ET 210 Quiz 4

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CUNY Queensborough Community College *

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210

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Electrical Engineering

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Apr 3, 2024

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docx

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ET 210 Quiz 4 1) Given the circuit drawn below, containing a Zener diode along with the other components shown: Find the following ( only in parts a through e , the Load Resistance RL = 160 Ω ): a) Load Voltage V L=5.1V b) Load Current I L=31.8 mA c) Current I Rs (which is the current through resistor R S )= 55.18 mA d) Zener Diode Current I Z=23.38 mA e) Zener Diode power dissipation P Z=119.23 mW f ) Assume that the Load Resistance is changed to RL = 70 Ω and find the new values of: V L = 4.11 V I L = 58.8 mA I Rs = 58.8 mA I Z = 0 A g ) Assume that the Load Resistance is now RL = 120 Ω and the power rating of the Zener diode is P Z (max specified) = 400 mW Now also assume that the input voltage Vin is a variable quantity ( V in is not 20 V in this part g ). Find the minimum input voltage V in (min) at which regulation will still be maintained = And: Find the maximum input voltage V in (max) before the Zener diode is damaged. (That is, you will determine the range of input voltages from minimum to maximum where the circuit will regulate properly (maintain constant output Load voltage based on the Zener diode) and the Zener diode will be not be damaged).
RL = 120Ω IZMAX= PzMAX / Vz = 400mW/5.1V = 78.43mA IRSMAX= IZMAX + IL = 78.43mA + 42.5mA = 120.93mA IL = 5.1V/120 Ω = 42.5mA The quiz is continued on the next page . 2) Given the circuit drawn below, containing a Zener diode along with the other components shown: Find the following: a) Load Voltage V L = VZ = 9.1 V b) Load Current I L = 9.1 V / 75 Ω = 0.121 A c) Current I Rs (which is the current through resistor R S ) IRS = VS - VRS/150 Ω = 36V-9.1V/150 Ω = 0.179A d) Zener Diode Current I Z IZ = IR - IL = 0.179A - 0.121A = 0.0583A = 58.3mA e) Power P Z dissipated in Zener Diode Pz = IZ * VZ = 58.3mA * 9.1V = 0.531W f) Powers P Rs and P RL dissipated in resistors R S and R L respectively. PRL = IL * VL = 0.121 A * 9.1V = 1.101W PRS = IR * VR = IR(Vs - Vz) IR(36-9.1)
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