Question
Asked Nov 22, 2019
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16. Using the information below, determine the enthalpy change (in kJ) for the reaction of 50.0 g of oxy
gas (MW 32.0) with excess diborane gas (B2H6; MW 27.6).
B2H6(g) + 302(g)
B2O3(s) + 3H20() AH--2147.5 kJ
a. -3360 kJ
b. -2150 kJ
c. -1300 kJ
d. -1120 kJ
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16. Using the information below, determine the enthalpy change (in kJ) for the reaction of 50.0 g of oxy gas (MW 32.0) with excess diborane gas (B2H6; MW 27.6). B2H6(g) + 302(g) B2O3(s) + 3H20() AH--2147.5 kJ a. -3360 kJ b. -2150 kJ c. -1300 kJ d. -1120 kJ

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Expert Answer

Step 1

Given,

Mass of oxygen gas = 50.0 g

Molecular weight of O2 gas = 32.0 g/mol

Moles of O2 can be calculated as:

50 g
Mass
1.5625 mol
Moles
32 g/mol
Molar masS
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50 g Mass 1.5625 mol Moles 32 g/mol Molar masS

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Step 2

Given, B2H6 (g) + 3 O2 (g) → B2O3 (s) + H2O (l)    △Ho = -2147.5 kJ

...

3 mol O2 releases
-2147.5 kJ
-2147.5 kJ
x 1.5625 mol O2
. 1.5625 mol O2 releases
3 mol O2
= -1118.5 kJ ~ -1120 kJ
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3 mol O2 releases -2147.5 kJ -2147.5 kJ x 1.5625 mol O2 . 1.5625 mol O2 releases 3 mol O2 = -1118.5 kJ ~ -1120 kJ

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