2. A M= 4942 kg rock Determine the ratio R=KE/DE of the kinetic energy K.E is released from rest at height H=50M. = MV ²/2 and gravitational energy PE =4 = mgh at height my h = 36M: al 0,861 6) 0.763 c) 0.60860 0.389 e)None

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Chapter39: Relativity
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2. A M= 4942 kg rock
Determine the ratio R=KE/DE of the kinetic energy K.E
is released from rest at height H=50M.
= MV ²/2 and gravitational energy PE =4 = mgh at height
h = 36M:
al 0,861
6) 0.763
C) 0.686
0.389 e)None
зда
Transcribed Image Text:2. A M= 4942 kg rock Determine the ratio R=KE/DE of the kinetic energy K.E is released from rest at height H=50M. = MV ²/2 and gravitational energy PE =4 = mgh at height h = 36M: al 0,861 6) 0.763 C) 0.686 0.389 e)None зда
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