PHY 132 - DC Circuits worksheet

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Arizona State University *

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132

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Electrical Engineering

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Dec 6, 2023

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1 D C C I R C U I T S – W O R K S H E E T Name: Andrew Crist Partners: Hunter, Nahom, Zainab TA: Rekha Joshi DATA & ANALYSIS Part 1 – Resistance • ࠵? ! (DMM): 20.1 (Ω) red-black-black • ࠵? " (DMM): 325.8 (Ω) orange-orange • ࠵? # (DMM): 216.2 (Ω) red-red Configuration Calculated Resistance (show your work) Measured Resistance R1+R2+R3 = 20.1+325.8+216.2 = 562.1 ohms 561.8 ohms R1+(1/((1/R2)+(1/R3))) = (20.1)+(1/((1/325.8)+(1/216.2))) = 150.06 ohms 150.0 ohms 1/((1/(R1+R2))+(1/R3)) = 133.04 ohms 130.1 ohms 1/((1/R1)+(1/R2)+(1/R3)) = 17.41 ohms 17.5 ohms Clean-up/sign-out (3): Data (25) & Graph (15): Analysis (30): Post Lab Qs (15): Lab Report Total (88):

2 Part 2 – Simple Circuits with Resistors Single Resistor (R 1 ) ࠵? = 1.298 (unit: V ) ࠵? = 59.15 (unit: mA ) ࠵? $%&$’&%()* = 21.944 (unit: ohms ) % difference compared to ࠵? ! (DMM) = 8.771% Two Resistors (R 1 +R 2 ) in Series ࠵? ! = .079 (unit: V) ࠵? ! = 3.94 (unit: mA) ࠵? !,$%&$’&%()* = 20.05 (unit: ohms) % difference compared to ࠵? ! (DMM) = 0.249% ࠵? " = 1.289 (unit: V) ࠵? " = 3.95 (unit: mA) ࠵? ",$%&$’&%()* = 327.16 (unit: ohms) % difference compared to ࠵? " (DMM) = 0.417% Two Resistors (R 1 +R 2 ) in Parallel ࠵? ! = 1.281 (unit: V) ࠵? ! = 59.08 (unit: mA) ࠵? !,$%&$’&%()* = 21.68 (unit: ohms) % difference compared to ࠵? ! (DMM) = 7.56% ࠵? " = 1.281 (unit: V) ࠵? " = 3.91 (unit: mA) ࠵? ",$%&$’&%()* = 327.62 (unit: ohms) % difference compared to ࠵? " (DMM) = 0.557% Calculations R=V/I R=(1.298)/(59.15x10^-3) = 21.944 ohms Percent Difference = (21.944-20.1)/(avg 21.944 and 20.1) * 100 = 8.771% Calculations R1 = (.079)/(3.94x10^-3) = 20.05 R2 = (1.289)/(3.95x10^-3) = 327.16 Percent Difference = (20.05-20.1)/(avg 20.05 and 20.1) * 100 = .249%, use 327.16 and 325.8 for R2 = .417% Calculations R1 = (1.281)/(59.08x10^-3) = 21.68 R2 = (1.281)/(59.08x10^-3) = 327.62 Percent Difference = (21.68-20.1)/(avg of 21.68 and 20.1) * 100 = 7.56%, use 327.62 and 325.8 for R2 = 0.557%

3 Part 3 – Power Draw from a Non-Ideal EMF r (measured with DMM) = 214.9 (unit: ohms) Fit parameter A = .03059 (unit: W) Fit parameter B = 214.8 (unit: ohms) ࠵? (Ω) 5 10 20 40 80 160 320 640 1280 ࠵? (A) .02396 .02342 .02243 .02066 .01787 .01408 .00990 .00619 .00355 ࠵? (V) .122 .229 .429 .785 1.350 2.120 2.970 3.724 4.262

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4 POST LAB QUESTIONS 1) (10 pts) Solve Eq. (8). Take the derivative and solve for ࠵? in terms of ࠵? . Show your work. Attach a separate page if needed. 2) (5 pts) How does the load resistor value that maximizes the power compare to the internal resistance? Does this agree with your result from Part 3? We measured the resistor at 214.9 ohms, and our graph yielded a load resistance value of 214.8 ohms at maximum power. With a difference of .1 ohms, our graph value very closely matches the real known value of our resistor. All of our data aligns throughout and agrees with the other results.