Drill 5
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University of Central Oklahoma *
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2114
Subject
Electrical Engineering
Date
Apr 3, 2024
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4
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© Add one more victory to Central’s history! © Name: /\ 0 \/\\\'M éC H?M Drill #5, Spring 2023. MWF 9-9:50 -/ / Page 1 of 4 AA cells have an EMF of 1.50 V. When a current of 0.250 A is drawn from the cell, its terminal voltage is measured to be 1.30 V. 1. [5 pts] Sketch cell, including the EMEF, the current, and the internal resistance. r-“u’ 2. What is the internal resistance of the AA cell? Identify Variables and Constants. Write “?” if the value is initially unknown. Required. Symbol Description Value Units VU/EMF = Electromotive force of AA cell = 1.50 v K = Terminal voltage of AA cell Y= 1.30 v T = Current drawn from AA cell = 0.250 A R = Internal resistance of AA cell = ? Q Accepted Equations [3 pts] Show your work here. Keep the units at each step! [5 pts] U= TR /U; - @/gmgf - Kin: T Q\;‘* - Uerr —;JT/I ALy - 0.y Symbol Value Units Final answer. [2 pts] K. = 0.¢ L+ Q
© Add one more victory to Central's history! © Name: Drill #5, Spring 2023. MWEF 9-9:50 Page 2 of 4 Paul Peter Jingleheimer-Schmidt is installing a lightning rod on the side of his house. The lightning rod is 7.29 m long and has a circular cross-section with a radius of 2.00x102 m. The lightning rod is made of stainless steel, which has a resistivity of 69.0x10® Q-m. 3. [5 pts] Sketch the situation described above, showing the radius and length of the rod. PN 4. What is the resistance of the lightning rod? Identify Variables and Constants. Write “?” if the value is initially unknown. Required. Symbol Description Value Units L = Length of lightning rod = 7.29 m = Radius of lightning rod = 2.00x1072 m Fool= Resistivity of stainless steel = 6.90x107 Q'm Q = Resistance of lightning rod = ? Q Accepted Equations [3 pts] Show your work here. Keep the units at each step! [5 pts] - PL AL (Wox 0T em) (T 24 Y s R= & Q- W,%.ooxm' o\ T A= pv = 4.00xIp 3.0 Final 2 pts] Symbol Value Units inal answer. [2 pts , —7 R =1 4000 Q
®© Add one more victory to Central's history! @ Name: Drill #5, Spring 2023. MWEF 9-9:50 Page 3 of 4 A 500-22 resistor is in series with another resistor. The voltage across the combination of resistors is 1.00x10? V. The total power dissipated is 8.00 W. 5. [5 pts] Sketch the two resistors in series and the voltage across the combination. AN 0 VK Y 2 i /\ AAA A 'f\v’\/’\“ —— 7= "b[ 6. What is the resistance of the other resistor? - Identify Variables and Constants. Write “?” if the value is initially unknown. Required. Symbol Description Value Units R, = Resistance of resistor #1 = 5.00x10? Q “\// = Voltage across combination of resistors = 1.00x10? v @ = Total power dissipated = 8.00 W R. |= Resistance of resistor #2 = ? Q Accepted Equations [3 pts] Show your work here. Keep the units at each step! [5 pts] QSU‘\LS N ip\r\ R=vp = QO0XI0" Y /iy = 1230 P-7"JQ ‘Q‘KU.\LS N V\l ) @\’L Q‘l = R - g\ - WS0 9 -S0p S = 700 O Symbol Value Units Final answer. [2 pts] Re =] 2
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® Add one more victory to Central’s history! © Name: Drilt#5, Spring 2023. MWF 9-9:50 Page 4 of 4 A 500-L2 resistor is in parallel with another resistor. The total current through the combination of resistors is 2.00x10* A. The total power dissipated is 8.00 W. 7. [5 pts] Sketch the two resistors in parallel and the total current through the combination. 8. What is the resistance of the other resistor? Identify Variables and Constants. Write “?” if the value is initially k41 Lt v YNV = unknown. Required. Symbol Description Value Units Q\ = Resistance of resistor #1 = 5.00x10? Q Ty | = Current through combination of resistors = 2.00x10™ A 4 = Total power dissipated = 8.00 W R, |= Resistance of resistor #2 = ? Q Accepted Equations [3 pts] Show your work here. Keep the units at each step! [5 pts] @Qum\u - E‘E’T \@::\1@ T~ ’h = LW “/(1.00x\b“ A = 2000 | = t 2{){7)9\ /:S:m__(; n ) el vl Ty ?\1 - (O‘OOBS—’JL 3333% QL Symbol Value Units Final answer. [2 pts] B =] 233.>
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Vdc0
U=12 V
Circuit
#1
Ried
V LED
www
Ried_series
0.05
Vdc0
U = 12 V
0,04
Circuit
0.03
0.02
0.01
RED LED
GREEN LE
Set current to 10 mA
LED voltages
Given the circuit #1 presented above, answer the following
questions:
BLUE_LEC
Red
0.5
1) Determine the value of the V₁ (voltage forward of the LED)
for the LEDS RED, VDRED GREEN, VREEN and BLUE, VOBLUES
when the current through the LEDs is 10mA,
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lighting up or not - Justify your answer
Green
3) Calculate the value of the resistance Rled in Circuit #1, to
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1.5 2 25
Voltage across LED (V)
4) Calculate the value of the resistance Rled in Circuit #1, to
ensure that a GREEN LED will have a current of 10 mA
Blue
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6) Given three LEDs, connected in series as shown in the Circui
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Choose the correct answer
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please see attachment, thank you
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The principle operation of LVDT is based on the variation of
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View Image
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In the figure below you see the sketches for the front and back of an electrical circuit board. The board is
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inserting the leads from a DC power supply. The legs of the resistors and capacitors go through the holes
on the board and are soldered to the conducting paint on the back side. You also have a multi-meter which
you can use as an ammeter or a voltmeter.
16 v
4700
16
10
8
O-
7
3.
6.
4
O+
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Recommended textbooks for you
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