PC141-PC161 final exam solutions (2) (2)
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Physics
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Jan 9, 2024
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PC 141/PC161, Dr. Maher Ahmed, closed book exam, 10 questions, the calculator is allowed
Question 1
You throw a stone vertically upward with an initial speed of 10 m/s from a third-
story office window. If the window is 10m above the ground, find the
total time
the
stone will take to reach the ground.
-10=10t-0.5*9.8*t
2
t
=
−
10
±
√
10
2
+
4
∗
4.9
∗
10
−
2
∗
4.9
=
2.78
sec
Question 2
Ilya can run at a speed of 6m/s and walk at a speed of 2m/s .On a route of length 8 m.
Ilya walks
half of the time
and runs the other half. How long does it take Ilya to cover the distance of 8 m.
(6*t/2)+(2*t/2)=8
8t=16
t=2 sec
Question 3
A stone thrown off a bridge 20 m above a river has an initial velocity 14.14 m/s at an angle of 45
o
above the horizontal. What is the range R of the stone?
V=14.14cos45 x+ 14.14 sin45 y=10 x
+10 y
Y=10t-0.5*9.8t
2
, -20=10t-4.9t
2
t
=
−
10
±
√
10
2
+
4
∗
4.9
∗
20
−
2
∗
4.9
=
3.28
sec
, R=10*3.28=32.8 m
1
PC 141/PC161, Dr. Maher Ahmed, closed book exam, 10 questions, the calculator is allowed
Question 4
A stone thrown off a bridge 20 m above a river has an initial velocity 14.14 m/s at an angle of 45
o
below the horizontal. What is the range R of the stone?
V=14.14cos45 x - 14.14 sin45 y= 10 x
-10 y
Y=-10t-0.5*9.8t
2
, -20=10t-4.9t
2
t
=
10
±
√
10
2
+
4
∗
4.9
∗
20
−
2
∗
4.9
=
1.24
sec
, R=10*1.24=12.4 m
Question 5
In the figure shown below m1
= 141.4kg and m2 = 20kg.
Neglect the friction between
m1
and the table.
After the system begins to move, what is the magnitude and direction of the
acceleration? What is the tension force in the robe?
T-m
2
g=m
2
a, m
1*
sin(45)-T=m
1
a
a=(100-20)*9.8/161.4=
4.86 m/sec
2
in the direction of m1
T=m
2
(g+a)=20*(9.8+4.9)=294N
Question 6
A 1 kg mass is placed on the end of a spring that has a spring constant of 100 N/m. The mass–
spring system rests on a frictionless incline that is at an angle of 30
o
from the horizontal. The
system is eased into its equilibrium position, where it stays. Determine the change in elastic
potential energy of the system.
F=kx=m*g*sin(30), x=mg/2*100, U=(1/2)*k*x
2
=m
2
*g
2
/8k=1*9.8*9.8/800=0.12 Joul
2
PC 141/PC161, Dr. Maher Ahmed, closed book exam, 10 questions, the calculator is allowed
Question 7
A 0.030 Kg bullet with a speed of 500 m/s strikes a target brick of mass 1.0 kg. The brick breaks
into two fragments. The bullet deflects at an angle of 30
o
above the + x axis and has a reduced
speed of 100 m/s. One piece of the brick (0.75 kg) goes off to the right as shown below with
speed 5 m/s. Determine the speed and direction of the other piece of the brick immediately after
the collision.
m
b
V
0
=m
b
V
b
+m
1
V
1
+m
2
V
2
m
b
V
0
=m
b
V
b
cos30+m
1
V
1
+m
2
V
2
cos
θ
2
θ
2
=
¿
0.03
∗
500
−
0.03
∗
100
∗
0.866
−
0.75
∗
5
0.25
=
15
−
2.598
−
3.75
0.25
=
34.608
v
2
cos
¿
m
b
V
b
sin30=m
2
V
2
sin
Ɵ
2
,
θ
2
=
¿
0.03
∗
100
∗
0.5
0.25
=
1.5
0.25
=
6
v
2
sin
¿
Tan
θ
2
=0.17
θ
2
=
9.8
degrees
,
v
2
=
35.25
m
/
s
Question 8
Three masses 2.0 kg, 3.0 kg and 5.0 kg are located at positions (3.0, 0), (6.0,0), and (-4.0, 0),
respectively, in meters from the origin where is the center of mass of this system?
3
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