1. The equation for the metabolic breakdown of glucose (C6H1206) is the same as the equation for the combustion of glucose in air: C6H1206(s) + 6O2(g) → 6CO2(g) + 6H20(I) Calculate the volume of CO2 produced at 45 °C and 3.40 atm when 6.50 g of glucose is used up in the reaction.

World of Chemistry, 3rd edition
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Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter7: Chemical Reactions: An Introduction
Section: Chapter Questions
Problem 50A
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We will now extend our knowledge with its essentials with the prepared activities that expound everything we
have learned in the previous lessons.
ACTIVITY 4
HOW MUCH AM I FOR THE SECOND TIME?
Stoichiometry deals with the amounts of reactants and products in a chemical reaction. It involves conversion
of amounts of either reactant or product using mole method. In this activity, we will apply the concept of stoichiometry
to look for the amounts of reactants and products in a chemical reaction using gas laws.
Let us answer the given problems below.
DIRECTION: Read, understand, and solve the following problems in gas stoichiometry. SHOW YOUR SOLUTION
1. The equation for the metabolic breakdown of glucose (C6H1206) is the same as the equation for the
combustion of glucose in air:
C6H1206(s) + 602(g) → 6CO2(g) + 6H20(1)
Calculate the volume of CO, produced at 45 °C and 3.40 atm when 6.50 g of glucose is used up in the
reaction.
Transcribed Image Text:We will now extend our knowledge with its essentials with the prepared activities that expound everything we have learned in the previous lessons. ACTIVITY 4 HOW MUCH AM I FOR THE SECOND TIME? Stoichiometry deals with the amounts of reactants and products in a chemical reaction. It involves conversion of amounts of either reactant or product using mole method. In this activity, we will apply the concept of stoichiometry to look for the amounts of reactants and products in a chemical reaction using gas laws. Let us answer the given problems below. DIRECTION: Read, understand, and solve the following problems in gas stoichiometry. SHOW YOUR SOLUTION 1. The equation for the metabolic breakdown of glucose (C6H1206) is the same as the equation for the combustion of glucose in air: C6H1206(s) + 602(g) → 6CO2(g) + 6H20(1) Calculate the volume of CO, produced at 45 °C and 3.40 atm when 6.50 g of glucose is used up in the reaction.
2. Consider the formation of nitrogen dioxide from nitric oxide and oxygen:
2NO(g) +O2(g) → 2NO2(g)
If 10.0 L of NO are reacted with excess of O2 at STP, what is the volume in liters of NO2 produced?
3. In alcohol fermentation, yeast converts glucose to ethanol and carbon dioxide:
C6H12O6(s) → 2C2H5OH(I) +2CO2(g)
If 6.87 g of glucose are reacted with and 1.55 L of CO2 gas are collected at 293 K and 0.975 atm, what is the
percent yield of the reaction?
Transcribed Image Text:2. Consider the formation of nitrogen dioxide from nitric oxide and oxygen: 2NO(g) +O2(g) → 2NO2(g) If 10.0 L of NO are reacted with excess of O2 at STP, what is the volume in liters of NO2 produced? 3. In alcohol fermentation, yeast converts glucose to ethanol and carbon dioxide: C6H12O6(s) → 2C2H5OH(I) +2CO2(g) If 6.87 g of glucose are reacted with and 1.55 L of CO2 gas are collected at 293 K and 0.975 atm, what is the percent yield of the reaction?
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