PHY 150 Project One Supply Drop Plan Template_KAbbott

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Southern New Hampshire University *

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150

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Industrial Engineering

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Apr 3, 2024

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A&L ENGINEERING Supply Drop Plan Keon Abbott November 9 th , 2023 PHY 150-J2326 3-2 Project One: Objects in Motion Scenario You have recently joined the team at A&L, an engineering firm with a broad portfolio. A&L has recently been hired to help plan a supply drop following a natural disaster. Due to conditions on the ground, the supply drop will be done from the air. Your supervisor has asked you to use that information, as well as your knowledge of kinematics, to create a supply drop plan detailing how far the payload should be from the drop site when it is delivered. Additionally, due to adverse conditions in the area, your supervisor has asked you to prepare for two contingencies. Directions The plane carrying the supplies will be cruising at a constant velocity of 250 miles per hour relative to the ground and at a height of 2,650 meters above the target site. Using this information, create a supply drop plan including all required information and calculations outlined below. As you are completing your supply drop plan, remember that correct SI units are a required component of your calculations and descriptions. Horizontal and Vertical Motion Diagram *Can be seen on next page

Kinematics Calculations *can be seen on next page 𝑦 = 𝑦 𝑜 + 𝑣 𝑜 𝑡 + 1 2 𝑔𝑡 2 0 = − 2,650 + 4.9 𝑡 2 2,650 = 4.9 𝑡 2 2,650 4.9 = 𝑡 2 √ 2,650 4.9 = 𝑡 𝑡 = 23.26 𝑠 Initial Velocity Horizontal: 250 mi/h (or 402 km/h) Vertical: 0 Final Velocity Horizontal: 250 mi/h (or 402 km/h) Vertical: 141.64 mi/h (or 227.95 km/h)

𝑣 𝑦 = 𝑣 𝑜 − 𝑔𝑡 𝑣 𝑦 = 0 − 9.8 ⋅ 0.11 𝑣 𝑦 = − 288 𝑥 = 𝑣 𝑜 𝑡 𝑥 = 23.26 ⋅ 0.11 (km/s) 𝑥 = 2.6 Km 𝐷 = 𝑉𝑇 𝐷 = 0.11 (km/s) 23.26(s) 𝐷 = ¿ 2.56 km or 2,560 meters Equation Descriptions Time of travel was calculated by using this equation: 𝑦 = 𝑦 𝑜 + 𝑣 𝑜 𝑡 + 1 2 𝑔𝑡 2 Finding the horizontal distance traveled was calculated by using this equation: 𝑥 = 𝑣 𝑜 𝑡 The velocity on landing was calculated by using this equation: 𝑣 𝑦 = 𝑣 𝑜 − 𝑔𝑡 The distance needed to travel to drop the load at the accurate spot was calculated by using this equation: 𝐷 = 𝑉𝑇 To truly understand this calculation, it is imperative to know that the horizontal motion will always stay consistent, because there is no acceleration. Vertical velocity is different in this scenario because gravity is responsible for the force on the object. There is no initial vertical velocity which results in the final velocity being negative. This is an accurate answer because the object (cargo) is being dropped from the plane. This is when I

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