1) You have an array named array1 with these elements: 6 4 10 3 What is the value of array1[4]? What is the value of array1.length? 9 2 7 8

Arrays Write three statements to print the first three elements of array runTimes. Follow each statement with a newline. Ex: If runTime = {800, 775, 790, 805, 808}, print:800 775 790 Note: These activities will test the code with different test values. This activity will perform two tests, both with a 5-element array (int runTimes[5]). See "How to Use zyBooks".Also note: If the submitted code tries to access an invalid array element, such as runTime[9] for a 5-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>using namespace std; int main() {const int NUM_ELEMENTS = 5;int runTimes[NUM_ELEMENTS];int i; for (i = 0; i < NUM_ELEMENTS; ++i) {cin >> runTimes[i];} /* Your solution goes here */ return 0;} Please help me with this problem using c++.

# Declare a named constant for array size here. MAX_AVERAGES = 8 # Declare array here. # Write a loop to get batting averages from user and assign to array. averageString = input("Enter a batting average: ") battingAverage = float(averageString) # Assign value to array. # Assign the first element in the array to be the minimum and the maximum. minAverage = averages[0] maxAverage = averages[0] # Start out your total with the value of the first element in the array. total = averages[0] # Write a loop here to access array values starting with averages[1] # Within the loop test for minimum and maximum batting averages. # Also accumulate a total of all batting averages. # Calculate the average of the 8 batting averages. # Print the batting averages stored in the averages array. # Print the maximum batting average, minimum batting average, and average batting average. This is on mindtap pyton what needs to be fix

4. Fill in the table below to trace the values of the arrays in main at various points. int array1 = (10,20,30,40,50)}; int] array2 = (5,4,3,2,1}; intij array3 = new int[5]; Ilprint the array values at this point dolt(array1, array2); /print the array values at this point array2 = array1; Ilprint the values at this point array3 = dolt(array1,array2); Ilprint the array values at this point } llend of main public static int] dolt(int] arri, int] arr2){ int] arr3 = new int[5]; for (int i=0; icarr1.length;1++) arr3[1] = arr1[i]+arr2[arr2.length-1-i); return arr3; Values of the arrays below in main before first invocation of dolt array1 array2 array3 Values of the arrays below in main after first invocation of dolt array1 array2 array3 Values of the arrays below in main before second invocation of dolt array1 array2 Values of the arrays below in main after second invocation of dolt array1 array2 array3

Programming language: Processing from Java Question attached as photo Topic: Use of Patial- Full Arrays

Problem Description - JAVA PROGRAMMING Use a Two-dimensional (3x3) array to solve the following problem: Write an application that inputs nine numbers, each of which is between 1 and 10, inclusive.  Display the array after the user inputs each value. Rotate/flip the array by changing places. Make the rows columns and vice versa. You have to move the elements to their new locations.   Remember to validate the input and display an error message if the user inputs invalid data.  Documentation and the screenshot(s) of the results.  Example:  1  2  3 4  5  6 7  8  9 the result will be :  1  4  7 2  5  8 3  6  9

Let numbers be an array defined as follows. int numbers[5][7]; Assume that the array has been filled with values. Which of the following blocks of code calculates the row totals of the 2-dim array and store them in the 1-dim array named totals? int totals[5] = {0}; for (int row = 0; row < 5; ++row) { int total = 0; for (int col = 0; col < 7; ++col) { total += numbers[row][col]; } totals[row] = total; } int totals[7] = {0}; for (int col = 0; col < 7; ++col) { int total = 0; for (int row = 0; row < 5; ++row) { total += numbers[row][col]; } totals[col] = total; } O None of these int totals[7] = {0}; for (int row = 0; row < 7; ++row) { int total = 0; for (int col = 0; col < 5; ++col) { total += numbers[row][col]; } totals[row] = total; }

part a- 2point) for 3 students find the average of a student by asking him how many grades do you have. The answer to this question, determine the size of the array(list of grades) and then ask the user to enter grades(the number of the grades is equal to the size of the array) then calculate the average for each student. Hence, you will calculate 3 averages. to calculate the average, use the array accumulator. Also when you get each grade validate it. validation for grade means that you check whether a grade is between 0 and 100. if the grade is negative or a grade is more than 100 then it is not valid and you have to ask the user to enter a grade again. Part b- 1 point) Find the maximum and minimum grades for each student. Part c- 1 point) Print the sorted list of the grades for each student. example: if grades user entered are: 60 78 98 23 45 then sorted list is:23 45 60 78 98 (Array not vector)

Please Help me I will give thumbs up Follow the task in the skeleton code. public class DoublyLinkedList{   // define ListNode elements specific for this type of list, indicating current, previous and next   // consider head as name for previous node, and tail for the next one.private ListNode head;private ListNode current;private ListNode tail;    // default constructor   public DoublyLinkedList(){       //*** Task #1: implement a default constructor here, initializing the nodes to null }    // method that calculates the length of the listpublic int length(){       //*** Task #2: implement the method navigating through the list until you run out of elements } public void addANodeToStart(E addData){       //*** Task #3: implement this method, taking into consideration that the head will be replaced by a new node. You may want to use a temporary variable }    // accessor method that gets data at current nodepublic E getDataAtCurrent(){       //*** Task #4: implement this method making…