Abstract
This laboratory involved utilizing equipment to dilute a sugar water solution. It also created solutions containing varying levels of concentrations and densities. Equations were used to figure the molecular weight of the sugar, and the number of moles of sugar in the volumetric flask. There was also an equation to figure the Molarity, as well. As a result of the experiment, I now have a better understanding of the density of a concentration, and what Molarity is .
Observations
Data Table 8: Initial Concentration
Chemical Mass (g) Molecular Weight (g) Moles in Volumetric Flask Total Volume (L) Molarity (mol/L)
Sugar (C12H22O11) 8 331.23 0.02415 25 0.9961
*As a side note, upon researching the molecular weight of sugar, I
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(Molarity is y-axis, Density is x-axis) Questions
H.) How would you prepare 10 mL of a 0.25M HCl solution if 1M HCl was available? How much
1M HCl is needed? How much distilled water is used?
You would have to dilute 1 M HCl in distilled water to get a less concentrated 0.25 M HCl. To do this, you would have to determine the amount of moles in the final concentration of 10 mL 0.25 M HCl solution by using the formula M1*V1 = M2*V2.
M1*V1 = M2*V2
M1 = 0.25 M
V1 = 10 mL
M2 = 1 M
V2 = M1*V1 / M2 =
0.25 x 10 / 1 = 2.5 mL
A 10 mL solution containing 2.5 mL of 1 M HCl needs to be prepared.
To determine the amount of distilled water to be used, you would need to take the total solution minus the amount of HCl to be used.
10 mL - 2.5 mL = 7.5 mL of distilled water
I. ) From the Excel chart of Molarity vs. Density, what was the relationship between the molarity of the sugar solution and the density of the sugar solution?
From the chart, you can tell that the relationship between the molarity of the sugar solution and the density of the sugar solution vary. It seemed at first that the higher the solution density, the higher the molarity, and the lower the density, the lower the molarity (and vice versa). However, the density appeared to remain the same for several dilutions, but the molarity kept dropping, so one
Procedure: Measure the volume, mass, length and temperature of a variety of items. Create dilution of sugar water.
5. Prepare the salt solution by mixing 1/8 teaspoon of salt and three cups of water in a clean pitcher or 2-liter bottle. Stir or shake the solution until it is dissolved. This will produce a 1% salt solution.
Procedure: I used a ruler, thermometer, and scale to take measurements. I used a graduated cylinder, short step pipet, scale, and ruler to determine volume and density. I used a volumetric flask, graduated pipet, pipet bulb, scale, and glass beaker to determine concentrations and densities of various dilutions.
of sugar to 25ml of water and dissolve it. When we have the water at
H. How would you prepare 10 mL of a 0.25M HCl solution if 1M HCl was available? How much
The Distilled water pH average of HCl for zero drops was 6.67, and the pH for the final thirtieth drop
(0.074 mol HCl x 1 mol NaOH) / 1 mol HCl = 0.074 mol NaOH
In the ADI Molarity Lab, the primary tasks was to use different values of moles of solute, volume of solvent, and molarity to find the mathematical relationships between them. To find these relationships, our group had to change the quantities of each of the variables and visually observe the molarity within the solution. For instance when using Cobalt (II) Nitrate to find the relationship between volume of the solution and the molarity of the solution; the group kept the amount of moles of the solute at a constant of 1.00 moles because if it would have changed it would have caused inaccurate data. We first set the volume of the solution to 0.2 liters. The molarity of the solution was 5.00 mol/L. Then we changed the volume of the solution
The concentration or molarity of a solution can be seen through the ratio of solute amount to solution volume. This means that when you take the solute amount of a solution in moles and divide it by its volumes in liters you are able to find the solution’s overall concentration or molarity. This is proven in my data table below labeled, Molarity Simulation Data, and it helps to show that when you get the moles of a solute and the volume of the solvent you can easily and accurately figure out the molarity of the solution you are investigating. For example, when there were .75 moles of an energy drink power, and only .25 liters of water to mix it in, as shown in #3 of my data table, I was able to identify the molarity as 3 M through the process of division The way I executed this experiment lets me to see the impressionable relationship between the solute amount in moles and the solution volume in liters and how they affect molarity of a solution. The data table allows me to demonstrate this pattern. My argument is, the molarity of an aqueous solution can be found if you take the moles found in a given solute and divide them by the volume of the solvent. The data presented in this paper proves that the given formula shows the dependent, mathematical relationship that all three of these factors
• Serially dilute the 4 mg/ml solution with buffer A to make working solutions of 400 µg/ml and 40 µg/ml.
9. Each of the other solutions is already approximately 0.1 M. With these solutions you can pour a small
Our purpose in this lab was to create four solutions of the same components and different concentration. I found the concentration in Molarity (mol/liter). I would dilute a solution to create new solutions, using the formula M1xV1=M2xV2 where M=molarity and V=volume. In this lab, there were four solutions, Solution A, Solution B, Solution C, and Solution D. The solute or substance that dissolves was sugar and the solvent or substance that the solute dissolves in was water. For Solution A, I weighed 3.42 g sugar and diluted to 100 mL to get a concentration of 0.10 M and the color of bright red. For Solution B, I weighed 0.342 g sugar and diluted to 100 mL to get a concentration of 0.010 M and the color of pink. For Solution C, I measured 10
7. In a procedure developed to determine the percent zinc in post 1982 pennies, 50 ml of an HCl solution was used to react (dissolve) all of the zinc in the penny. To ensure complete reaction, the solution contains twice as many moles of HCl that is actually needed. What concentration of HCl should be used?
In the third stage of this experiment, the density of a liquid was determined and compared to known standards. A 100ml beaker was filled to about half-full with room-temperature distilled water. The temperature of the water in ◦C was recorded in order to compare to known standards later. A 50ml beaker was then weighed on a scale in order to determine mass and recorded. A sample of the distilled water with an exact volume of 10ml was then placed in the 50ml beaker using a volumetric pipette. The 50ml beaker with the 10ml of water was then weighed again and the initial mass of the beaker was subtracted from this mass to obtain the mass of the 10ml of water. With the volume and the mass of the water now known, density was calculated using d = m/V and recorded in g/ml. This process was then repeated to check for precision and compared to standard values to check for accuracy. Standard values were obtained from CRC Handbook, 88th Ed.
If we have one Liter of a solution, how many milliliters (ml) is that? 1000 mL