10.57 The metabolic oxidation of glucose, C6H1206, in our bodies produces CO2, which is expelled from our lungs as a gas: COH12O6(aq) + 6 O2(g) 6 CO2(g) + 6 H20(1) (a) Calculate the volume of dry CO2 produced at body temperature (37 °C) and 0.970 atm when 24.5 g of glucose is consumed in this reaction. (b) Calculate the volume of Oxygen you would need, at 1.00 atm and 298 K, to completely oxidize 50.0 g of glucose.

Chemistry for Engineering Students
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Author:Lawrence S. Brown, Tom Holme
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Chapter5: Gases
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10.57 The metabolic oxidation of glucose, C6H1206, in our bodies
produces CO2, which is expelled from our lungs as a gas:
COH12O6(aq) + 6 O2(g) 6 CO2(g) + 6 H20(1)
(a) Calculate the volume of dry CO2 produced at body
temperature (37 °C) and 0.970 atm when 24.5 g of glucose
is consumed in this reaction. (b) Calculate the volume of
Oxygen you would need, at 1.00 atm and 298 K, to completely
oxidize 50.0 g of glucose.
Transcribed Image Text:10.57 The metabolic oxidation of glucose, C6H1206, in our bodies produces CO2, which is expelled from our lungs as a gas: COH12O6(aq) + 6 O2(g) 6 CO2(g) + 6 H20(1) (a) Calculate the volume of dry CO2 produced at body temperature (37 °C) and 0.970 atm when 24.5 g of glucose is consumed in this reaction. (b) Calculate the volume of Oxygen you would need, at 1.00 atm and 298 K, to completely oxidize 50.0 g of glucose.
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