Lab4-Capacitors
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Dec 6, 2023
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Capacitors
NAME: ____Sehajpartap Gill_______________
Date: ____7/19/2021______
Lab Partner’s: _______(No Contact, Worked Solo)______________
Access the University of Colorado’s PhET simulation:
Capacitor Lab
OBJECTIVES
:
To understand how capacitance varies with the separation between the plates
To understand how capacitance varies with the area of the plates
To understand how the dielectric affects the stored charge, energy, and voltage between the
plates of the capacitor, when it is connected or disconnected from the battery
BACKGROUND:
When a capacitor is connected to an EMF (
E
), the plates attain charge from the
terminals of the battery.
The amount of charge is governed by the geometry of the capacitor.
For a parallel plate capacitor, the capacitance is given by
0
A
C
K
d
where
A
is the effective plate area (the area effectively overlapping,
d
is separation of the plates,
o
is electric permittivity of free space, and
K
is the dielectric constant for the insulating material
in the inner plate region.
In this lab, you will investigate this relation.
First you will keep the separation constant and vary
the area.
In this case, a plot of
C
vs
A
should be a straight line with the slope given by
0
1
K
m
d
Then, you will keep the area constant and vary the separation.
Here, a plot of
C
vs
1
d
should be
a straight line with the slope given by
2
0
m
K
A
INSTRUCTIONS:
Use Excel to plot the graphs and insert or attach
all
graphs, plots, and tables to
this lab assignment. Convert values to SI units and show
all
your calculations.
PROCEDURE:
Open the simulator and select the middle tab:
Dielectric
.
PART I: Capacitance
1)
Select “paper” from the choice of dielectrics in the menu on the right-hand side. Use the
horizontal double-tip arrow to
insert
the dielectric
completely
inside the capacitor. Check
“Capacitance” to see the capacitance meter. The battery could be either connected or
disconnected for this part.
NOTE
:
The exponent of the value shown below the capacitance meter should be
negative.
Common capacitor values are of the order of pF or
m
F. Use negative
exponents to obtain the correct values.
2)
Record the values of the plates’ area
A
0
(initially, it should be the smallest possible),
distance between the plates
d
0
(initially, it should be the largest possible), and
corresponding capacitance.
3)
Use the diagonal double-tip arrow to slowly
increase
the plates’
area
and measure the
corresponding capacitance 4 more times. Record your results in the table, include units. It
is recommended to use SI units for all measurements and calculations.
4)
Use Excel to
plot
capacitance as dependent variable against the area. Then, use linear
regression to draw the best-fit line (also called trendline) to approximate the data with
the linear model.
Insert
a screenshot of your graph below. It should contain:
2
A
C
0
100.0 mm^2
.89 x 10^-13 F
1
152.9 mm^2
2.39 x 10 ^-13 F
2
250.5 mm^2
5.48 x 10^-13 F
3
311.4 mm^2
7.54 x 10^-13 F
4
400 mm^2
10.62 x 10^-13F
100
152.9
250.5
311.4
400
0.00E+00
2.00E-13
4.00E-13
6.00E-13
8.00E-13
1.00E-12
1.20E-12
f(x) = 0 x − 0
Capacitance Vs. Area Plot
Area (mm^2)
Capacitance (F)
3
Your preview ends here
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Related Questions
Find the energy density of the capacitor using two differerent methods
arrow_forward
True or False
__________1.The insulating material sandwiched between two plates of a capacitor is
known as a dielectric.
__________2. Capacitance is directly proportional to the voltage and is expressed in units of
farads.
__________3. A capacitor with a higher relative permittivity would yield a greater
capacitance.
__________4. A parallel-plate capacitor that stores 3.0 coulombs of charge connected to a
1.2-volt battery can produce a capacitance of 0.4 farads.
__________5. The relative permittivity of a dielectric material such as air is equal to 1.
__________6. The unit of farad can also be expressed in volts per coulomb.
__________7. A 2.0-farad capacitor connected to a 12.0-volt battery can store a charge of
0.2 coulombs.
__________8. Capacitance is directly proportional to the area but inversely proportional to
the separation distance between plates
arrow_forward
True or False
__________1.The insulating material sandwiched between two plates of a capacitor is
known as a dielectric.
__________2. Capacitance is directly proportional to the voltage and is expressed in units of
farads.
__________3. A capacitor with a higher relative permittivity would yield a greater
capacitance.
__________4. A parallel-plate capacitor that stores 3.0 coulombs of charge connected to a
1.2-volt battery can produce a capacitance of 0.4 farads.
__________5. The relative permittivity of a dielectric material such as air is equal to 1.
__________6. The unit of farad can also be expressed in volts per coulomb.
__________7. A 2.0-farad capacitor connected to a 12.0-volt battery can store a charge of
0.2 coulombs.
__________8. Capacitance is directly proportional to the area but inversely proportional to
the separation distance between plates
__________9. More charges are stored in a capacitor of higher capacitance.
__________10.The capacitance of a parallel…
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Physics Question: Please take a look at this question and answer the following! Thank you so much!
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In the figure below, find the equivalent capacitance of the combination. Assume that C1 = 13.0 µF, C2 = 6.00 µF, and C3 = 3.00 µF. _________________________µF
arrow_forward
6:20 *
K/s
expert.chegg.com/e
3
= Chegg
Time remaining: 00:09:38
Physics
You have two capacitors, one with capacitance 17.5 x 10-6F and the other of unknown capacitance. You connect the two
capacitors in series with a voltage of 357 V applied across the capacitor pair. You discover that, as a result, the unknown
capacitor has a charge of 0.00183 C. Find its capacitance C.
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For the configuration shown in the figure:
C1
C2
C3
If the fem source is 120 V, C1= 21 µF, C2= 8 µF and C3= 16 µF. The equivalent capacitance of the
assembly is:
a) Ceg = 11.2 µF
b) Ceq = 0.0893 µF
c) Ceg = 55 µF
d) Ceg = 59.7333 µF
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Q/A capacitor whose Capacitance is ( 2uf) and the
distan ce between its plates is (o.1 mm) is
charged
0ITh a Source of potent ial difference C30 volt)
1- Calculate the charge of the capacitor and
the
magnitude of the electric field between
its two plates.
2- If the capacitor is separa ted from
the Source amd an insulator is inserted between
its
two plates , the stored energy in the
electric field be Comes ( 3*10 ) Calc u late
-4
the potential difference of the Capacitor
after placing the insulator and the
dielectric Constant of the insulating
material ?
arrow_forward
.ull Asiacell ?
ÖS 2:24
@ %75
A docs.google.com
LICU CT
(Experimental)
Required
Select the true answer:
1. The capacitor voltage (VC) in the of
discharging at a specific value of time t = T =
RC [d.c. Voltage Supply (ɛ)= 10 volts] is
6.3 V
14.14 V.
7.07 V.
3.7 V.
This is a required question
2. When will be capacitors fully charged? *
When the supply voltage is equal to the
capacitor voltage.
When voltage is infinity.
arrow_forward
18
arrow_forward
True or False
1. When a capacitor is DISCHARGING, the charge on the plates builds up gradually to its equilibrium value of q0 = CV0 where V0 is the voltage of the battery.
2. Ohm times a farad is EQUAL to seconds.
3. When a capacitor is CHARGING, the magnitude q of the charge on the plates at time t is q= q0 [1 - e^(- t/RC) ]
4. The equivalent capacitors stores the same amount of charges but NOT THE SAME amount of energy when connected in PARALLEL.
5. A small time constant means that the capacitor charges and discharges VERY SLOWLY.
6. A good voltmeter is designed with a VERY LARGE resistance for it not to alter the voltage in the circuit when connected.
7. Time constant is equal to R / C.
8. A good ammeter is designed with a VERY SMALL equivalent resistance to avoid reduction of current when connected in a circuit.
Explain how lightning is produced and the mechanism of lightning rods.
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-Use numbers when answering, rouding to the hundredths in the format 0.00
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X 5.65
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EMF = Vo = 6 volts. and C = 5 μF
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