1.) Using unsigned 16-bit numbers, convert the following statement in C++ to Assembly language. (Example of an assembly language that is useful: movf i,w subwf j,w movf i+1, w subwfb j+1,w bc end_if movf j,w addwf i,w movwf m movf j+1,w addwfc i+1,w movwf m+1 end_if)   C++ code: unsigned char i, j, k;   if (i && j) {                         k = j + i;                         } // … rest of code …

2) Write the following code segment in MARIE's assembly language. If X >= Y then X = X * 2 else Y = X - Y + Z;

Consider the following C-statement(s). Assume that the variables f, g, h, i, and jare assigned into the registers $s0, $s1, $s2, $s3, and $s4 respectively. Convert into MIPS code. Then convert to Machine Code. f = (i+h) * (j-g)

Example: The Problem Input File Using C programming language write a program that simulates a variant of the Tiny Machine Architecture. In this implementation memory (RAM) is split into Instruction Memory (IM) and Data Memory (DM). Your code must implement the basic instruction set architecture (ISA) of the Tiny Machine Architecture: //IN 5 //OUT 7 //STORE O //IN 5 //OUT 7 //STORE 1 //LOAD O //SUB 1 55 67 30 55 67 1 LOAD 2- ADD 3> STORE 4> SUB 5> IN 6> OUT 7> END 8> JMP 9> SKIPZ 31 10 41 30 //STORE O 67 //OUT 7 11 /LOAD 1 //OUT 7 //END 67 70 Output Specifications Each piece of the architecture must be accurately represented in your code (Instruction Register, Program Counter, Memory Address Registers, Instruction Memory, Data Memory, Memory Data Registers, and Accumulator). Data Memory will be represented by an integer array. Your Program Counter will begin pointing to the first instruction of the program. Your simulator should provide output according to the input file. Along with…

1. Translate the following algorithm to this simple computer's assembly language and then to machine language. (use the columns in a table as shown below) Label Operation Operand Address Machine Code Comments read a read b set c = 0 if a == b set c = a - 7 + (2 * b - 3) else if a == 3 set c = a b + 2 write c

Convert this following C++ code below to easy68k assembly language: int sum = 0; int c =1; for (unsigned short i = 0; i <= 10; i++) { if (c == 1 ) { sum += i; c = 0; } else { c = 1; } }

Implement the following expression in assembly language: result = (val3 + val4) (vall - val2) (30*4)/55 Assume that result, vall, val2, val3 and val4 are 16-bit integer variables You need to implement the expression the way it is provided, you cannot do any reduction on the expression while implementing it. - Initialize vall with 134 (hexadecimal), va12 with 139 (hexadecimal), val3 with 67 (hexadecimal) and val4 with 47 (hexadecimal) -