1. Find the flow distribution in the three-parallel pipe system shown in figure below. Take Qix = 2500 L/min. Element L, m D, mm το ΣΚ en 1 50 75 0.02 2 2 80 85 0.03 4 120 100 0.025 2 Ans: Q₁ = 731 L/min, Q₂ = 790 L/min, Q₂ = 979 L/min 3 *
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- a piping system (C = 120) consists of 3050 m of 750-mm (AB), 2440 m of 600-mm (BC) and, from C to D, two 400-mm pipes in parallel, each 1830 m long, (a) For a flow of 0.394 m3/s from A to D, what is the lost head? (b) If a valve in one of the 400-mm pipes were closed, what change in lost head wouldoccur for the same flowThe system consists of 1200 m of 5 cm cast iron pipe, two 45° and four 90° flanged long-radius elbows, a fully open flanged globe valve, and a sharp exit into a reservoir. If the elevation at point 1 is 400 m, what gage pressure is required at point 1 to deliver 0.005 m3/s of water into the reservoir? Use the following: v = 1 x 10-6 m2/s Kentrance = 0.5 Kexit = 1 Kvalve = 6.9 f = 0.0316 γ = 9810 N/m3 Choices: 3.44 Mpa 1.02 MPa 3.48 Mpa 1.00 MPa None of the choicesQ5: What is the diameter of smalle pipe, if the flow rate (30 lit/sec) ? ·S=0.6 D= Ans: 146.8 mm² 40cm D = 200mm D=?
- The figure shown below is a series pipeline system used to draw a fluid from a lower source open tank to a higher destination open tank . The flow and geometric layout for the system are listed below: Fluid: water Volume flow rate: Q=0.015 m3/s Elevation difference: h=8.0m of two free surfaces Suction line: DN100 Sch. 40 Steel pipe Length: Ls=2.0 m Valve1: hinged disc type foot valve Entrance type: well-rounded Discharge line: DN80 Sch. 40 Steel pipe Length: Ld=100 m Valve2: full open gate valve Elbows: 90ο long radius elbow (2) Select all energy loss types between section 1 and 2_________ A. Minor loss for the two elbows B. Friction loss in suction line C. Minor loss for Valve 1 D. Entrance loss E. Exit loss F. Friction loss…The figure shown below is a series pipeline system used to draw a fluid from a lower source open tank to a higher destination open tank . The flow and geometric layout for the system are listed below: Fluid: water Volume flow rate: Q=0.015 m3/s Elevation difference: h=8.0m of two free surfaces Suction line: DN100 Sch. 40 Steel pipe Length: Ls=2.0 m Valve1: hinged disc type foot valve Entrance type: well-rounded Discharge line: DN80 Sch. 40 Steel pipe Length: Ld=100 m Valve2: full open gate valve Elbows: 90ο long radius elbow (1) Select the simplified general energy equations for section 1 and 2_________ A. B. C. D.A 60-cm water pipe carries a flow of 0.1 m³/s. At point A the elevation is 50 meters and the pressure is 200 kPa. At point B, 1200 meters downstream from A, the elevation is 40 meters and the pressure is 230 kPa. The head loss , in feet, between A and B isA. 6.94B. 15.0C. 20.88D. 100.2
- For the series-parallel system shown in figure, all pipes are 8cm_diameter cast iron. If the total flow rate is 0.026 m3/s find; a-) The flow rate for each pipe b-) Pressure lost between point (A) and (B) note: Take f=0.02 and neglect minor losses.1.Compute the lost pressure for a diverging fitting. The flow rate in the 20 cm upstream section is 0.24 m3/s, and the flow rate in the 20 cm branch is 0.24 m3/s. The downstream section has a diameter of 25 cm. Assume a 45° wye.On a circular conduit there are different diameters: diameter D1 = 2 m, changes into D2 = 3 m. The velocity in the entrance profile was measured: v1 = 3 m/s. Calculate the discharge and mean velocity at the outlet profile (see figure below). Determine also type of flow in both conduit profiles (whether the flow is laminar or turbulent) – temperature of water T = 12° C. (use Reynold’s number Re), For laminar flow: Re<2320, For turbulent flow Re>2320, Kinematic viscosity of water of 12°C, v is equal to 1,24 10^-6 m2/s.
- In a pipe of diameter 300mm the center line velocity and the velocity at a point 100mm from the center, as measured by pitot tube are 2.4 m/s and 2.0 m/s respectively. Assume the flow in the pipe to be turbulent find: 1-Dischrge through the pipe,2-Coefficient of friction, 3 Height of roughness projections.Please do not waste my question solve with correct answers only.Oil (Specific gravity = 9, ν =1.0*10-5 m2/s) is transported through a plastic pipe of 500 m in length and 8 cm of diameter with a major head loss of 80 m. Calculate the volume flow rate in the pipe in L/s using the Swamee equation. g = 9.8 m/s2. Round your answer to one decimal place.UsingFig. P6.27. All parameters are constant except the uppertank depth Z(t). Find an expression for the flow rate Q(t) asa function of Z(t). Set up a differential equation, and solvefor the time t0 to drain the upper tank completely. Assumequasi-steady laminar flow.