ET310_Lab2_G00304033

Two batteries are connected in parallel delivering power to a power resistor. The first battery has an open circuit voltage of 12.6 V and an internal resistance of 0.2 ohm. The second battery has an open circuit voltage of 12.2 V and an internal resistance of 0.3 ohm. Find the maximum power delivered to the load resistance.

For a combined circuit digram, what should we do first? what will happen to the resistance? what will happen to the voltage? what will happen to the current? Please give an explanation to a combined circuit diagram.

Please in typing format please ASAP for the like   Please answer the same to

What is the difference between the cut-off voltage VGS0 f and the narrowing voltage Vp? Explain this with the diagram

Subject: CircuitsGivenRt = 37.9529 ohm..Rcd = 3.6 ohm.Rab=2.3529ohmIt=1.58APt=94.85WV2=3.16VV4=6.32VVab=3.7175vVcd=5.688VI10=0.372AI5=0.7435AI8=0.465AI9=0.632AI6=0.348AP2=4.9928WP4=9.9856WPab=5.88WP14=34.95WPcd=8.99WP12=29.96W

Create a circuit and apply kirchhoffs laws

Create five(5) Kirchhoff's Voltage Law (KVL) problem with figure and solve it(Show complete solution)

Units of R1 and R2 are Ohm   Electric Circuits

Can you please do (c)  Calculate the total power consumption of your circuit. I attached a photo of the circuit ect

8 The figure is a graph of . Current Voltage the current across a voltage as a function of the potential difference through it the resistance as a function of the current across a component the current through a component as a function of the voltage across it O All three of the above (a), (b), and (c) are true O None of the above (a), (b), or (c) is true

Create a general procedure to solve any circuit DC circuit with any number of resistors.

Find voltage regulation in typing format please ASAP for the like

PLS PLS SHOW COMPLETE SOLUTION AND WRITE LEGIBLY. DRAW CIRCUIT DIAGRAM. PLS PLSS SHOWS HOW ALL THE EQUATIONS ARE REDUCED TO NEEDED.

A component requires 6.3-V across it with a current of 0.3 V. A second component requires 12.6-V at 0.15A.  The two components are connected in series. What is the value of resistor that must be connected across the 12.6-V component to allow it to operate properly when in series with the 6.3-V component?

MCQ

Ans the following questions.

Now let's try using a pack of AA batteries (1.2 V output voltage and 0.2 Ohm internal resistance each) to replace the lead-acid battery. In order to match the car lead-acid battery, first, 10 such AA batteries need to be connected in series to form a 12V cell, while 50 such cells need to be connected in parallel (as shown in picture above; the total of 500 AA batteries are used). Find the power that is supplied to the same "car starter" using this pack of AA batteries. (Hint: for the second question, you need to find the total voltage and the internal resistance of the whole pack; you also need to find the resistance of the "car starter"; this can be done using the data of the first part of this problem)

180 is the answer amount of ohms needed on the oscilliscope. I need to transpose the equation to solve for R. I must work out an equation that equals 180 ohms R resistance that gives off 50mA of current using the transposed equation. Series impedence ,inductive reactive, phase angle formulas may need to be used. I need to get as close to 180 ohms as possible.

Part A: A multi-range ammeter is required to measure the current in a certain network. A PMMC instrument has connected as an Ayrton shunt with a four resistor across PMMC. The resistance values are R1 = 0.006N, R2 = 0.0650, R3 = 4.00 and R4 =10.00. The PMMC has Rm = 1kQ and FSD = 50µA. %3D %3D a. Draw the circuit for the multi-range Ayrton shunt. b. Calculate the four current ranges of the ammeter. c. What is the main advantage of Ayrton shunt ammeter compared to parallel type. d. Briefly explain how this device can be calibrated. * Note: Show all calculation details. Part B: The measurement of the voltage from a prototype of a 20V DC power supply were captured by 8 times as shown in the following table: Number 1 2 3 4 6 Voltage (V) 18.5 19.8 20.2 19.9 20.0 20.1 19.7 18.9 Determine the following: 1. the arithmetic mean, 2. the standard deviation of the readings, 3. the probable error. 4. If the voltmeter that used to carry the measurements has an error of 0.5%; calculate the total…

For the circuit in Figure: 1) Set up the equation for the upper supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 2) Set up the auxiliary equation for the top supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 3) Set up the equation for the lower supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 4) Set up the auxiliary equation for the lower supermesh. Response format: Ai1 ± Bi2 ± Ci3 ± Di4 = E 5) What is the value of ix in A?

An example of Simple Resistive Circuits is ,

Can you verify experimentally the characteristics of series and parallel circuits? Put it into words.

L VL VR + E An L-R series circuit consists of an inductor with inductance, L, connected in series with a resistor with resistance, R. The resistance, R, is a circuit parameter that opposes the current, I, and causes a drop in potential given by Ohm's Law while inductance, L, is a circuit parameter that opposes a change in current. Both the resistor and inductor cause the total drop in electric potential and is equivalent to the total electromotive force, E, which is produced by a voltage source such as batteries. dl I + R E = L dt As soon as the switch is opened, the current, I, passing through the circuit varies through time, t. In the given differential equation above, the current I and the time t are the dependent and independent variables, respectively. The electromotive force E, the resistance R, and the inductance L are constants. Using A as the constant of integration, find the general solution in explicit form I = f(t). Knowing that there is no current passing through the…

Can solve this with solution and explanation

(II) Explain what happens if the topology is modified as shown in figure below. VREFO- ww Qz

1. Find the current in the resistor (R1) using the principle of superposition in the figure below. jón R -j82 := 10260° V TI=220 A