MATH 1201-01 - AY2024-T2 Written Assignment Unit 5

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Jan 9, 2024

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MATH 1201-01 - AY2024-T2 Written Assignment Unit 5 Using the formula: A=P(1+ r/n)nt where P is the principal amount, r is the annual interest rate (decimal), n is the number of times interest is compounded per year, and t is the time in years. For simple interest, the future value (A) is given by: A=P(1+rt) where r is the annual interest rate (decimal), and t is the time in years. A(20) = 8500(1 + 0.0812/12) 12*20 A(20) = 8500 (1+ 0006677) 240 = 42922.27 A (20) = 42922.27 Deposit compounded monthly with simple interest: A(t) = P(1 + r/n*nt) A(t) = P(1+rt) A(t) = 8500(1+0.0812*20) A(t) = 8500*2.624 A(t) = 22304 Thus, there was an exponential increase. 2. Graph the function f(x) = 5(0.5) -x and its reflection about the line y = x on the same axis, and give the x – intercept of the reflection. Prove that a x = e xlna a x = e xlna y = 5 *0.5 -x = 5e -xln0.5 y/5 = e -xln0.5 ln(y/5) = -xln0.5 –ln(y/5)/ln0.5 = x y – ln(x/5)/ln0.5
X intercept is a point where y = 0 so, f-1(x) = -ln (0.5) ln(5x) 0 = -ln (0.5) ln(5x) Ln(5x) = 0 5x = e0 5x = 1 X = 5 ax=exlna The reflection of f(x)=5(0.5)−x about the line y=x is f−1(x)=−ln(0.5)ln(5x) The reflection of f(x)=5(0.5) −x about the line y=x is f−1(x)=−ln (0.5) ln(5x) Therefore, x – intercept of reflection is function is (5,0) 3. Answer: 800 = 1000 e ln0.5/703800000t 0.8 = e ln0.5/703800000t Ln0.8 = ln0.5/703800000t 703800000*ln0.8/ln 0.5 =703800000*0.322 = t
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