1. The hemoglobin in blood establishes an equilibrium with oxygen gas very quickly. The equilibrium can be represented as heme + O2 heme-O2 where "heme" stands for hemoglobin and "heme-O;" stands for the hemoglobin-oxygen complex. The value for the equilibrium constant for this reaction is about 9.2 x 105. Carbon monoxide also binds with hemoglobin by the following reaction: heme + co = heme-co This reaction has an equilibrium constant of 2.3 x 103. Which reaction's equilibrium lies farther toward products? Does your answer justify the toxicity of CO?
1. The hemoglobin in blood establishes an equilibrium with oxygen gas very quickly. The equilibrium can be represented as heme + O2 heme-O2 where "heme" stands for hemoglobin and "heme-O;" stands for the hemoglobin-oxygen complex. The value for the equilibrium constant for this reaction is about 9.2 x 105. Carbon monoxide also binds with hemoglobin by the following reaction: heme + co = heme-co This reaction has an equilibrium constant of 2.3 x 103. Which reaction's equilibrium lies farther toward products? Does your answer justify the toxicity of CO?
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 61QRT
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