The Simple Pendulum_Hypothesis Testing_PHYS 130
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The Simple Pendulum
Purpose:
To investigate how the period of a pendulum is affected by its mass, angle of swing, and length.
Discussion The simple pendulum is of historic and basic importance. Its regular swing, discovered by Galileo Galilei, makes it an accurate and simple timekeeper and, in the hands of Isaac Newton, resulted in the first evidence that inertial and gravitational masses are proportional. Until relatively recently, the motion of a pendulum provided the most accurate and convenient method for measuring the local gravitational pull of the Earth. Although “pendular” motion had been likely observed for centuries, Galileo (1564-1642) was intrigued by the back
and forth motion of a suspended weight. Legend has it that he began his studies of pendulums after watching a
ceiling lamp swing back and forth in the cathedral of Pisa (no doubt during a particularly long winded sermon!) Using his pulse
to time the motion of the swinging lamp, the crude measurements indicated the period (the amount of time required for one
swing) remained constant although the swinging motion varied as time passed. The motion of the pendulum bob posed interesting problems. What causes it to swing back and forth? What keeps it moving
after it is released? Which factors influence the time it takes to complete one swing (called the period)? Throughout his
experimental work, the pendulum was never very far from Galileo's thought. Although he did not address the first two
questions, he did figure out the third which led to the development of the pendulum clock, although it would take another 60 –
70 years before it became a practical time keeping device.
Model Testing
When setting up a simple pendulum, you have three variables you can adjust: (1) the bob mass, (2) the pendulum length, and (3) the pendulum swing amplitude (
θ
). The “physics analysis” of the motion of the simple pendulum as it swings forth and back makes the following
prediction for the period measurement:
T
=
2
π
√
L
g
In this model,
T ≡ period ,L≡length,
∧
g≡gravity constant
.
You can see that the model predicts
that the period is independent of the amplitude of the swing (
θ
) and the mass of the pendulum bob (
m
). But under what conditions, if any, is this model valid? It is your goal to test the limits of this model to discover when it is appropriate to use in an experimental setting. (That is, when can we use the formula to get reliable and valid results from measurements made in an experimental system?)
Link for online simulation:
https://phet.colorado.edu/sims/html/pendulum-lab/latest/pendulum-lab_en.html
PROCEDURE: When the pendulum simulation has opened “Click” on the lab window .
Click on Period Timer. Make sure that speed is set to Normal and Friction (slider) is set to None.
To get a period measurement, simply pull the pendulum to the side and release it. Click on the period timer to get the measurement.
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Related Questions
Then we have:
In an oscillatory motion of a simple pendulum, the ratio of the maximum angular
acceleration, O"max, to the maximum angular velocity, O'max, is 2Tt s^(-1). What is
the time needed for the pendulum to complete two oscillations?
4 sec
0.25 sec
O 2 sec
1 sec
0.5 sec
Consider a place where the gravity is one-ninth the gravity on Earth (g' = g/9),
then the frequency of oscillation of a simple pendulum in that place, f', as
compared to its frequency on earth is:
f' = f/3
O f' = 2f
O f' = f/2
f' = 4f
f' = 9f
hp
arrow_forward
The distance of a swinging pendulum from its resting position is given by the function dit)
= 5.5cos(8), where the distance is in inchès and the time is in seconds. Once released, how
long will it take the pendulum to reach its resting position? Round your answer to the
nearest hundredth.
arrow_forward
QUESTION 5
the following equation refers to V-pendulum experiment
T4 = (44 L k/g²)(8 m4L/g² )d, where :
L: length of the string (2 meters).
T: pendulum periodic time
d: distance between rods
k: pendulum constant
g: gravitational acceleration
Given that the slope of the graph (T4,d) = -14.2 s4/m, and y-intercept-13.5 s4,
Find the value for K:
1.91 m
O 2.00 m
O 19.1 m
2.10 m
arrow_forward
need asap please
arrow_forward
A conical pendulum has length / and the angle made by the string with vertical is 0 = 38° . The mass of the object is m=140 g. If the period of the circula
motion of the object is T=1.74s find the length of the string. Take g=10m/s. Round your answer to two decimal places.
m
arrow_forward
Not 81930449@students.liu.edu.lb? Switch account
15 MCQS
In an oscillatory motion of a simple pendulum, the ratio of the maximum angular
acceleration, e"max, to the maximum angular velocity, O'max, is t s^(-1). What is
the time needed for the pendulum to complete two oscillations?
0.5 sec
1 sec
O 4 sec
2 sec
0.25 sec
arrow_forward
QUESTION 3
- The following equation refers to v-pendulum experiment:
T4 = (4x4 Lk/g²)(8 n4L/g² )d, where:
L: length of the string (2 meters).
T: pendulum periodic time
d: distance between rods
k: pendulum constant
g: gravitational acceleration
Given that the slope of the graph (T4,d)= -14.2 s4/m, and y-intercept -13.5 s4,
Find the value for g:
9.81 m/s²
Can't be defined
a- 8.51 m/s2
10.5 m/s2
arrow_forward
If one oscillation has 6.5 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes?
Express your answer using two significant figures.
A high energy/A low energy =
arrow_forward
A simple pendulum has a period of oscillation of 2.20 seconds. What is its length
Use g = 9.8 m/s/s
Give your answer in meters to 2 decimal places.
arrow_forward
How would you relate Simple Harmonic Motion to Law of Universal Gravitation? Explain in words.
arrow_forward
1010 Please include a diagram in your answer:
The maximum speed of the pendulum bob in a grandfather clock is 0.55 m/s. If the pendulum makes a maximum angle of 8.0◦ with the vertical, what is the length of the pendulum?
arrow_forward
Write down the expression for period of a pendulum of length I and the gravitational field strength g. Please use
Il * II
for products (e.g. B*A), "/"
for ratios (e.g. B/A) and the usual "+" and "-" signs as appropriate. For square root and power please use sqrt(A*B) and (A*B)^2. Please use the
"Display response" button to check you entered the answer you expect.
T=
arrow_forward
A simple pendulum has a length of 1.3
meters. What is its period of oscillation?
Use g = 9.8 m/s/s
Give your answer in seconds to 1 decimal
place.
arrow_forward
vezsion1.
Question 1:
A mass m attached to a horizontal spring of spring constant k is oscillating on a frictionless
surface. If this mass-spring system makes 180 oscillations during a time interval of 6 minutes,
then the frequency of oscillations is:
arrow_forward
A 10-kg steel ball is tied to a string attached to a ceiling. If the length of the string is 45 cm, a) what is the time it would take the steel ball to complete one cycle? b) If the mass of the metal ball is doubled, what will be its period?Note: Answer it using GAFSA Format (Given, Asked, Formula, Solution, Answer)
arrow_forward
Note the square of the period of oscillation for a hanging mass of 151.2 g is 0.937s^2..... (calculate it to get more decimals)
arrow_forward
You will fire the spring gun 3 times from the first detent and measure the change in height of the (pendulum + ball) for each shot. Write the equation for the change in height of the first shot.
arrow_forward
If the period of a pendulum on another planet is four times its period measured on Earth, what is the gravitational acceleration on the planet? Show the equation used and your calculations.
arrow_forward
University of Technology an
Tn Experiment 6: Simple Pe X
A https://moodle.nct.edu.om/mod/quiz/attempt.php?attempt3D713034&cmid%3D76215
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(Please Note: Trial 1 and Trial 2 values are given for 20 oscillations)
Table 1: Calculation of acceleration due to gravity (keeping mass and amplitude constant)
Pendulum
Square of
Trial Trial
Time Period
Mean
L/T2
length
1
2
Time period
(s)
T (s)
(m/s)
L (cm)
(s)
(s)
T? (s²)
50
28.4 28.3
55
29.7 29.9
60
31.1 31.0
65
32.3 32.4
70
33.6 33.5
Mean value of
Calculated value of
L/T?
g
(m/s)
(m/s²)
to search
arrow_forward
A watch hanging from a chain swings back and forth every 0.7 seconds . What is the frequency of its oscillations ? Calculate answer to one decimal .
arrow_forward
Can you solve it plz
arrow_forward
Give the expression for the frequency ?f of a simple pendulum of length ?L in the gravitational field strength ?g. Use the following notation (without the quotes): "/" for division, "*" for multiplication, "+" an "-" as usual. For powers used "^2", while for square root use "sqrt". To indicate that square root applies to the whole expression use brackets - for example, for ??‾‾‾‾√AB use sqrt(A*B). For Greek letters such as ?π, ?α etc. use pi, alpha. For example to get 1??2???‾‾‾‾√1πA2BAB use 1/pi*A^2/B*sqrt(AB). Please use the exact variables given in the conditions of the problem: e.g if ?L is given, then do not use ?l.
arrow_forward
Kindly check the answer before submitting the solution. Answer is also mentioned in picture containing the question.solution for this question provided recently was incomplete and wrong. Kindly ensure proper solution.
arrow_forward
0.1 sec
In an oscillatory motion of a simple pendulum, the ratio of the maximum angular
acceleration, O"max, to the maximum angular velocity, O max, is rt s^(-1). What is
the time needed for the pendulum to complete two oscillations?
0.25 sec
2 sec
04 sec.
0.5 sec.
)1 sec
Constder a place where the gravity is 4 times the gravity on Earth (g 4g), then
the frequercy of oscillation of a simple pendulum in that place. f. as compared
O O00
arrow_forward
Could a standard of time be based on the period of a certain standard pendulum? What advantages and disadvantages would such a standard have compared to the actual present-day standard
arrow_forward
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Related Questions
- Then we have: In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, O"max, to the maximum angular velocity, O'max, is 2Tt s^(-1). What is the time needed for the pendulum to complete two oscillations? 4 sec 0.25 sec O 2 sec 1 sec 0.5 sec Consider a place where the gravity is one-ninth the gravity on Earth (g' = g/9), then the frequency of oscillation of a simple pendulum in that place, f', as compared to its frequency on earth is: f' = f/3 O f' = 2f O f' = f/2 f' = 4f f' = 9f hparrow_forwardThe distance of a swinging pendulum from its resting position is given by the function dit) = 5.5cos(8), where the distance is in inchès and the time is in seconds. Once released, how long will it take the pendulum to reach its resting position? Round your answer to the nearest hundredth.arrow_forwardQUESTION 5 the following equation refers to V-pendulum experiment T4 = (44 L k/g²)(8 m4L/g² )d, where : L: length of the string (2 meters). T: pendulum periodic time d: distance between rods k: pendulum constant g: gravitational acceleration Given that the slope of the graph (T4,d) = -14.2 s4/m, and y-intercept-13.5 s4, Find the value for K: 1.91 m O 2.00 m O 19.1 m 2.10 marrow_forward
- need asap pleasearrow_forwardA conical pendulum has length / and the angle made by the string with vertical is 0 = 38° . The mass of the object is m=140 g. If the period of the circula motion of the object is T=1.74s find the length of the string. Take g=10m/s. Round your answer to two decimal places. marrow_forwardNot 81930449@students.liu.edu.lb? Switch account 15 MCQS In an oscillatory motion of a simple pendulum, the ratio of the maximum angular acceleration, e"max, to the maximum angular velocity, O'max, is t s^(-1). What is the time needed for the pendulum to complete two oscillations? 0.5 sec 1 sec O 4 sec 2 sec 0.25 secarrow_forward
- QUESTION 3 - The following equation refers to v-pendulum experiment: T4 = (4x4 Lk/g²)(8 n4L/g² )d, where: L: length of the string (2 meters). T: pendulum periodic time d: distance between rods k: pendulum constant g: gravitational acceleration Given that the slope of the graph (T4,d)= -14.2 s4/m, and y-intercept -13.5 s4, Find the value for g: 9.81 m/s² Can't be defined a- 8.51 m/s2 10.5 m/s2arrow_forwardIf one oscillation has 6.5 times the energy of a second one of equal frequency and mass, what is the ratio of their amplitudes? Express your answer using two significant figures. A high energy/A low energy =arrow_forwardA simple pendulum has a period of oscillation of 2.20 seconds. What is its length Use g = 9.8 m/s/s Give your answer in meters to 2 decimal places.arrow_forward
- How would you relate Simple Harmonic Motion to Law of Universal Gravitation? Explain in words.arrow_forward1010 Please include a diagram in your answer: The maximum speed of the pendulum bob in a grandfather clock is 0.55 m/s. If the pendulum makes a maximum angle of 8.0◦ with the vertical, what is the length of the pendulum?arrow_forwardWrite down the expression for period of a pendulum of length I and the gravitational field strength g. Please use Il * II for products (e.g. B*A), "/" for ratios (e.g. B/A) and the usual "+" and "-" signs as appropriate. For square root and power please use sqrt(A*B) and (A*B)^2. Please use the "Display response" button to check you entered the answer you expect. T=arrow_forward
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SEE MORE QUESTIONS
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Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning