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Physics
Date
Dec 6, 2023
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Physics Experiment: Light as a Wave
Name:
Date:
Part 1: Diffraction
1)
Go to:
https://phet.colorado.edu/en/simulations/wave-interference
2)
Roll over “SIMULATIONS and click on “Physics”
3)
Scroll down to “Waves Interference” and click on it.
4)
Click on:
5)
Click on:
6)
Get familiar with all the controls, make changes, interact with the simulation.
7)
Now that you are familiar with the simulation, select the box
; adjust the width
and height so you get a tall, narrow opening
8)
Select a wavelength near one end of the color spectrum – you choose and then turn on the
light
12) Describe the diffraction pattern that appears:
9) Describe the diffraction pattern that appears:
10) How is the diffraction pattern oriented, relative to the opening?
There is a rectangle in the center and there are 4 smaller versions of the rectangle to the left and right of the rectangle. As the smaller rectangles get further from the center rectangle they start fading.
11) Now make the opening short and wide.
I picked purple
The diffraction pattern is the same shape as the opening but is rotated horizontally and has rounded
edges.
The diffraction pattern is now a vertical rectangle with smaller rectangles on the top and bottom of the rectangle in the middle. Again, as the smaller rectangles get further from the center rectangle, they start fading.
13) How is the diffraction pattern oriented, relative to the opening?
14) Now max out the width and height of the opening
15) Describe the diffraction pattern that appears:
16) How is the diffraction pattern oriented, relative to the opening?
17) Now minimize the width and height of the opening.
18) Describe the diffraction pattern that appears:
19) How is the diffraction pattern oriented, relative to the opening?
20) Now, change the wavelength to the other side of the spectrum. For example, if you chose the
red end of the spectrum for the previous steps, move the wavelength slider to the blue end
of the spectrum.
21) Describe the diffraction pattern that appears:
22) How is the diffraction pattern oriented, relative to the opening?
23) How does this diffraction pattern compare to the diffraction pattern of the previous color?
24) Now max out the width and height of the opening
25) Describe the diffraction pattern that appears:
26) How is the diffraction pattern oriented, relative to the opening?
27) How does this diffraction pattern compare to the diffraction pattern of the previous color?
28) Now make the opening short and wide.
29) Describe the diffraction pattern that appears:
30) How is the diffraction pattern oriented, relative to the opening?
The diffraction pattern is vertical and the same shape as the opening but with round edges. There is a square with soft edges and has smaller squares on each side (left, right, top, and bottom)
The diffraction patter is smaller than the opening and looks to be positioned just like the opening.
There is a big square with soft edges and smaller squares surrounding each side, slowly fading as they get
further from the big square.
The diffraction pattern is positioned like the opening and is bigger. Since I picked purple in the previous steps, I now switched to red. The red diffraction pattern is bigger than purple.
The diffraction pattern is still the same shape as the opening, but is way bigger This diffraction pattern is bigger compared to the diffraction pattern of purple. There is a square and has smaller squares on each side The diffraction pattern is smaller than the opening but the same shape as the opening with softer edges.
Just like before, this diffraction pattern is just a bigger version of the previous pattern
There is a vertical rectangle with rounded edges and has 2 smaller versions of it on both top and bottom
The diffraction pattern is the same shape as the opening but is rotated vertically.
31) How does this diffraction pattern compare to the diffraction pattern of the previous color?
32) Now make the opening tall and narrow.
33) Describe the diffraction pattern that appears:
34) How is the diffraction pattern oriented, relative to the opening?
35) How does this diffraction pattern compare to the diffraction pattern of the previous color?
36) Explain how this shows light behaves like a wave.
37) Get a screenshot or picture of your setup.
The diffraction pattern is a bigger scale of the previous diffraction pattern. There is a horizontal rectangle with a smaller rectangle on the left and right. The diffraction pattern is the same shape as the opening but with rounder edges and is rotated horizontally. Just like before, it is a bigger version of the purple diffraction pattern.
Different lights have different wavelengths
Part 2: Interference
1)
Down at the bottom, select
2)
Select light
3)
Set Amplitude in the middle
4)
Turn on:
a.
Screen
b.
Intensity
5)
Pick a color with the frequency slider and write the color you chose.
6)
Turn on only one of the lights
.
7)
Describe how you can determine the wavelength of the color of light you chose using any or
all of the tools and controls in the simulation.
8)
Now go figure out the wavelength of the light you chose and write it here________. Be sure
9)
Calculate the frequency of the color of light you chose (you may need to check your notes or
the textbook to find an equation to use). Write the frequency of the color you chose, here
here________. Be sure and put correct units on it!
10) If you changed the Amplitude, set it back to the middle and describe the intensity chart.
11) Now, max out the Amplitude. How did the intensity chart change?
12) Pick a new color with the Frequency slider. After letting the waves propagate across, describe
how the intensity chart compares to the previous color.
BLUE
and put correct units on it!
You can determine the wavelength of the color by using the graph and measuring from
one wave to the next.
432.9nm
693*10^8
The intensity chart is less than 1/4 away from the start of the chart
The intensity chart is now about 1/4 of the way in the chart and is wavy.
With a new color the the intensity chart is similar to the previous color
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Related Questions
QUESTION 4
How would you produce coherent light from an ordinary incandescent light bulb?
O A. By using a spectral filter, a pinhole and a spectral (color) filter respectively.
O B. By using a spectral (color) filter, spectral filter and a telescope respectively.
O c. By using a spectral filter, telescope and spectral (color) filter respectively.
O D. By using a spatial filter, a pinhole and a spectral (color) filter respectively.
arrow_forward
How would you produce coherent light from an ordinary incandescent light bulb?
A. By using a spectral filter, telescope and spectral (color) filter respectively.
B.
C.
D.
By using a spectral (color) filter, spectral filter and a telescope respectively.
By using a spectral filter, a pinhole and a spectral (color) filter respectively.
By using a spatial filter, a pinhole and a spectral (color) filter respectively.
arrow_forward
EXERCISE
1.
What is light?
2. Explain the wave front?
Phase Speed?
3.
4. According to Huygens principle, explain how each point
on the wave front and secondary wave propagation
arrow_forward
Monica was using different colored pieces of clear plastic for an art project Her little brother came and scattered the plastic all over the photograph of Name Name Class Date Name 20 the the image she was using as a guide. As she was cleaning up, she noticed that the image appeared differently behind certain colors of plastic. Why was this
A. Certain colors of light pass through, leaving everything else blank or invisible. B. Only the color matching the plastic can pass through, leaving everything else shades of black. C. Only the color matching the plastic can pass through, leaving everything else blank or invisible. D. All colors except the one that matches the plastic can pass through, leavng. that color black
arrow_forward
Assessment 2
Directions: Write ULTRA if the statement is correct, and VIOLET if not. If the statement is
incorrect, state reason or appropriately correct the statement.
1. Too much exposure to UV rays may increase the risk for skin cancer and cataracts.
2. Sunscreens protect our skin so we can stay under the sun all day.
3. The higher the Sun Protection Factor (SPF) in a sunscreen, the higher the protection.
4. Sunglasses have UV coating that help block harmful rays from the sun.
5. It is good to avoid the sun entirely.
arrow_forward
Calculate the frequency of yellow light with a wavelength of 580 x 10-9 m.
pls make your answer clear and understandable, and avoid long explanation. + strictly no plagiarism. Thank you!
arrow_forward
S.Co.
CommonLit | MY A.
The New Yorker Fic.
Forces and Motion:. Turnitin
Open a wcb browser and go to: PHET Waves Intro
https://phet.colorado.edu/sims/html/waves-intro/latest/waves-intro en.html
Choose the WAVES INTRO LIGHT
1. In the upper right gray menu, choose the options
• Choose the laser source (device on the right). The visible spectrum should
appear.
• Move the yellow tape measure from the gray menu to the wave field.
2. In the lower left corner, choose continuous waves (button with many transverse
waves),
3. Under the wave field, choose TOP VIEW.
4. Press the PLAY button. Press the round green button on the laser. Light waves
should begin to come out of the laser.
SLIVEWORKSHEE
5. Toggle the slide pointer to the far left side of the visible spectrum to the near
infrared. The color of the laser light should change from its original color to a deep
brownish red.
6. Allow for the near infrared light waves to fill the entire wave field, then press
PAUSE.
7. Use the yellow tape…
arrow_forward
6) Hi, Can you solve the question 6 and make explanation please? and if you are gonna use handwrite please make sure that it is readable thank you. I know that you cant solve multiple options so can you solve the option A and B please
arrow_forward
a.) Describe the principles behind the interference and diffraction of light?
b.) How does interference and diffraction of light interconnection with each other and how can they be used beneficially to us? Give at least one.
arrow_forward
nts]
Content
DETAILS
+
webassign.net
Chapter 24- General Physics 2 - Summer 2022, Summer 2 2022 | WebAssign
OSCOLPHYS2016 24.3.P.006.
(b) Which frequency (in MHz) would produce smaller hot spots in foods due to interference effects?
MHz
Two microwave frequencies are authorized for use in microwave ovens, 895 and 2540 MHz. Calculate the wavelength (in cm) of each.
cm (frequency = 895 MHz)
cm (frequency
= 2540 MHz)
Additional Materials
Reading
MY NOTES
ASK YOUR
range is 540 to 1,600 kHz.
arrow_forward
Activity 3: CRITICAL THINKING!
Directions: Answer the following questions comprehensively.
1. Which wave can be polarized?
2. What is the difference between unpolarized light and plane-polarized light?
3. An Unpolarised light with intensity (1) is passing through a polarizer. What happens
to the intensity of incident light?
arrow_forward
3. Spherical waves: Consider electromagnetic radiation from a "pointlike" antenna, e called
spherical waves, rather than plane waves. Here is a simplified mathematical formula for such a
spherical wave (simplified meaning that it is accurate for large distances from the origin)
sine
Ē(r,0,0,t) = A² -cos(kr-cot)
Why would we call this a "spherical wave"? Describe it in words or pictures as best you can.
Far from the origin, how is it similar to/different from a polarized traveling plane wave?
- Show that this wave satisfies Gauss' law in free space. Then use Faraday's law to find the
formula for the corresponding magnetic field. Since we are assuming we are far from the
origin, you can (and should!) toss terms that appear which drop off FASTER than 1/r...
arrow_forward
Course Home
ge.com/course.html?courseld%316501969&OpenVellumHMAC=3a1da24d859fdc8cea2e88a375ea89fe#10001
Constants | Periodic Table
Correct
Learning Goal:
To understand multislit interference and how it leads to
the design of diffraction gratings.
Part F
Diffraction gratings are used in modern spectrometers to
separate the wavelengths of visible light. The working of
a diffraction grating may be understood through multislit
interference, which can be understood as an extension of
two-slit interference. In this problem, you will follow the
progression from two-slit to many-slit interference to
arrive at the important eauations describina diffraction
Recall that phasor diagrams give the magnitude of the electric field, and that the intensity is related to the
electric field squared. In going from two slits to three, the amount of energy in the total interference
pattern increases by 50% (three slits worth of light instead of two), but the peak intensity of the
interference maxima…
arrow_forward
6. The solar emission
spectrum shown to
the right is broad,
meaning light is
emitted over the
Solar Emission Spectrum
4500
4000
entire visible region
of the
electromagnetic
spectrum, but it also
has "dips" in the
intensity. Search the
web for "Fraunhofer
3500
3000
2500
2000
1500
1000
500
lines" and describe
the cause of these
"dips" in intensity.
What specifically is
the cause of the
large "dip" at -760
nm?
200
400
600
800
1000
Wavelength (nm)
Intensity
arrow_forward
Wavelength
nm
Color
me
400
*****************
100004
B
Editor Suggestions: Showing
10
450
Q Search
525
1. Describe the relationship between color and wavelength.
580
Yellow
BOL
600
Am
3. Use this to explain which color slows down the most in a glass block
hp
B
2. Looking at the spectrum produced by the prism, which colour is bent more?
M
E
650
I
700
arrow_forward
Question 2
arrow_forward
List down applications of wave-based light.
What does a scattering of light mean?
Search about the Tyndall effect. Explain its importance.
arrow_forward
2. If horizontally polarized light hits a 2/4 plate at an angle of 23° from its fast axis. What is the Jones
Vector for the polarization of light after the 2/4 plate? What device(s) would you need to place after
the 2/4 plate to produce vertically polarized light? If the initial horizontally polarized light is lo, what is
the intensity of the vertically polarized light?
arrow_forward
Do it asap!
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Which of the following statements are true?7. the bending and spreading of light waves is known as interference8. laser emits a range of colors9. waves diffract as they meet other wave
arrow_forward
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