Lab #7 Report
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447
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Mechanical Engineering
Date
Jan 9, 2024
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5
Uploaded by EarlMule3901
McKenna Nichols
BME 447
Loeffler
25 October 2023
Chapter 8 Lab Report: Spectrophotometry
Results
Task 1: Hemoglobin Quantification with a Spectrophotometer
Intensities Measured At Wavelength:
530
Concentration (mg/mL)
Intensity
Absorbance
0
12258.46
0
0.125
3389.73
0.55827
0.25
2701.61
0.65681
0.5
2683.69
0.06597
1
679.41
1.25630
Task 2: Hemoglobin Quantification with LED/PD Circuit
Concentration (mg/mL)
𝑉
𝑜??
Absorbance
0
11.1
0
0.125
10.3
0.03249
0.25
9.6
0.0630
0.5
9
0.09108
1
8.1
0.13684
Task 3: Unknown Sample
𝑉
𝑜??
Absorbance
Assumed Concentration (mg/mL)
9.9
0.04969
0.25
Discussion
In the first portion of this lab, we began by making five solutions which each have
different concentrations of hemoglobin. The concentrations we made are 1.0 mg/mL, 0.5 mg/mL,
0.25 mg/mL, 0.125 mg/mL, and 0.0 mg/mL. We then used the spectrophotometer to measure the
intensities of these concentrations. We then used these intensity values to calculate the
absorbance for each solution. The equation we used for absorbance is
, where
is
𝐴 = 𝑙𝑜𝑔(
𝐼
0
𝐼
)
𝐼
0
the light intensity from the light source and
is the light intensity passing through the material.
𝐼
Now that we have the absorbance, we graphed that in comparison to the concentrations. This
graph can be seen in the results section above. Our results showed that there is a direct
relationship between the absorbance of hemoglobin and the concentration of hemoglobin. This
makes sense because as the hemoglobin concentration increases, the solution becomes less
transparent. This means that more of the light is absorbed by the hemoglobin and less of the light
passes through the solution.
In the second portion of this lab, we used the same five solutions that we made for the
previous section. To begin we had to wire
the circuit that is shown to the right. From
here, we measured the value of
when
𝑉
𝑜??
the cuvette was filled with different
solutions of different concentrations. We
did this for the concentrations of 1.0 mg/mL, 0.5 mg/mL, 0.25 mg/mL, 0.125 mg/mL, and 0.0
mg/mL. We then used these
values to find the absorbance for each solution. We used the
𝑉
𝑜??
equation
where
is the voltage output of the 0 mg/mL solution and
is
𝐴 = 𝑙𝑜𝑔(
𝑉
𝑜??,0
𝑉
𝑜??
)
𝑉
𝑜??,0
𝑉
𝑜??
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