The purpose of the experiment is to determine the chemoselectivity of different reducing agent or reductant by reducing 3-nitroacetophenone with tin and hydrochloric acid. For this research, 3.45g of tin granular was put into a 100mL of round bottomed conical flask attached to a reflux condenser; then add 1.6585g of 3-nitroacetophenone and 24mL of water. Heat the mixture over oil bath for 90 minutes. At the end of the process, 0.4115 grams of final product were obtained giving a percent yield of 30%. Analyzing tests including melting point determination, IR Spectroscopy and TLC were done on the final product to analyze the properties of the product. The melting point was found out to be 98.2ᴼC. TLC using solvent system 60% ethyl acetate and …show more content…
Reduction reaction means gain of hydrogen atoms whereas oxidation reaction includes a gain in oxygen atoms. In this experiment student will do a reduction of 3-nitroacetophenone by tin and hydrochloric acid.
In this experiment, the substrate, 3-nitroacetophenone has two potential functional groups for reduction such as a ketone (C=O) group and a nitro (NO2) group. Several conditions may favor in the reduction of the ketone group whereas the other leads to the reduction of the nitro group. For every redox reaction, a reducing agent will always be used. A reducing agent, also known as electron donor is one that loses and is oxidized during the process. For this experiment, student will do a reduction experiment on 3-nitroacetopheone by using tin as the reducing agent.
To determine the identity of the final product, it is significant to determine the Infrared bands of the starting material (3-nitroacetophenone). Infrared spectrum can help to gather information, asses the impurity as well as to identify the molecules present in a compound. In this experiment, student found out that all the functional groups present in a 3-nitroacetophenone molecule (NO2, OH, C=O, NH2) have polar bonds. These polar bonds when stretched give an increase to important molecular dipole changes and therefore illustrate an intense IR
…show more content…
By this, student would be able to classify how the reducing agent selectively reduces one of the two functional groups from the benzene ring. It hypothesized that 3-aminocetophenone is the final product of this reaction.
Set up 3.45g of tin granular into a 100mL of round bottomed conical flask attached to a reflux condenser; working in a fume cupboard, add 1.6585g of 3-nitroacetophenone and 24mL of water. Mix the mixture thoroughly and heat the mixture over oil bath for 1.5 hours. Periodically stir the solution. After all the tin granules are dissolved (not everything will be dissolve due to the different equivalent of reagents) allow the mixture to cool and filter it under vacuum using Buchner funnel.
Carefully add 20mL of aqueous sodium hydroxide to the filtrate, with external cooling (ice-water bath) and continuous stirring. Re-filter the solution under vacuum and collect the resulting yellow precipitate using Buchner funnel. Dissolve the product under 50mL of boiling water, filter while hot and allow the mixture to cool. Collect the crystals obtained and dry them by
The objective of this lab was to create a ketone through an oxidation reaction using a using a secondary alcohol and oxidizing agent in order to use that ketone in a reduction reaction with a specific reducing agent to determine the affect of that reducing agent on the diastereoselectivity of the product. In the first part of this experiment, 4-tert-butylcyclohexanol was reacted with NaOCl, an oxidizing agent, and acetic acid to form 4-tert-butylcyclohexanone. In the second part of this experiment, 4-tert-butylcyclohexanone was reacted with a reducing agent, either NaBH4 in EtOH or Al(OiPr)3 in iPrOH, to form the product 4-tert-butylcyclohexanol. 1H NMR spectroscopy was used to determine the cis:trans ratio of the OH relative to the tert-butyl group in the product formed from the reduction reaction with each reducing agent. Thin-layer chromatography was used in both the oxidation and reduction steps to ensure that each reaction ran to completion.
Oxidation is a key reaction in organic chemistry. Oxidation of an alcohol can produce aldehydes,
The purpose of this laboratory experiment is for an aromatic compound to undergo an electrophilic substitution reaction. To carry this out, our method combines sodium iodide and common bleach as the oxidizing agent in aqueous alcohol as the solvent.
The purpose of this experiment was to synthesize the Grignard reagent, phenyl magnesium bromide, and then use the manufactured Grignard reagent to synthesize the alcohol, triphenylmethanol, by reacting with benzophenone and protonation by H3O+. The triphenylmethanol was purified by recrystallization. The melting point, Infrared Spectroscopy, 13C NMR, and 1H NMR were used to characterize and confirm the recrystallized substance was triphenylmethanol.
The Purpose of this experiment is for the students to learn how to use sodium borohydride to reduce benzil to its secondary alcohol product via reduction reaction. This two-step reaction reduces aldehydes by hydrides to primary alcohols, and ketones to secondary alcohols. In order for the reaction to occur and to better control the stereochemistry and yield of the product, the metal hydride nucleophile of the reducing agents such as LiH, LiAlH4, or NaBH4 must be carefully chosen. Being that LiAlH4 and NaBH4 will not react with isolated carbon-carbon double bonds nor the double bonds from aromatic rings; the chosen compound can be reduce selectively when the nucleophile only react with
21) After all of the solid dissolves, move the flask from the hot plate and allow it cool to room temperature. After a while, crystals should appear in the flask.
Working in the hood or a designated work area, add about 1 mL of ethyl alcohol to a clean evaporating dish. Place the evaporating dish on a heat- resistant pad.
15) Wash the residue three or four times using about 5-10 mL of distilled water. No residue of blue color should remain in your silver crystals.
The Oxidation of a Secondary Alcohol with Sodium Hypochlorite experiment was performed to show how to change an unknown alcohol into a ketone. The unknown that was found for this experiment was Compound A. Once the ketone was found from the unknown alcohol, an IR and the boiling point was taken to try and figure out what the product and starting alcohol actually is. The first thing that is added to the 1.50 g of unknown compound A is 15 mL of 8.25% of NaOCl, which is a bleach solution. This reacted with the alcohol so the solution could then be tested using the iodide-starch paper. The reaction came out positive when tested because a blue, black spot appeared on the strip.
Tube 4 now should only have crude solid in the tube and it is then weighed. The tube is placed into a 50℃ water bath and then approximately 0.5 -1 ml of methanol is added, as well as H2O until the solution gets cloudy, once the solution is dissolved it is cooled to room temperature and then iced. The crystals are then collected using a Hirsh funnel. Next a small amount (~ 0.1g) of the crystals are placed into a melting point tube and placed into the melting point machine to record the unknown neutral substances melting point.
There are four main regions of IR absorptions: region 4000 – 3000 cm-1 corresponds to N-H, C-H and O-H stretching, region 2250- 2100 cm-1 is triple-bond stretching , region 2000- 1500 cm-1 is double bonds and the region below 1500 cm-1 is the fingerprint region where a variety of single bonds are absorbed.3 The chromic acid test is a test for oxidizability and gives a positive result for primary and secondary alcohols as well as aldehydes2. A positive result in the chromic acid test is indicated by a color change and the formation of a precipitate. Tertiary alcohols give negative results for the chromic acid test since there must be a hydrogen present on the alcoholic carbon for oxidation to occur. The 2,4 DNP test, tests for a carbonyl and is therefore a dependable test for aldehydes and ketones. Finally, 13C NMR spectroscopy is a test to determine the structure of a compound. 13C NMR detects the 13C isotope of carbon. Each carbon has a different chemical shift. A carbon’s chemical shift is affected by the electronegativity of nearby atoms. Carbons that are bonded to highly electronegative atoms resonant downfield because the electronegative atom pulls electrons away from the nearby carbons and cause those carbons to resonant downfield1 (John McMurry, 2008). A general trend is that sp3-hybridized carbons absorb from 0 to 90 ppm, sp2-hybridized carbons resonant between 110
The pipet was put into the top of the condenser and leaving no open spaces. The vacuum served to get rid of the nitrogen oxide gases that were formed during the oxidation reaction. The solution was heated for 30 minutes, beginning the time when the first sign of nitrogen oxide fumes were observed. After the 30 minutes, the solution was removed and cooled for a few minutes. The solution turned was a brownish-yellow color and all the crystal were dissolved, leaving a liquid. The solution was then transferred, using a Pasteur pipet, to 3 mL of water in a beaker. The reaction flask was rinsed to remove the remainder of the solution. The solution was stirred with a glass rod until room temperature of the solution was achieved. A yellow solid was to form, but instead the solution remained aqueous in the case of the specific experiment explained here. With additional scraping of the solution with a glass rod, no crystals formed at all. The next procedure, if the crystals had formed was to crush the solid with the glass rod and filter the solid until the crystals were dry. The mass would then be weighed and the crystals were to be recrystallized with 95% ethanol. The crystals were to be cooled in ice water to get full crystallization and then the crystals were to be filtered and air dried, then weighed.
Before the start of the experiment, the theoretical yield was to be calculated. First, the limiting reagent was determined from the reagents by comparing the amount of moles. Among the three reagents involved in this experiment - camphor, sodium borohydride, and methanol, camphor was found to be the limiting reagent. The moles of camphor was less than the combined moles of the other two reagents. The theoretical yield, which is the amount of product that could be possibly produced after the completion of a reaction (“Calculating Theoretical and Percent Yield”), was found to be 0.25 g. Once the product was achieved, a percent yield of 97% was determined. As a result, the reduction of camphor to isoborneol was successful.
3. Add 25 mL of 10% MgSO4 . 7H2O solution to the filtrate. Then add approximately 75 mL of 2M NH3 slowly while stirring. A white precipitate of MgNH4PO4 . 6H2O will form. Allow the mixture to sit at room temperature for 15 minutes to complete the precipitation.
In this experiment it is aimed to synthesize benzopinacol through photochemical reaction of benzophenone and, benzopinacolone via acid-catalyzed rearrangement of benzopinacol. In this experiment, mixture of benzophenone, isopropyl alcohol and a drop of glacial acetic acid was exposed to sunlight which in turn, undergone photochemical reaction. In this reaction, molecules of benzophenone was brought to n((* triplet state where it possibly abstracted hydrogen from isopropyl