare the
variables of the coil current versus the radius of the beam, and a line of best fit was created.
Results and Calculations
The diameter displayed through each change of current was observed by looking at the
measuring stick inside the e/m apparatus (
Table 1)
. The r
2
was dividing the diameter by 2, and
then squaring it as shown below,
2
= 7.56 x 10
(-4)
m
2
(
0.055𝑚
2
)
2
= 7. 5625𝑥10
(−4)
𝑚
The magnetic field, B, was determined by using the equation,
8µ𝑁𝐼
𝑎 125
Where μ
0
is 4π x 10
-7
(resistance around a magnetic field),
N
is 130 (number of coil turns),
I
is
the current (in Amperes), and a is 0.1525 (the average radius of every coil). A sample calculation
for the first trial is shown below,
=
=
= 1.76 x 10
-3
T
8µ𝑁𝐼
𝑎 125
8𝑥(4π 𝑥 10
−7
)𝑥130𝑥2.30
𝑎 125
3.005873312𝑥10
−3
1.705001833
Ten trials were performed and data was collected, this can be seen in
Table 1.1
.
Current (A)
Diameter (m)
r
2
(m
2
)
B (T)
1
𝐵
2
2.30
0.055
7. 5625𝑥10
−4
1.76769 x 10
-3
321742.4433
2.18
0.059
8.7025 x 10
-4
1.67546564 x
10
-3
358138.5247
2.11
0.060
9.00 x 10
-4
1.621666292 x
10
-3
382295.4392
1.97
0.065
1.05625 x 10
-3
1.514067581 x
10
-3
438562.5821
1.86
0.070
1.225 x 10
-3
1.429525736 x
10
-3
491969.4545
1.73
0.075
1.40625 x 10
-3
1.320612647 x
10
-3
568685.0629
1.63
0.080
1.60 x 10
-3
1.252756425 x
10
-3
640602.7795
1.55
0.085
1.80625 x 10
-3
1.152843335 x
10
-3
708436.0145
1.46
0.090
2.025 x 10
-3
1.122100847 x
10
-3
798469.4712
1.31
0.095
2.25625 x 10
-3
1.006816513 x
10
-3
991793.9076
Table 1 - Data Collected on Particle’s Properties as Current Change
s
It was observed that as the current and the radius were inversely proportional, meaning
that as the current increased, the radius of the beam decreased. This was the major tell that the
observed particle was not a proton, since proton current and proton radius are proportional. For a
proton, if the current was increased, then the radius of the beam would increase with it as well.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Questions
Quantity that is not affected by magnetic field is
Current flowing in conductor
Moving charge
Stationary charge
None of the choices
arrow_forward
Please see the attached image.
arrow_forward
Explain the following.
A. Magnetic Field Strength
B. Boundary Conditions
arrow_forward
(3.4)The length of a magnetic circuit in a moving iron instrument is 300mm. The coil around the soft-iron
core has 360 turns and takes a current of 1.75 A. The core is square in section with sides of 20 mm. Take
the relative permeability of soft iron as 1100.
3.4.1) Determine the magnetomotive force in the core
3.4.2)Determine the field strength
3.4.3) Determine the total flux
arrow_forward
Two long parallel wires are
4 cm apart and carry
Currents Of 2.A and A in the same direction
a) Solve for the magnetic field
b) Compute the force between the wires per
meter of wire length
arrow_forward
compute the reluctance of the magnetic circuit
arrow_forward
Pls. refer to the answer below and write the solution neatly.
Thankyou!
arrow_forward
Answer 5
arrow_forward
The magmatic flux density within a har of some material of 0.630 Tesla at an H field of 5*10 compute the following for this material a-the magnetic permeability and the magnetic susceptibility
arrow_forward
In a coil with radius of 6 cm and 400 turns, there is a magnetic field leaving in a direction
perpendicular to the area of the turn with a value of de 0.232t + 4x10-5t4. The
resistance of the coil is 100 2. Find the EMF after 10 s.
arrow_forward
A magnetic core in the form of a closed circular ring has a mean length of 30 cm and a cross sectional area of 1 sq cm. Determine the reluctance if the relative permeability of iron is 2400
arrow_forward
7) A square magnetic core has a mean path length of 55 cm and a cross-
sectional area of 150 cm². A 200-turn coil of wire carrying a current of
0.316 A is wrapped around one leg of the core. What is the magnetomotive
force created by the system?
arrow_forward
5) ) The point charge at the bottom of the figure is, Q = 17 nC and the curve is
a circular arc, of radius r = 5 cm. What is the magnitude of the force on the
charge Q due to the other point charges shown?
-6.0 nC
2.0 nC
2.0 nC
45° 45°
5.0 cm
5.0 cm
+)
Explain or Show Work Here:
arrow_forward
What is a magnetic field? a) it is the space araund a magnet, or the space in whic magnetic forces act, b) it is the magnetic force which has definite direction at all points along a curved line from the north to south pole, c) it is the ability of a magnetic material to be magnetized easily, d) none of above
Wihch of the following true with regards to magnetic materials. A) like polarities repel, B) unlike polarities attract, C) both a and b, D) none
According to weber is theory of magnetism, a magnetic material_____. A) consust of one large single magnetic molecule, B) is made up from many tiny magnetic molecules, C) consist of one single nonmagnetic molecule, D) none
arrow_forward
1Electromechanics
arrow_forward
A small, square loop carries a 46 A current. The on-axis magnetic field strength 49 cm from the loop is 6.2 nT .
What is the edge length of the square?
Express your answer to two significant figures and include the appropriate units.
arrow_forward
help me provide a picture of a device that is used everyday with the concept of this image. And explain the mechanism and principles of the device's operation
arrow_forward
An electron starts from rest. There are two charged plates, 12 cm apart, which an electric field strength of 175 N/C, that accelerate an electron into a magnetic field, which has a field strength of 0.260T (refer to the diagram below)
(a) What is the speed of the electron as it leaves the plates/ enters the magnetic field
(b) What is the magnetic force acting on the electron when it is in the magnetic field
(c) What is the radius of the path the electron takes in the magnetic field (Draw the path the electron takes/ state initial direction of turn)
arrow_forward
a. The unit of field intensity is
B. coulomb/m?
newtons/m?
A. coulomb
C. newtons/coulomb D.
b. Coulomb's law for the force between electric charges most closely resembles
with
A. Gauss theorem
C. Law of conservation of energy
B. Newton's law of gravitation
D. Newton's laws of motion
C. A region around a stationary electric charge has
B. magnetic field
D. neither of the two
A. electric field
C. both electric and magnetic field
arrow_forward
Please answer all subpart either dislike is ready..
Please both subpart in short for like..
arrow_forward
Question 3.4
(3.4)The length of a magnetic circuit in a moving iron instrument is 300mm. The coil around the soft-ironcore has 360 turns and takes a current of 1.75 A. The core is square in section with sides of 20 mm. Takethe relative permeability of soft iron as 1100.
3.4.1) Determine the magnetomotive force in the core
3.4.2)Determine the field strength
3.4.3) Determine the total flux
arrow_forward
Multiple choice
arrow_forward
An electromagnet shown below has a cross section area of 10 cm2 with a mean length of iron path of 100cm
and mean length of airgap is 0.4cm . It is excited by a coil of 1000 turns of conductor windings. When a current
of 1A is provided to the coil and the relative permeability of iron is 1300, then find the magnetic flux in the
circuit.
Select one:
Oa. 1.25Wb
O b. None of these
Oc.0.00027Wb
O d. 027W.
arrow_forward
The applied MMF to a simple magnetic circuit is 350AT. It was found that the resulting magnetic field denstiy is 0.7 Wb/m2. The average length of this magnetic circuit is 1.64ft and its cross-sectional area is 4cm². What is the relative permeability of the magnetic material of the core?
arrow_forward
A magnet has a north and a south pole which are linked through a
magnetic field force. Draw a diagram to illustrate the fields when:
i)
A single magnet is involved
ii)
When two magnets are next to each other with the opposite poles
aligned
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning
Related Questions
- (3.4)The length of a magnetic circuit in a moving iron instrument is 300mm. The coil around the soft-iron core has 360 turns and takes a current of 1.75 A. The core is square in section with sides of 20 mm. Take the relative permeability of soft iron as 1100. 3.4.1) Determine the magnetomotive force in the core 3.4.2)Determine the field strength 3.4.3) Determine the total fluxarrow_forwardTwo long parallel wires are 4 cm apart and carry Currents Of 2.A and A in the same direction a) Solve for the magnetic field b) Compute the force between the wires per meter of wire lengtharrow_forwardcompute the reluctance of the magnetic circuitarrow_forward
- Pls. refer to the answer below and write the solution neatly. Thankyou!arrow_forwardAnswer 5arrow_forwardThe magmatic flux density within a har of some material of 0.630 Tesla at an H field of 5*10 compute the following for this material a-the magnetic permeability and the magnetic susceptibilityarrow_forward
- In a coil with radius of 6 cm and 400 turns, there is a magnetic field leaving in a direction perpendicular to the area of the turn with a value of de 0.232t + 4x10-5t4. The resistance of the coil is 100 2. Find the EMF after 10 s.arrow_forwardA magnetic core in the form of a closed circular ring has a mean length of 30 cm and a cross sectional area of 1 sq cm. Determine the reluctance if the relative permeability of iron is 2400arrow_forward7) A square magnetic core has a mean path length of 55 cm and a cross- sectional area of 150 cm². A 200-turn coil of wire carrying a current of 0.316 A is wrapped around one leg of the core. What is the magnetomotive force created by the system?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage Learning
Electricity for Refrigeration, Heating, and Air C...
Mechanical Engineering
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Cengage Learning