ENG10002-Lab 1-Stiffness of Materials using EXCEL - submission

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Swinburne University of Technology *

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10002

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Mechanical Engineering

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Oct 30, 2023

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2023 Stiffness of materials using Hooke’s Law, and Data analysis using EXCEL – submission [V.6.09.2023] Updated: 6.09.2023 1 Stiffness of materials using Hooke’s Law, and Data analysis using EXCEL submission Date and time of experiment: Click or tap to enter a date. Demonstrator name Click or tap here to enter text. Your name: Vicheadanin Rath Your Swinburne ID: 104480460 Your partner’s name: Click or tap here to enter text. Your lab submission sheets should be submitted to CANVAS within ONE week of completion of this work. SUBMISSION REQUIREMENTS-in pdf Spring Type Linear Equation of best fit “y=mx+c” ie F=Kx Regression analysis value from Linear Trendline R 2 , From Linear Equation of best fit Value of Spring Law constant K Comparison Value of Spring constant K Steel Spring y = 0.1271x + 4.3072 R² = 0.9995 0.1271 0.1328 Brass A Spring y = 0.0738x + 2.6479 R² = 0.9999 0.0738 0.079 (Short) Brass B Spring y = 0.0926x + 2.3036 R² = 0.9998 0.0926 0.0972 (Long) Brass B Spring y = 0.0899x + 2.7263 R² = 0.9999 0.0899 0.0897 SUBMISSION one graph for the two springs of different materials; one graph for the two springs of the same material but different lengths. Fill in the table on this SUBMISSION SHEET using data from EXCEL, trend line linear analysis, Regression analysis value R 2 , and so determine a value of K (Hooke’s constant/spring constant) for each spring . Conclusion Sum up the results and look for possible sources of error. Do not just say human error- be specific! And don’t say calculation error - fix it if you made a mistake . If the equation involved in the graph is F = Kx and the equation of a line is y = mx + b, what is represented by the slope of the graph?
2023 Stiffness of materials using Hooke’s Law, and Data analysis using EXCEL – submission [V.6.09.2023] Updated: 6.09.2023 2 Figure: 1.1: Force vs Extension of 2 different medium brass and steel Figure: 1.2: Force vs Extension of one medium with different length (brass short and brass long) This experiment demonstrates the complex behaviour of materials under forces. By examining these two materials' (steel and brass) elastic properties, investigate Hooke's law. The findings highlight the importance of taking into account a number of variables, such as material properties and experimental settings, when examining a material's elastic response. The steel and brass mediums exhibit elastic behaviour within the range of loads used in this experiment, according to the data gathered and analysis carried out. The goal was to ascertain the degree to which these materials adhered to Hooke's Law, which outlines the linear relationship between applied force and resulting deformation. Based on the Hookes' law (F = kx), where x (m) is the deformation and F (N) is the y = 0.0738x + 2.6479 R² = 0.9999 y = 0.1271x + 4.3072 R² = 0.9995 0.00 2.00 4.00 6.00 8.00 10.00 12.00 0 20 40 60 80 100 120 Force (N) Extension (mm) Brass medium Steel medium y = 0.0899x + 2.7263 R² = 0.9999 y = 0.0926x + 2.3036 R² = 0.9998 0.00 2.00 4.00 6.00 8.00 10.00 12.00 0 10 20 30 40 50 60 70 80 90 Force (N) Extension (mm) Brass Long Brass Short
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