Lab 1 Instructions

Mechanical Vibration Question is image

A 65 kg industrial sewing machine has a rotating unbalance of 0.15 kgm. The machine operates at 125 Hz and is mounted on a foundation of equivalent stiffness 2×106 N/m and damping ratio 0.12. What is the machine's steady state amplitude? [Ans: 2.43mm]

Response using matlab.

Thanks

Vibration Engineering:  Mass = 10 kilogramsSpring constant = 400 Newtons per meterPeriodic Force = 6 KilonewtonsForcing Frequency = 5 radians per secondDamping coefficient = 200 Newton second per meter Calculate: (Express the final answer in 4 significant digits) -the phase angle in radians -the natural frequency in radians per second -the amplitude of steady-state vibration in meters

A seismic transducer with natural frequency 750 rad/s and damping ratio 0.7 is used to measure acceleration. The input to the sensor is a sinusoidal displacement with amplitude 1 x 10 m and fundamental frequency 100 Hz. The resulting steady-state acceleration measurement is a sinusoid. What is its amplitude (in m/s?)?

1. Verify Eqs. 1 through 5. Figure 1: mass spring damper In class, we have studied mechanical systems of this type. Here, the main results of our in-class analysis are reviewed. The dynamic behavior of this system is deter- mined from the linear second-order ordinary differential equation: where (1) where r(t) is the displacement of the mass, m is the mass, b is the damping coefficient, and k is the spring stiffness. Equations like Eq. 1 are often written in the "standard form" ď²x dt2 r(t) = = tan-1 d²r dt2 m. M +25wn +wn²x = 0 (2) The variable wn is the natural frequency of the system and is the damping ratio. If the system is underdamped, i.e. < < 1, and it has initial conditions (0) = zot-o = 0, then the solution to Eq. 2 is given by: IO √1 x(1) T₁ = +b+kr = 0 dt 2π dr. dt ل لها -(wat sin (wat +) and is the damped natural frequency. In Figure 2, the normalized plot of the response of this system reveals some useful information. Note that the amount of time Ta between peaks is…

Phase (deg) Magnitude (dB) 20 20 40 180 135 90 45 10' 0 ġ(t) 하 R www Mechanical Deformation Piezo Charge Amplifer 10 10 Frequency (rad's) v(t) Figure 2: Frequency response function of a microphone Figure 3: A simple model for piezoelectric sensor 3. Figure 3 is a simple circuit modeling a piezoelectric sensor. Mechanical deformation of the sensor induces charge q(t), which is first modeled as a current source. The capacitance C models the piezoelectric material, and the resistance R represents impedance of a charge amplifier with output voltage v(t). Usually, C is fixed for a sensor, but R is adjustable from the amplifier. The frequency response function from q(t) to v(t) is Answer the following questions. G(w)= = jRw 1+jRCw (6) (a) Consider the case when C = 1 Farad and R = 0.5 Ohm. (The numbers are chosen to ease calculations. In practical applications, C is much smaller and R is much bigger.) If the input deformation induces electric charge = q(t) cost+2 sin 3t (7) predict the…

A test was undertaken to find the dynamic properties of a SDOF system. The measured transient response recorded is shown in Figure QA2a. If the stiffness of the system is 1,000 N/m estimate: i) the damping ratio, ii) the undamped natural frequency, and iii) the mass of the system. Displacement (m) 0.08 0.06 0.04 0.02 O -0.02 -0.04 -0.06 -0.08 Figure QA2a 0.5 Time (s) 1.5 2

solve, show solution and matlab code, vibrations

I need the answer as soon as possible

Vibrations

Vibration Engineering

2. The equation of motion for a damped multidegree of freedom system is given by Where [m] = [m]{x} + [c]{x} + [k]{x} = {f} [100 = 0 0 0 10 0 10. 1000-4 {f} [c] 8 –4 0 8 – 4 -4 4 0 8 4 = 100 2 0 = Focos(wt) -2 -2 The value of Fo 50N and w 50 rad/sec. Assuming the initial conditions to be zero and using the modal coordinate approach, find out the steady state solution of the system in the modal coordinate for first mode. Plot the steady state solution using the computational tools. 0 −2], [k] = = 2

Calculate the natural frequencies and vibration modes of a free-vibrating 2-GDL spring-mass system, using the matrices of this system presented below. mass matrix stiffness matrix [":] m 2k -k M K: %3D т ーk 2k

The following chart represents the Dynamic Amplification Factor (DLF) of pulses type Ramp. Time from 0 to Maximum force: td Natural Period of the structure: T What is the maximum dynamic displacement of a structure with: stiffness, k, of 150 kip/in mass, m=50/g k-sec^2/in g: gravity acceleration The ramp force reach the maximum force F=100kip in a time td-0.15 sec RAMP: DLF vs td/T DLF 2500 1.500 1.000 0:000 O 0.81 in O 1.22 in O 0.67 in O 1.50 in td/T 15

1. Determine the driven response for: Bi k B2 k mi m2 Given: ID k spring constant, mě – mass, B: - damping coefficient, F(t)   Initial data:   ID = 500351   ID % 4 = 1

2. ▷522, 258px yağ-kütle sönümleyici sistemi aşağıda verilmiştir. 771- 10 kg. b 30 N-s m. k 1000 Nm. P-10N and ws= 2 rad/s if what is the steady state response at the output - v(t) = ? input p(t)=? COD N p(t)=P sin cr 661 x 308px Boyut: 57.4KB Casper

otoring: MITO R (Motor) = VAPPL Torque [N*m] 60 T 0₁ V 200 rad/s W₁ Viscous Friction b₁ N₁ J₁ 2 N₂ b₂ Viscous Friction J₂ VMOTOR K, W₁ T=K₁ i 0₂ ta from the steady state dynamometer test and the given values: J₁ ², b₁ 2N, b2 = 12N, N₁ = 50 teeth, N₂ = 100 teeth (R should rad'

Needs Complete typed solution with 100 % accuracy

oE 22_Mat_Eng_Test_10_phase_trans X P 22_Mat_Eng_Test_10_phase_trans X + O File | C:/Users/Asus/Downloads/material/22_Mat_Eng_Test_10_phase_transformation_11_04.pdf of 30 (D Page view A Read aloud T Add text V Draw E Highlight Erase 03 25 att Mechanical behaviour - problem MUEGYETEM 17 82 Determine the tensile strength of a eutectoid Fe-Fe3C alloy that has been subjected to heat treatment: 760 °C → rapidly cool to 650 ° C, hold for 20 s, rapidly cool to 400 °C, hold for 1000 s, and quench to RT. 800 A Eutectoid temperature 1400 700 A 1200 600 1000 500 B Bainite Pearlite 800 600 400 2000 500 A 300 600 1500 400 M(start) 200 M + A 50% 400 300 1000 M(50%) M(90%) 200 100 200 500 100 10-1 10 102 103 104 105 200 300 400 500 600 700 800 Time (s) Transformation temperature (°C) 60 ENG 8:08 AM qb US 5/11/2022 Brinell hardness number Tensile strength (MPa) Temperature (°C) Temperature (°F)

Question 2 |Soalan 2] A student is asked to design a four bar crank-rocker mechanism that satisfied Grashof mechanism with following condition: time ratio is 1:1.4, rocker is 70 mm and maximum oscillation angle is 60 degree. (i) With the aid of appropriate diagram, explain the required steps to design this mechanism in general without considering the condition (ii) Solve the angles a, ß and 8 for crank-rocker mechanism following the condition given. (iii) Based on information in Q2(ii), design the four bar crank-rocker that satisfied all condition given. Please label all the links and angles a, ß and ô in your design. the (iv) If time ratio of this mechanism becomes 1, construct the kinematics diagram of the crank- rocker mechanism. Please label all the links and angles a, ß and ô in your design.

The response of a certain dynamic system is given by: x(t)=0.003 cos(30t) +0.004 sin(30r) m   (5Mks)   Determino:   (i) the amplitude of motion.   (2Mks)   (ii) the period of motion.   (in) the linear frequency in Hz.   (4) the angular frequency in rad/s.   (2Mks) (2Mks)   (2Mks) (2Mks)   (v) the frequency in cpm.   (vi) the phase angle.   (2Mks)   (vii) the response of the system in the form of x(t) = X sin(t +$) m.

Need help with parts C and D plssss

2. An operator provides mobile communication service for a city with area of 3500 Km' and has population of 1.56 million. Following parameters have been specified for the cellular network: Downlink band: 800 MHz to 940 MHz, • Channel bandwidth = 200 KHz, • Probability of Blocking 1%, Frequency Parameters i=2 & j=1, Cell radius = 0.85 Km If the user has an average of 2 calls/hour and each call lasts for an average of 3 minutes. Using table 1 obtain: i. Number of users that could be served per a cell, (14 Marks) No. Channels/cell BP= 0.01 BP= 0.005 BP= 0.002 5 1.36 1.13 0.9 10 4.46 3.96 3.43 20 12 11.1 10.1 70 56.1 53.7 51 100 84.1 80.9 77.4

Example 6: Calculate the response of Single Degree of Freedom System for the given step force by Duhamel Integral for two cases: a) 0 b) 40 p(t) Po k p sin [a, (t – t)]dt %3D mwn 1 Dampd u(t) = man peten-) sin [awp(t – t)] dt mwp Jo 0000