Chapter Three Lab
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Chapter 3 Lab –
So, for this chapter’s lab we will be using the following simulation:
https://phet.colorado.edu/sims/html/ohms-law/latest/ohms-law_en.html
We will be doing two experiments, or really just repeating this first experiment twice. We will be studying Ohm’s Law.
In the simulation let’s start by thinking about the independent variable. This would be the thing that we control. We can control the battery or voltage and we can control the resistance.
Let’s think about the dependent variable. This is the variable that we do not have control over but might change when the independent variable changes. The dependent variable is the current. Try changing the voltage on the battery by moving the slider around and you will see that the current increases.
Try decreasing the resistance and see what happens to the current. It increases right?
In order to verify this physics principle (Ohm’s law) we need to keep one of the three variables constant. Let’s keep the resistance constant. Move the slider for resistance around and then keep the resistance the same for the duration of the experiment. It really does not matter what value you choose as long as you collect this as data and include it in a data table.
You can take a screen shot of the resistance to show that resistance and cut and paste that image into your lab report in the data section. Remember that you are writing a typical lab report with the following labeled sections.
Title
Introduction
Procedure
Data and Results
Conclusion
Now you will need to do what is often done in physics experiments. You will graph two variables and you will use the slope to verify a physics principle. I will only give full credit for your results if you show
a graph with the equation of best fit on the graph showing the slope and you use that slope for your final answer!
Let’s pick this equation apart.
V = I*R can be rearranged to I = V/R
Or I = 1/R * V
Y= m *X
Do you see the y value in the equation above?
I – current – This means that you will have a different value for current for each time you change the voltage. Be sure to create a data table showing your values for voltage and current for each trial. BE CAREFUL HERE. You are NOT being instructed to use Ohm’s law to calculate
the current. You are measuring
current using the simulation and verifying Ohm’s law. If you were to calculate current than you would be using Ohm’s law to verify Ohm’s law would not count as a scientfific experiment.
Do you see the x value?
V – voltage (battery) – This means that you will have several trials where you will change the voltage and
there will be a resulting change in current. Remember again to measure the current as seen in the simulator and not to calculate current. Be sure to create a data table showing your values for voltage and current for each trial. The slope should then be equal to?
I = 1/R * V
Y= m *X
Slope = (1/R) - Be careful here. Slope is NOT equal to R, Slope is equal to 1/R.
So your task is to graph Current vs Voltage
In physics when you say current vs voltage then current is the y axis (dependent variable) and voltage is the x axis (independent variable).
You will get Excel (or google sheets) to show the equation of best fit which should be on the graph.
Then you will solve for the resistance of the battery that you have kept constant.
Slope = 1/R
R = 1/slope
Show your work with symbols and units in your data section!
Then you must calculate a percent error to quantitatively express the accuracy of your experiment and discuss whether you have verified Ohm’s Law. The resistance of the battery is your accepted value and the resistance that you calculate from the slope is the experimental value. You should get very close to 0% error because you are using a simulation instead of a multimeter and a battery. However you are graphing the data because this would be the best way to do a similar lab with real equipment.
% error = accepted value – experimental value/ accepted value x 100.
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Related Questions
Part A
Learning Goal:
To understand and use exponential decays.
Exponential decay occurs when a quantity y is
proportional to the number e taken to the power
-t/T. The quantity T is known as the time
constant. So we say that y equals A times the
quantity (e to the power of minus t over T) and
write this mathematically as
y = Ae-T/T,
where A is a constant.
SCALING Whenever t increases by one time
constant, y decreases by a factor of 1/e. For
instance:
• At time t = 0, y = A.
• Increasing time to t = 7, reduces y
to A/e.
⚫ A further increase to t = 2T reduces
y by another factor of 1/e to A/e².
Generally, we can say:
At t = nT, y has the value A/en.
LIMITS As t becomes large, y becomes very small
and approaches zero.
Consider the case when the constant A = 3 and 7 = 4. Plot the graph of y = 3e-t/4 at each available point from
t = 0 to t = 10.
+
*
血
No elements selected
4.0
3.0
y
2.0
1.0
0
2.0
4.0
6.0
8.0
10.0
t
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Reclung.c
A on
ri gle
Figure 1
2. The circuit shown above is constructed with two 6.0 V batteries and three resistors with the values shown.
The currents 1₁, 12, and 13 in each branch of the circuit are indicated.
2
GEOMETRY AND TRIGONOMETRY
Circle
A = ²²
C = 2πr
Cy.inder
bh
- re
Rectangular Solid
Vlh
Sphere
1. Using Kirchhoff's rules, write, but DO NOT SOLVE, equations that can be used to solve for the
current in each resistor.
ii. Calculate the current in the 200 9 resistor.
iii. Calculate the power dissipated by the 200 2 resistor.
V = ar²l
S..
Figure 2
The two 6.0 V batteries are replaced with a battery with voltage & and a resistor of resistance 50 2, as shown
above. The voltmeter V shows that the voltage across the 200 £2 resistor is 4.4 V.
(b) Calculate the current through the 50 2 resistor.
(c) Calculate the voltage & of the battery.
V=²
S = 4; 7²
Rig Triangle
2 +6² = c²
sin =
COS==
tan 8 =
OJA
b
C
2m.
a
b
6.0 V
7,4
&
A - area
C=circumference
h-hei
£= le L
W = IUL
r=fuu.0…
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Capacitance, Charge and Voltage: Q = CV
1. Click the Reset Button on the bottom right of the PHET simulation.
2. CHECK Plate Charges and Bar Graphs boxes in the upper right so your display resembles
the graph below.
3. SET the Plate Area to 200 mm² and the Separation to 4.0 mm.
Capactance
Tup Pate Charge oc
Sured Energy
Pu Charges
r Graphs
O e Fd
Cument Direction
1500 V
4. Connect the voltmeter across the capacitor by placing the red on the top plate and black
on bottom. If the voltmeter reads a negative, switch the red and black.
5. Set the battery Voltage to 0.25 V. Record the measured plate charge, Q.
6. Repeat Step 5 for each Voltage in Table 3.
Table 3: Charge and Voltage
Voltage
|(V)
Plate Charge
|(pC)
0.25 V
0.50 V
0.75 V
1.00 V
1.25 V
1.50 V
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TEXT ANSWER
Question 6
Explain how the device in the diagram below works. Use at least three vocabulary terms
for this unit in your explanation.
Answer using 2 to 3 complete sentences.
H
Normal
Enter your answer here
||'
|||
|| C
BIUS X₂ X² EEAA
√x 2 Ix
300 ch bull
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Given the picture below, give a brief explanation on the possible relationship of the each variable. Then determine the input, process and output.
Please help me. I only need a brief answer not a discussion.
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nce Principles Sen x
r19.core.learn.edgenuity.com/Player/
Google Docs
Science Principles Semester A
de with
个
1
2
ооооо
3
Which statements are true? Select three options.
4
Mark this and return
C
+
Functions can have one parameter.
Functions can have many parameters.
Functions must have a return value.
Functions must have a parameter.
Functions can have two parameters.
O
3
0
DELL
6
O
Save and Exit
L
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x testbank (2).pdf - Google Drive 4
x Chapter 23.pdf - Google Drie
drive.google.com/file/d/OB_ASSL_Ri3Gfcr
Chrom. lio O Google biljs ?
YouTube O
Gmail M
Course: GENERAL. 6
hd client e Notebo
E. 1, 2 and 4 tie, then 3
ans: A
44. The purpose of Milliken's oil drop experiment was to determine:
A. the mass of an electron
B. the charge of an electron
C. the ratio of charge to mass for an electron
D. the sign of the charge on an electron
E. viscosity
ans: B
45. A charged oil drop with a mass of 2 x 10-4 kg is held suspended by a downward electric field
of 300 N/C. The charge on the drop is:
A. +1.5 x 10-6 C
-1.5 x 10-6 C
C. +6.5 x 10-6 C
-6.5 x 10-6 C
В.
D
E. 0
ans: D
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Chapter 22: ELECTRIC FIELDS
UPLOADED BY AHMAD T JUNDI
Chanter 23
CAUSS LAW
SAMSUNG
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b. What is the wavelength of light (in nanometers, nm) being produced by Sakalam?
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with the final answer written inside a box. Make sure to put the final unit
of measurement.
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3. The maximum power that could be transferred to the load will always be at what
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4. What is the Ohm's law formula for the resistance?
If the voltage across a fixed-value resistor is tripled, does the current increase or
decrease, and by how much?
5.
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0.5834149°
(v.)
Formula Q4
Assuming v₂[0] = 120° volts determine
(¹) and (2) then comment on the results
obtained in terms of the outcome of the iteration so far.
III.
1
1.62-80°
- (1.92100°) x (1.140°)
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Aa - A A
Editing
Dictate
Sensitivity
Font
Paragraph
Styles
Voice
Sensitivity
1. The velocity of an alpha particle, He2+, with mass m = 6.64×10-27kg changes from
u1 = (-0.30, 0.45,0.10)c
Uz = (-0.50, 0.30, -0.75)c,
to
where c=3x10°ms-1
Determine the change in the particle's kinetic energy. (In the kinetic energy formula, do not forget to
square the speed of light.) Answer: 1.2x10°
2 Accessibility: Good to go
D. Focus
rds
A GeneralAll Employees (unrestricted)
23
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question attached below
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. Comment on any observation you made as you conduct the
simulation.
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ISBN:9781938168277
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