SERIES AND PARALLEL CIRCUITS LAB

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ECPI University *

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120

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Electrical Engineering

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Jan 9, 2024

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docx

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Name: Thi Huyen Trang Nguyen Date: 12/02/2023 SERIES AND PARALLEL CIRCUITS Introduction In today’s lab, you are going to investigate the characteristics of circuits with resistors in series and circuits with resistors in parallel. To investigate the characteristics, you are going to apply Ohm’s Law. Voltage (V) = Current (I) x Resistance (R) Purposes 1. To determine the equivalent resistance of resistors in series. 2. To determine the equivalent resistance of resistors in parallel. 3. To apply Ohm’s Law to simple circuits. Materials This lab requires you to create simulated circuits using the PhET Circuit Construction Kit Virtual Lab ( be sure you use the HTML5 version, not the Java version ). Part 1: Applying Ohm’s Law to a Simple Circuit Create the following simple circuit using the simulation. The simulation shows electrons flowing from the negative terminal of the battery (black end), through the resistor (light bulb) and the positive terminal (copper colored end). Change the current direction by selecting Conventional Current (in top right box). This shows the direction physicists thought current was flowing before the existence of the electron was discovered. 1

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 Set the voltage and resistance in your circuit using the values in the table below that correspond to the first letter of your last name: First letter of Last Name Voltage Resistance A-C 5 V 5 Ω D-F 6 V 6 Ω G-I 7 V 7 Ω J-L 8 V 8 Ω M-O 9 V 9 Ω P-R 10 V 10 Ω S-U 11 V 11 Ω V-Z 12 V 12 Ω Change the setting on the battery and light bulb by clicking on the component and using the arrows and/or slider at the bottom of the simulation screen. Enter the values you are using in the table below: Voltage Resistance Current 9 V 9 Ω 1 A Using your assigned values of voltage (V) and resistance (R), use Ohm’s Law to calculate the current to demonstrate that the ammeter reading is correct. 9V/9Ohms = 1A Result of this calculation = 1 A Now double the voltage. Indicate the new values in the circuit in the following table: Voltage Resistance Current 18 V 9 Ω 2 A So when the voltage is doubled, the current is (put an X next to your choice) a ½ of what it was. b ¼ of what it was. c 4 times what it was. X d 2 times what it was. Do not change the voltage of the battery from the new value (listed above). Double the resistance. Indicate in the following table the values of the circuit after making the change. Voltage Resistance Current 9 V 18 Ω 0.5 A 2

Name: Thi Huyen Trang Nguyen Date: 12/02/2023 So when the resistance is doubled, the current is (put an X next to your choice) X a ½ of what it was. b ¼ of what it was. c 4 times what it was. d 2 times what it was. For part 2 and 3, set the battery voltage and the resistances in your circuit using the values in the table below that correspond to the first letter of your last name First letter of Last Name Voltage Resistance 1 Resistance 2 A-C 5 V 5 Ω 12Ω D-F 6 V 6 Ω 11Ω G-I 7 V 7 Ω 10Ω J-L 8 V 8 Ω 9Ω M-O 9 V 9 Ω 8Ω P-R 10 V 10 Ω 7Ω S-U 11 V 11 Ω 6Ω V-Z 12 V 12 Ω 5Ω Part 2: Resistors in Series In this part of the lab, you are going to create the following circuit with two resistors in series. . 3

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