0.750 g of Al(OH), according to the following reaction Al(OH).(s) + 3 HCI(aq) → AICI(aq) + 3 H0(aq) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 78.00 18.02 mol AICI, mol AICI, 0.750 133.33 mol Al(OH), 6.022 x 1023 0.0288 g HCI 3 0.117 g Al(OH), 1.05 9.60 x 10-3 mol H,0 0.351 mol HCI g AICI, 1 36.46 g AICI, 2.25 g H,0

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Chapter2: The First Law Of Thermodynamics
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Determine the mass in grams of HCI that can react with
0.750 g of Al(OH); according to the following reaction
Al(OH)3(s) +
3
HCI(aq) → AICI3(aq) +
H2O(aq)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
*( )
78.00
18.02
mol AICI,
mol AICI,
0.750
133.33
mol Al(OH)3
6.022 x 1023
0.0288
g HCI
3
0.117
g Al(OH),
1.05
9.60 x 10-3
mol H20
0.351
mol HCI
1
g AICI3
36.46
g AICI3
2.25
g H20
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Transcribed Image Text:9:08 Time's Up! Submit Determine the mass in grams of HCI that can react with 0.750 g of Al(OH); according to the following reaction Al(OH)3(s) + 3 HCI(aq) → AICI3(aq) + H2O(aq) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 78.00 18.02 mol AICI, mol AICI, 0.750 133.33 mol Al(OH)3 6.022 x 1023 0.0288 g HCI 3 0.117 g Al(OH), 1.05 9.60 x 10-3 mol H20 0.351 mol HCI 1 g AICI3 36.46 g AICI3 2.25 g H20 Tap here or pull up for additional resources -
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