PHY 211 Lab 4 Forces in Equilibrium fully complete by everyone

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University of Kentucky *

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211

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Physics

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Dec 6, 2023

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xlsx

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1

Uploaded by daltonshepler

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ PI Name DA Name R Name ~ Carlie ArlinghausDalton Shepler N'Diah Jones ~ ~ M1 (g) δM1 F1 M2 (g) δM2 F2 ~ 180 99.95 0.05 979.51 20 50 0.05 490 M3_min (g) M3_max (g) F3min F3max F3_measured δF3 52.95 53.05 518.91 519.89 519.4 0.49 346.5 0.5 ~ ~ ~ X component Y component ~ F1 -979.51 1.20004516307E-13 F3x F3y F3_calc δF3 ~ F2 460.4493841851 167.589870229578 519.0606 -167.58987023 545.44503618 -0.9559665 342.1062 0.047428776134412 ~ ~ DA 1: Include the two scatter plots that compare the magnitudes and angles. These charts should have titles, axes, labels, units, etc, as shown in Figure 2. ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ F1x_max F1x_min F2x_max F2x_min F1y_max F1y_min F2y_max F2y_min F3x_max F3x_min F3y_max F3y_min ~ -979.02 -980 460.90983356928 459.9889 1.2006455E-13 1.199445E-13 167.75746 167.4223 520.01106519909 518.11016643 -167.4223 -167.7575 ~ F3x F3y F3_min F3_max F3 δF3 θ3max θ3min 519.06061581491 -167.58987023 546.401018802702 544.4891 545.445052285 -0.955966518 -17.846434 -17.94129 -17.8938626344282 0.0474287761 ~ ~ Researcher: Explain in detail how your group determined θ_max and θ_min. ~ ~ Large surface area ~ ~ θmax θmin μs_large max μs_large mμs_large δμs ~ 17.5 16.5 1.51371554438863 1.510264 1.5119899257 0.0017256187 ~ ~ ~ Medium surface area ~ ~ θmax θmin μs_Medium max μs_Mediumμs_Medium δμs ~ 12.5 11.5 1.49096634108266 1.484058 1.4875121646 0.0034541765 ~ ~ small surface area ~ ~ θmax θmin μs_small max μs_small mμs_small δμs ~ 11.5 10.5 1.48405798811891 1.475845 1.47995130429 0.0041066838 ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ Large surfa 1.51199 ~ medium su 1.487512 ~ small surfa 1.479951 ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ Researcher: Create a careful scale drawing, similar to Figure 1, of the three forces, F_1,F_2, and F_3 that you have selected. Then create a second figure where these forces are rearranged without changing the magnitudes or directions so they follow the “tip-to-tail” method of addition of vectors. Explicitly explain the concept(s) which connect(s) your drawing to Newton’s Second Law. Experimental Determination of F 3 and θ 3 θ 1 θ 2 θ 3_measured δθ 3 Calculation of F 3 and θ 3 F 3 theory θ 3 _calc δθ 3 θ 3 δθ 3 We adjusted the inclined plane for the wooden block until it slid down. Then proceeded repeat this procedure five times, we were able to see in our data, the lowest and highest angles possible that would cause the wooden block to slide down the plane. DA2: One striking feature of Figure 2 is the fact that the “Measured” points have error bars that are much larger than the “Calculated” points. Highlight rows 31 through 37, right-click, and select “Unhide.” Use these additional cells to determine why the “Measured” results have uncertainties that are so much bigger than the “Calculated” results. Ultimately you want to determine which cells in row 5 control the size of the error bars for each type of result. The cells that include everything with the angle of F2. Since F1 Contributes nothing to the x direction, then F2 should be what is making the error bars for figure 2 bigger than the calculated version. DA: Create a scatter plot to compare μs based on the surfaces in contact. Label all axes. In your caption, comment on whether the three μ measurements agree or not. PI: Using the charts provided by the DA, explain why the measured and calculated values of F_3 and θ_3 overlap or not. In your explanation, use terms such as overlap and error bars etc. The error bars do not overlap showing that there is a significant difference in values. The measured and calculated values do not overlap because they represent separate things so they are not similar, hence them not overlapping. PI: Using the chart provided by the DA, explain whether μs depends on the surface area of the wooden block. In your explanation, use terms such as overlap and error bars etc. The μs doesn't seem to depend on the surface area as all three values are around the same, ranging from 1.48-1.51, based on the data from the chart created by the DA. Because surface area doesn't play a role in determining the force caused by friction, that static coefficient shouldn't depend on the surface area of the block. Between the medium and small surface areas, the error bars overlap, showing that there is not a significant difference in these values. This helps to give evidence to support that the μs doesn't depend on surface area, since the differences aren't significant. PI: The formula μ_s≥tanθ relies on the fact that there are exactly three forces involved on the incline plan, which form a triangle in exactly the same way that the Researcher described at the end of part 1. Build upon the Researchers work within the context of static friction to determine WHY μ_s≥tanθ. No the three measurements do not agree. The measurements are suppose to be different due to the different amounts of surface area. When something is on a ramp, "creating a triangle", due to the laws of static friction, the coefficient of static friction is going to be the same as the tangent of an angle. Therefore, in order for the formula μ_s≥tanθ to work, there needs to be exactly three forces, so the coefficient must be greater than tanθ so that this triangle can be formed with the ramp. 0.8 1 1.2 1.4 1.6 1.8 2 339 340 341 342 343 344 345 346 347 342.106211535916 346.5 Angle difference between calc & measured θ3_measured θ3_calc Degrees 0.8 1 1.2 1.4 1.6 1.8 2 505 510 515 520 525 530 535 540 545 550 545.445036180287 519.4 Difference of magnitude between calc & measured F3_measured F3_calc Magnitude of orce 0.8 1 1.2 1.4 1.6 1.8 2 1.46 1.47 1.48 1.49 1.5 1.51 1.52 Static Coefficient Large surface area medium surface area small surface area µs 0.8 1 1.2 1.4 1.6 1.8 2 505 510 515 520 525 530 535 540 545 550 545.445036180287 519.4 Difference of magnitude between calc & measured F3_measured F3_calc Magnitude of orce 0.8 1 1.2 1.4 1.6 1.8 2 339 340 341 342 343 344 345 346 347 342.106211535916 346.5 Angle difference between calc & measured θ3_measured θ3_calc Degrees I decided to move F2 and F3 because it was easier to make these connections “tip to tail” without disrupting the direction and magnitudes of the vectors. Considering F2 and F3 are similar in size and direction its best we make those conections to F1. This is the perfect representation of newtons second law, the F1=F2+F3 for both mass and forces.
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