Chris Todd Johnson - Lab 8
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How investigating a simulated fluid pressure water tank proves the relationship between the total pressure of a fluid and depth
Introduction:
The data collected while observing a simulated fluid pressure water tank allows the comparison of the dependency of the total value of Pressure (P) on a fluid to different test values for depth (h). Given that the simulation of a fluid pressure water tank allows for the input of multiple values, including different test values for depth (h), it is possible to determine the dependency of each value on the total value of Pressure (P).
An observer would notice that the total value of Pressure (P) is called the dependent variable because it will be the variable that may or may not depend on the change in another variable and is located on the y-axis of the graphs. The Pressure (P) may be calculated by the following equation: Pressure (P) = Force (F) / Area (a).
The effect of depth (h in meters) on the total pressure of a fluid (P in Pascals) may be calculated by the following equation: Pressure (P) = [(density (ρ) X gravity (g)] X depth (h) + atmospheric pressure (P
o
).
The accepted value for the pressure of the atmosphere at sea-level which is 101,350 Pascals.
The accepted value for the acceleration of gravity is 9.8 m/s
2
.
The accepted value for the density (ρ) of water is 1000 kg/m
3
.
Procedure:
1.
Start the simulation 2.
list 15 different test values for depth (h) to input into the simulation to determine its dependency on the value of the water pressure (P)
Trial #
X = Depth (meters)
1
0.2 meters
2
0.4 meters
3
0.6 meters
4
0.8 meters
5
1.0 meters
6
1.2 meters
7
1.4 meters
8
1.6 meters
9
1.8 meters
10
2.0 meters
11
2.2 meters
12
2.4 meters
13
2.6 meters
14
2.8 meters
15
3.0 meters
3.
input the first test value for depth (h) into the simulator and observe its dependency on the value of the pressure (P), then repeat the process for the fourteen remaining test values
4.
perform comparative analyses
Results:
Trial #
Y = Pressure (Pascals)
X = Depth (meters)
1
103200 Pascals
0.2 meters
2
105300 Pascals
0.4 meters
3
107100 Pascals
0.6 meters
4
109100 Pascals
0.8 meters
5
111000 Pascals
1.0 meters
6
113100 Pascals
1.2 meters
7
115100 Pascals
1.4 meters
8
117000 Pascals
1.6 meters
9
119000 Pascals
1.8 meters
10
120900 Pascals
2.0 meters
11
122800 Pascals
2.2 meters
12
124900 Pascals
2.4 meters
13
126800 Pascals
2.6 meters
14
128700 Pascals
2.8 meters
15
130500 Pascals
3.0 meters
100000
105000
110000
115000
120000
125000
130000
135000
0.0
0.5
1.0
1.5
2.0
2.5
3.0
3.5
f(x) = 0 x − 10.35
Pressure (P) vs. Depth (h)
h = Depth (meters)
P = Pressure (Pascals)
Data from the table, input into the graph, shows that when different test values for depth (h) are input into the simulator, the value for pressure (P) rises as the value for depth (h) does. Data from the table and graph also show that the slope of the “Pressure (P) vs. Depth (h)” graph is constant and forms a diagonal line. One may observe that values of the pressure of a fluid and the depth are directly proportional.
Data from the simulation screenshot allows an observer to view one of the 15 trials for different values of depth (h), and the resulting total pressure (P) value. One may observe that during the current screenshot of trial #8, the value of depth (h) was set to 1.6 meters (m) and the resulting value for total pressure (P) was 117,000 Pascals (P).
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Related Questions
https://eagleonline.hccs.edu/courses/156500/quizzes/969413/take
Question 40
5 pts
A pressure gauge on a tank reads 25 psi. What is the absolute pressure in atmospheres and psia?
Formular:
1 atm = 760 mmHg = 76 cm Hg = 14.7 psia =29.92 in Hg = 33.91 feet H2O
%3D
%3D
%3D
Pabs
Pgauge + Patm
where
Pabs is absolute pressure
Pgauge is gauge pressure
Patm is atmospheric pressure
Upload
Choosc a File
Subimit Quiz
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A fixed amount of ideal gas is kept in a container of fixed volume. The absolute pressure P, in pascals, of the gas is plotted as a function of its temperature T, in degrees Celsius.
Which of the following are properties of a best fit curve to the data? Select two answers.
a. Having a positive slope
b. Passing through the origin
c. Having zero pressure at a certain negative temperature
d. Approaching zero pressure as temperature approaches infinity
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2.30.
Ans. 161 kPa
30
FLUID STATICS
[CHAP. 2
Air
10
Oil
sp gr 13.57
Fig. 2-20
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A model tow-tank test is conducted on a bare hull model at the model design
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ship and model:
Ship
1,100
Model
Length (ft)
Hull Wetted Surface Area (ft2)
Speed (knots)
30
250,000
15
Freshwater
Water
Seawater 50°F
70°F
Projected Transverse Area (ft²)
Cair
7,500
0.875
Appendage Resistance (% of bare hull)
10%
Hull Resistance (Ibf)
20
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TOUT
REFERENCES
MAILINGS
REVIEW
VIEW
Hyperlink
P Bookmark
tArt Chart Screenshot Apps for
Office
Online
Video Cross-reference
Comment Header Footer
Page
Number
Text Quick WordA
Box Parts -
ns
Apps
Media
Links
Comments
Header & Footer
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(b) gradient of shear rate -/dy using cgs units.
(c) Repeat using SI units.
A Torce
Fdshear berween teoparailel plates
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Sheet 1
Page 2 of 2
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¿When viscous resistance is important,
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14 cm.
20 cm.
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