1. Suppose x is a normally distributed random variable withthe random variable, call it x0, such thata) P(x x0)8413b) P(x > x0) = 025c) P(x > x0) = .95d) P(41 Sx < x0) 8630e) 10% of the values of x are less than x0.f) 1% of the values of x are greater than x50 and ơ-3. Find the value of0

Question
Asked Mar 12, 2019

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1. Suppose x is a normally distributed random variable with
the random variable, call it x0, such that
a) P(x x0)8413
b) P(x > x0) = 025
c) P(x > x0) = .95
d) P(41 Sx < x0) 8630
e) 10% of the values of x are less than x0.
f) 1% of the values of x are greater than x
50 and ơ-3. Find the value of
0
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1. Suppose x is a normally distributed random variable with the random variable, call it x0, such that a) P(x x0)8413 b) P(x > x0) = 025 c) P(x > x0) = .95 d) P(41 Sx < x0) 8630 e) 10% of the values of x are less than x0. f) 1% of the values of x are greater than x 50 and ơ-3. Find the value of 0

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Expert Answer

Step 1

Standard normal distribution:

The standard normal distribution is a special case of normal distribution. The standard normal distribution will have mean 0 and standard deviation 1. If a random variable y follows normal distribution with mean (m) and standard deviation (s), then the standard normal variable z will be as given below:

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Step 2

d.

Find the value of x0 for which P(41 ≤ x x0) = 0.8630:

The random variable x follows normal distribution with mean 50 and standard deviation 3.

That is, m = 50 and s = 3.

The value of x0 for which P(41 ≤ x x0) = 0.8630 is obtained as 53.3 from the calculation given below:

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Step 3

e.

Find the value of x0 where 10% of the value x are less than x0:

The value of x0 where 10% of the value x are less than x0 is obtained as 46.16 ...

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