ElliottBrooks_Lab5-2

.docx

School

The University of Tennessee, Knoxville *

*We aren’t endorsed by this school

Course

231

Subject

Electrical Engineering

Date

Jan 9, 2024

Type

docx

Pages

Uploaded by DrAntelope309

Name: Elliott Brooks Samantha Reasonover E-mail address: ebrook26@vols.utk.edu Samantha Reasonover Laboratory 5 Report Goal: The goal of this lab is to have the chance to look closer at energy fields. Within these fields several variables work together to promote or deter energy formation. Through this laboratory, we are able to utilze stimulations and compare magnetic fluctuation, velocity, and frequency in their relationship to create energy. Activity 1 ● Briefly describe the three experiments performed in this video clip and explain how they demonstrate Lenz's law. 1) A magnetic horseshoe held a current as an aluminum ring was observed to enter and exit this current. The ring was slow moving through this current and confirms Lenzs’ law is demonstrated here due to the steady rate of movement observed with the ring and current. 2) Here we observed the difference between a pencil and a magnet both dropping from a height, sharing all same variables except that one is magnetic and the other is not. We observed the speed of the pencil to be much faster than that of the magnet due to the charge on the magnet, reacting with the opposing force it is headed toward. Lenz’s law is demonstrated through this experiment due to the oppositional fields at play. 3) Finally it was observedthat a diskj will move quicker with a current produced silently by a magnet that then produced the magnetic field to move the magnet into the air, freely floating. This is in direction relation with Lenz’s law. Exploration 1 ● as you move the magnet through the coils with different number of loops: ● As I moved the magnet through the coils with different numbers of loops, I observed that through both, as the magnet would enter a side the voltage would quickly enter a negative range then coming back through the opposite end, it would bounce into a positive voltage range. This observation was true for each coil experimented with, however, the coil that was longer had a greater range of voltage, meaning it bounced both far into the negative and positive on the meter. The shorter coil, however, reached mid ranges of both bositive and negative, not like the measurement captured from the longer coil. ● as you change the frequency and therefore the speed of the magnet for a given number of loops:

● As the frequency increased, it almost completely stopped the range of voltage. The two coils measured very similarly, not moving hardly any outside the mid-line on the voltage meter. As we ran through the coil quickly for both coils, it would bounce quickly from out of the mid range and then back, as it entered and exited each end of the coil. ● as you change the polarity of the magnet? ● Interestingly, as we changed the polarity of the magnet, putting the south end forward into the coil and the northern end being the first to exit, it produced the exact same results for both coil in voltage measurement, only captring a positive voltage, no negative range was observed to occur. (b) In a transformer, a current in one coil creates a magnetic field. When the flux of this magnetic field through the second coil changes, an induced current flows in the second coil. ● Refer to the image on the right. With a direct current (DC) flowing in the primary coil, predict what will happen as you move the primary coil in and out of the secondary coil. ● I predicted that as the primary coil was moved in and out of the secondary coil, we would see a lot of electron movement and a high range recorded from the voltage meter. Curious if my prediction would be correct, I performed the stimulation and saw a small amount of electron movement and a strong range of velocity as the frequency was slow and steady, however, as the frequency increased, the velocity decreased. ● Refer to the image on the right. With an alternating current (AC) flowing in the primary coil do you have to move the primary to light up the bulb? Why or why not? ● With the alternating current flowing within or primary coil, we do not have to move the primary to light up the lightbulb used here to measure the current. With movement, it only increases the brightness of the bulb as the primary coil with the AC moves closer. As it moves far away, the bulb only gets dimmer. This is due to the direct current moving this energy in only one direction, with the alternating current we are moving the direction of the current both ways periodically. I believe the light stays on even without us moving the coil because the alternating current has less energy loss than the direct since it is constantly moving in either direction. ● Refer to the image on the right. Describe how this simple model for the generators in a hydroelectric plant works. ● The generator in an hydroelectric plant works by using the force of the liquid expelled onto the generator shaft to create electric energy from the physical, mech energy that is spinning the shaft. On our stimulation, the generator shaft has a magnet on it, so I wonder in changing the polarityof the

mechanical energy, how this might affect the electrical energy produced. The more fluid released onto the shaft, the greater the mechanical and electrical energy created and the less fluid released, the less mechanical and electrical energy made. ● Imagine you were actually turning the magnet by hand to generate a current. Neglecting friction, would you have to do work to keep the wheel turning? ● Yes work must be done to keep the wheel turning. As I said before the fluid released is physically moving the shaft to promote mechanical energy. Physical work must always be done to create mechanical energy, which in turns creates electrical, useful, energy. Exploration 2 ● Before you close the switch, predict the voltage across the switch and the current through the bulb. Record your prediction. ● Before closing the switch, I predicted that the voltage across the switch would be in the -70 V range. I also predicted the current, and thought it would measure to be 0 A. ● After you close the switch, predict the voltage across the switch and the current through the bulb. Record your prediction. ● After closing the switch, I predicted that the voltage across the switch would be 0 V with a closed circuit. I also predicted the current, and thought it would measure to be just a little over 0 A, but probably not over 1 A. ● Does the animation support your predictions? Adjust the scales on the chart recorders appropriately. ● Yes! The animation validated my predictions. I thought with an open switch, the velocity would be in the -70 range and the measure value through our stimulation recorded the velocity to be -75 V. After closing the switch, I was also correct in that the velocity would increase to reach to reach 0 V. I thought that the current, with the switch open would record to be 0 A. After closing the switch, I was again correct believing that the value would be above 0 and below 1A, the recorded value proved to be 0.5 A. ● Flip the switch a few times. How long does it take for the current through the bulb and the voltage across the switch to change after

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Related Questions

. What is the purpose of a discharge device used in conjunction with opening a highly inductive circuit?a) to minimize the possibility of damage to the circuits insulation as a result of a high induced voltage b) to minimize the possibility of endangering the life of the person opening the controlling switch c) to allow the magnetic field to gradually collapse, thus limiting the value of the self-induced ernf d) all of the above

PLEASE ANSWER IT ASAP FOR AN UPVOTE. THANK YOU. Round off your answer into four decimal places .Box your final answer .Use SI unit. A magnetic circuit consist of silicon having a cross section of 1.5 sq. m and 0.1 m length and an air gap of the same cross section and pf 0.02 m length. what is the field intensity at the air gap if 0.5 A current flows through the 5000-turns coil? Assume the permeability of silicon steel is 3000.

Moving to another question will save this response. Question 6 Electric field terminates at.. Neither positive nor negative Positive charge Negative charge Both positive and negative A Moving to another question will save this response.

Pls. refer to the answer below and write the solution neatly. Thankyou!

I need in 30 minutes please help

Please answer it in 30 mins. thank youu write your soln neat and complte

A magnetic circuit consists of silicon steel 2,500 permeability, of 10 cm length and a cross section of 1.5 sq. cm and an air gap of the same cross section and of 2 cm length. A 1/2 ampere current flows through the 5,100-turn coil. What is the field intensity at the air gap? draw the diagram

Show complete and step by step solution. It is basic electrical engineering subj.

In any circuit that includes inductance, current: Select one: is a result of the changing magnetic field. must flow before any voltage can be induced. depends only on relative motion, not applied voltage. lags behind voltage.

17. What type of device consists of a coil with a moveable iron core.. 18. What will happen when an inductor's magnetic field collapses the voltage will? 19. What is the inductance of 5H and 100 milli H coil connected in parallel. 20. It is the magnetic field generated around a conductor when a current passes through it.

....

Electric field terminates at. Both positive and negative Positive charge Negative charge Neither positive nor negative

Please answer it ASAP for an upvote. Thank you.

Within magnetic circuits, most of the structures are composed of a high-quality material permeability, which has the functionality to cause the magnetic flux to be directed to paths" Pre" delimited by this material structure. Within the electromechanical energy conversion processesw e find the application of magnetic materials in a multitude of devices and devices, and knowt he concepts that govern the operation of an apparatus or machine are part of the study regarding conversione lectromechanical energy. We know that transformers and electrical machines use materialsf erromagnetics to direct the magnetic flux and shape this “pre-established” magnetic field.K nowing this, you, engineer (a), should design a magnetic circuit consisting of a stack of ringsw ith a height of 2 cm wrapped around 65 turns. Consider an air gap area of 0.2 cm. Rings have radiusi nternal of 3.4 cm and the outer radius of couples rings is 4 cm. Suppose the magnetic flux present without materialf erromagnetic…

An iron core 0.4 m long and 5 cm^2 is wound with 300 turns. When a current of 0.5A flows in the coil, how much is the inductance of the coil. Assume the core has a permeability of 2500.

solve

A moving coil mili voltmeter has a resistance of 20 ohm and full scale deflection of 120 degrees is reaches when the p.d of 100V is applied across it's terminals. The moving coil has effective dimensions of 3.1cm x2.6cm and wound with 120 turns. The flux density in the air gap is 0.15 Weber per meter squared. Determine the control constant of the spring and suitable diameter of copper wire for a coil winding if 55% of the total instrument resistance is due to coil winding given resistivity of 1.73*10-8 ohm meter

: Explain briefly various theories of breakdown in liquid dielectrics

I will rate if solution will be correct

A magnetic flux density of 2.5 sin314t Tesla from the core with a cross section of 40 cm2 wandering. Accordingly, in 200 sipir and 45 sipir coils wrapped on the core Find the voltage that will occur.

4. If the Core of an Electromagnet is made of Permalloy (check the Tables for Relative Permeability) and has a 250 turn coil. The cross section has dimensions of 3 cm by 4.5 cm, and the average path length is 10 cm. Determine the amount of Flux that will be developed when a Current of 350 mA flow in the coil.

Please see the attached image.

A moving coil voltmeter with a resistance of 200 gives a full scale deflection of 120 degree, when a potential difference of 100mV is applied across it. The moving coil has dimension of 30mm*25mm and is wounded with 100 turns. The control spring constant is 0.375 *10-6N- m/ degree. Find the flux density, in the air gap. The specific resistance for copper=1.7* 10-80m . 0.13 0.22 0.15 0.12 0.2 wb/m2 wb/m2 wb/m2 wb/m2 wb/r flux density

6. Peak to peak ripple is defined as a) the difference between zero voltage and maximum b) the difference between average dc voltage and peak value c) the difference between maximum and minimum dc voltage d) the difference between maximum ac and average de voltages e) the difference between ac (rms) and average dc voltages f) none of above 7. a belt speed of 1.5 m/s, charge density of 12 µc/m2 and a belt width 2 m. The maximum charging current is: a ) 45 μΑ b) 50 μΑ c) 72 µA d) 81 µA e) 115μA f) None of above 8. In a Cockroft-Walton circuit, input voltage 100 kV load current 25 mA, supply frequency 100 Hz, each capacitor 10 nF. The optimum no. of stages for maximum output voltage is а) 1 b) 2 c) 10 d) 35 е) 45 f) None of above 9. If D is the diameter of the sphere, for better measurements, the gaps 'S' should be such that, a) 0.05 D

A resistance of the coil is 500 and the number of turns 200 turns, connecting in a row with a resistive galvanometer 3000, and placed in the magnetic field amount of 2 mWb. Find the value of current in the coil when moving during 0.2 sec to 0.6 mWb.
Answer the following questions below with 2-3 sentences: 1. How Piezoelectric Effect Works? 2. What is piezoelectricity used for? 3. Energy harvesting with piezoelectricity? 4. What is Piezoelectricity Harvesting
The magmatic flux density within a har of some material of 0.630 Tesla at an H field of 5*10 compute the following for this material a-the magnetic permeability and the magnetic susceptibility
Please answer all parts of the question with step by step working and explanantions so i understand the questions and solution better thank you.
Explain the following. A. Magnetic Field Strength B. Boundary Conditions

~~SEE MORE QUESTIONS~~

~~Recommended textbooks for you~~

Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON

Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning

Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education

Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education

Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON

Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,

~~SEE MORE TEXTBOOKS~~

~~Related Questions~~