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EEE20001

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Oct 30, 2023

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Digital Electronics - Tutorial 4 of 46 Tutorial 2 Solution Q1) Not provided. (Trivial I hope) Q2) Similar to Lecture example – OR gate Q3) a) LSTTL->HC Voh = 2.4 < Vih = 3.14 – broken, Vol=0.4 < Vil = 1.35 – OK Q3) b) LSTTL->HCT Voh = 2.4 > Vih = 2.0 – OK, Vol=0.4 < Vil = 0.8 – OK Q3) c) HC->LSTTL Voh = 3.84 > Vih = 2.0 – OK, Vol=0.33 < Vil = 0.8 – OK Q3) d) HCT->LSTTL Voh = 3.84 > Vih = 2.0 –OK, Vol=0.33 < Vil = 0.8 – OK Q4) F(A,B,C,D) = BD’ + B’CD + ABC + ABC’D + B’D’ SOP F(ABCD) = D’ + AB + B’C AC is not required. Q5a) f(a,b,c) = m 0 +m 2 +m 5 +m 6 F(abc) = a’c’+b.c’+a.b’.c Q5b) f(d,e,f) = Σ m(0,1,2,4) F(def) = d’e’+d’.f’+e’.f’ Q5c) f(r,s,t) = rt’+r’s’+r’s F(rst) = t’+r’ Q5d) f(x,y,z) = M 0 M 5 F(xyz) = y + xz’ + x’z 1 1 1 1 1 1 1 1 1 1 1 1 A B 01 11 10 10 11 01 00 C D 00 1 1 1 1 a b 01 11 10 1 0 c 00 ab c 1 1 1 1 d e 01 11 10 1 0 f 00 de f 1 1 1 1 1 1 r s 01 11 10 1 0 t 00 rs t 1 1 1 1 1 1 x y 01 11 10 1 0 z 00 xy z
Digital Electronics - Tutorial 5 of 46 Q6a) F(a,b,c,d) = Σ m(0,2,3,4,7,8,14) = B’C’D’+A’C’D’+A’CD+A’B’C+ABCD’ Q6b) F(a,b,c,d) = Σ m(1,2,4,15) + Σ d(0,3,14) = A’B’ + A’C’D’ + ABC Q6c) F(a,b,c,d) = Π M(1,2,3,4,9,15) = B’C’D’ + AB’C + AD’ + BC’D + A’BC A’B’C’, A’BD & BCD’ is not used Q6d) F(a,b,c,d) = Π M(0,2,4,6,8) Π D(1,9,12,15) = AC + D 1 1 1 1 1 1 1 A B 01 11 10 10 11 01 00 C D 00 ab cd X 1 X 1 1 1 X A B 01 11 10 10 11 01 00 C D 00 ab cd 1 0 0 0 0 1 1 1 1 1 0 1 1 0 1 1 A B 01 11 10 10 11 01 00 C D 00 ab cd 0 X 1 0 0 1 1 0 X 1 X 1 0 X 1 1 A B 01 11 10 10 11 01 00 C D 00 ab cd
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