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PhysicsCollege Physics1st Edition

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Chapter 33, Problem 7PE
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College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000

Solutions

Chapter
Section
Problem 1CQ
Problem 2CQ
Problem 3CQ
Problem 4CQ
Problem 5CQ
Problem 6CQ
Problem 7CQ
Problem 8CQ
Problem 9CQ
Problem 10CQ
Problem 11CQ
Problem 12CQ
Problem 13CQ
Problem 14CQ
Problem 15CQ
Problem 16CQ
Problem 17CQ
Problem 18CQ
Problem 19CQ
Problem 20CQ
Problem 21CQ
Problem 22CQ
Problem 23CQ
Problem 24CQ
Problem 25CQ
Problem 26CQ
Problem 27CQ
Problem 28CQ
Problem 29CQ
Problem 30CQ
Problem 31CQ
Problem 32CQ
Problem 1PE
Problem 2PE
Problem 3PE
Problem 4PE
Problem 5PE
Problem 6PE
Problem 7PE
Problem 8PE
Problem 9PE
Problem 10PE
Problem 11PE
Problem 12PE
Problem 13PE
Problem 14PE
Problem 15PE
Problem 16PE
Problem 17PE
Problem 18PE
Problem 19PE
Problem 20PE
Problem 21PE
Problem 22PE
Problem 23PE
Problem 24PE
Problem 25PE
Problem 26PE
Problem 27PE
Problem 28PE
Problem 29PE
Problem 30PE
Problem 31PE
Problem 32PE
Problem 33PE
Problem 34PE
Problem 35PE
Problem 36PE
Problem 37PE
Problem 38PE
Problem 39PE
Problem 40PE
Problem 41PE
Problem 42PE
Problem 43PE
Problem 44PE
Problem 45PE
Problem 46PE
Problem 47PE
Problem 48PE
Problem 49PE
Problem 50PE
Problem 51PE
Problem 52PE
BuyFindarrow_forward

College Physics

1st Edition
Paul Peter Urone + 1 other
ISBN: 9781938168000
Textbook Problem

Suppose a W− created in a bubble chamber lives for What distance does it move in this time if it is traveling at 0.900 c? Since this distance is too short to make a track, the presence of the W− must be inferred from its decay products. Note that the time is longer than the given W− lifetime, which can be due to the statistical nature of decay or time dilation.

To determine

The distance travelled by W− particle created in a bubble chamber.

Explanation

Given info:

W− particle created in a bubble chamber lives for 5×10−25 s and it is travelling at a speed of 0.900c.

Formula used:

If v is the speed and t be the time taken by a particle, then distance travelled by the particle, =vt

Calculation:

t=5×10−25 s and v=0.900c=0.900×3×108=2

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Ch-33 P-1CQCh-33 P-2CQCh-33 P-3CQCh-33 P-4CQCh-33 P-5CQCh-33 P-6CQCh-33 P-7CQCh-33 P-8CQCh-33 P-9CQCh-33 P-10CQ
Ch-33 P-11CQCh-33 P-12CQCh-33 P-13CQCh-33 P-14CQCh-33 P-15CQCh-33 P-16CQCh-33 P-17CQCh-33 P-18CQCh-33 P-19CQCh-33 P-20CQCh-33 P-21CQCh-33 P-22CQCh-33 P-23CQCh-33 P-24CQCh-33 P-25CQCh-33 P-26CQCh-33 P-27CQCh-33 P-28CQCh-33 P-29CQCh-33 P-30CQCh-33 P-31CQCh-33 P-32CQCh-33 P-1PECh-33 P-2PECh-33 P-3PECh-33 P-4PECh-33 P-5PECh-33 P-6PECh-33 P-7PECh-33 P-8PECh-33 P-9PECh-33 P-10PECh-33 P-11PECh-33 P-12PECh-33 P-13PECh-33 P-14PECh-33 P-15PECh-33 P-16PECh-33 P-17PECh-33 P-18PECh-33 P-19PECh-33 P-20PECh-33 P-21PECh-33 P-22PECh-33 P-23PECh-33 P-24PECh-33 P-25PECh-33 P-26PECh-33 P-27PECh-33 P-28PECh-33 P-29PECh-33 P-30PECh-33 P-31PECh-33 P-32PECh-33 P-33PECh-33 P-34PECh-33 P-35PECh-33 P-36PECh-33 P-37PECh-33 P-38PECh-33 P-39PECh-33 P-40PECh-33 P-41PECh-33 P-42PECh-33 P-43PECh-33 P-44PECh-33 P-45PECh-33 P-46PECh-33 P-47PECh-33 P-48PECh-33 P-49PECh-33 P-50PECh-33 P-51PECh-33 P-52PE

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