ID # 1226043119 - Written Homework Week #2

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Arizona State University *

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MAT 243

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Mathematics

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Apr 3, 2024

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ID # 1226043119 - Written Homework Week #2 1. Identify each of the following statements as true of false and explain your reasoning in full sentences. The domain of discourse is the integers. (a) x y ( y > x ) A. False. The statement says that there exists an x for which all y>x. However, this is not possible for any x as an integer like y=x or y=x-1 etc will be equal or smaller than x. (b) y x ( y > x ) A. True. The statement says that for all y there is an x such that y>x. This is true as for any y we can get an x = y-1 or x=y-(ANY +ve Integer), so that y>x. (c) x ( x = 0 x = 1) A. False. The statement says that there exists an x where if x=0 then x=1. However, if the premise(x=0) is true, then x cannot be 1 and the conclusion is false. Thus the implication is false. 2. Write the formal negation of the following statements. Your negation must not contain any explicit negation symbols. (a) x y (2 < x y ) A. ∃x∀y((2≥x) ∨ (x>y)) (b) y x ( y > 0 x 0) A. ∃y∀x((y>0) ∧ ( x>0)) 3. Negate verbally: (a) ”All people weigh at least 100 pounds.” A. Some people weigh at less than 100 pounds. (b) ”Somebody did not see any animals in the zoo” A. Everybody saw some animals in the zoo. 4. If P and Q are predicates over some domain, and if it is true that x ( P ( x ) Q ( x )), must xP ( x ) xQ ( x ) also be true? Explain. A. No, this is not the case. This is because if x(P (x) Q(x)) is true, this means that for all x, P(x) or Q(x) is true, whereas xP (x) xQ(x) means that for all x, P(x) is true or for all x, Q(x) is true. To explain, take x(P (x) Q(x)) as true. This implies that it could be the case that for some x = x 1 P(x) is true but Q(x) is not and for some x = x 2 Q(x) is true but P(x) is not. Now, the existence of x 1 implies that xQ ( x ) is false and x 2 implies that xP ( x ) is false. Thus, xP (x) xQ(x) is false. 5. Suppose P is the predicate defined by P ( x, y ) = x is friends with y , where x and y are people. (No one is considered to be friends with themselves.)
Translate the formal expression x y z ( y / = z P ( x, y ) P ( x, z )) into English. A. For all x there exists y and z such that y is not equal to z and x is friends with both y and z. 6. Let P be defined as in the previous problem. Is x y z ( y / = z P ( x, y ) P ( x, z )) true or false? Explain. A. False. This statement implies that for all x there is some y and z such that when y is not equal to z, x is friends with y and x is friends with z. This means that everybody is friends with at least two people. However, this may not be true. Thus, the statement is false. 7. Translate the following statement into a logical expression using quanti- fiers, logical operators and the given predicates with the given domains: There is a person in the class, who cannot swim ”. Let C and S be predicates defined by C ( x ) = ” x is in the class” and S ( x ) = ” x can swim”. (a) domain for x : students in the class. A. ∃x¬S(x) (b) domain for x : all people. A. ∃x(C(x) ∧ ¬S(x)) 8. Translate the following statement into a logical expression using quanti- fiers, logical operators and the given predicates with the given domains: All students in the class have taken calculus ”. Let C and Q be predicates defined by C ( x ) = ” x is in the class” and Q ( x ) = ” x has taken calculus”. (a) domain for x : students in the class. A. xQ(x) (b) domain for x : all people. A. x(C(x) → Q(x)) 1
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