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Empirical Formula Of Hydrate Lab

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The primary of this lab is about the hydrate. The hydrate is a compound formed by an ionic bond combined with the water molecule (known as “water of hydration”) attached to it. So for every formula unit, there would be some amount of water molecule combined with the ionic compound and would act as a single compound. Our theoretical hydrate for this lab was CuSO4 * 5H2O. To remove the water from the compound and get the mass of the ionic compound, you need to follow the dehydrating procedure by heating. That would separate the ionic bond (CuSO4) from the water molecule (5H2O) once it reaches certain decomposition temperature. And to physically determine whether or not the water of hydration is removed, see the color, in our case, turning white from blue. Once the water molecules have entirely evaporated, the mass left would be the weight of the ionic compound (mass of CuSO4 in grams). …show more content…

The empirical formula is a similar molecular formula but in its simplified ratio. While calculating, you need to find the percent of a part of the compound from the whole compound. Then find the moles of each composition and then calculate mole to mole ratio between copper(II) sulfate and water to achieve the possible empirical formula. But for the mole to mole ratio to work, you need to know the law of definite proportions. It says that every chemical compound would have certain proportion, by mass, of its composition and that ratio cannot be changed. So for example a mole of water would always have 1 mole of Oxygen and 2 moles of

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